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Use Cramer rule find yhe solution of X2 : X1+3x2+X3=1 2x1+X2+X3=5 -2x1+2x2-X3=-8...

Question

Use Cramer rule find yhe solution of X2 : X1+3x2+X3=1 2x1+X2+X3=5 -2x1+2x2-X3=-8

Use Cramer rule find yhe solution of X2 : X1+3x2+X3=1 2x1+X2+X3=5 -2x1+2x2-X3=-8



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Use Newton’s Method to obtain a general rule for approximating the indicated radical. $\sqrt{a}\left[\text {Hint}: \text { Consider } f(x)=x^{2}-a .\right]$

It is a question Number 59 you're We can write the system X is it will be right for the given system off immigration. So the metrics to buy dramatics is a metric said and directories be right. So first of all, find the determinant automatics A. So here go market nearby Dewey's for. And three more great by oneness three, which is equal to one. Right. So over determinant or mentally stay. Music would do Seguin, right? No, re bless the first goal with director beat. Right. So you're director. Be east to four. The second column of metrics say that these negative three and two right. So here, too much lately to Reese for and four months in my my negative. Really? That is well, so well plus for 2016. So we can right here. Do you want visit in 16? Right now? First column off meth Pixies Entities then right, Director, be over here. That is to four. So you're for money. Grabbing two is eight and two months by by one is too, which is equal to six. Right? So we can right here. The two is equal to six, right? No solution is doing like your expert is 1/4 Deegan body. And your ex too. He's equated Need to waiting right there. D one is 16. You're determinant. These seven you're extrude is equality to buy these over me. 236 and a basic photo. Say what you like. So these are all of solution. Don't think you

I want to solve the equation to expert minus X equals one. Since the quadratic, I'm gonna Set the equation equal to zero. Is attracting one to both sides. Now there are multiple ways that you can solve this. I'm going to choose to do factory because this is a try now. What multiplies the negative two And as two negative one, That would be negative too and positive one. And now we have four terms. So we can group from the first group. We can back out of two X. Left with the X minus one. The second group we can take out of one and left with the X minus one. Which means our factors are x minus one in two, X plus one of the zero product property. That means x minus one equals zero and two X plus one equals zero. So X equals one and two X equals negative one. So X equals negative one half.

I want to solve the quadratic X squared minus two, X equals one. Since we have the constant on the right hand side, one way we could do this could be the completing the square method. So we can rewrite x squared minus two X. And then complete the square half of negative two is negative one squared plus one. So I have to add one to the right hand side as well to get to. That allows us to write the left hand side of the equation is a perfect square, binomial X minus one squared equals two. Now we can square root both sides, that's positive or negative square root of two, So X -1 equals the positive or negative square to to therefore X is equal to when you add one to both sides, one plus or minus the square to Mhm.

X squared minus two X equals two questions laid out like this and that that be value right? There is even I'm going to use completing the square. So half of negative two is negative. One negative. One square is one at one double sides Factor that left side into the square of binomial. Take the square root of all sides and then add wonderful sides. Oops! Forgot a major thing. They're square to three so one plus or minus the square to three. So completing the square the way to go on that one.


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