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Far &Conedder Ine lollo vino tcacIion2CHa(g) CHa(g) 3Ha(g) concantemon CH] 0.0S6M equilibrimm ConcantnamonUne (eaconCH ' Camed G Ecmeremderamune Kn0 011 M,...

Question

Far &Conedder Ine lollo vino tcacIion2CHa(g) CHa(g) 3Ha(g) concantemon CH] 0.0S6M equilibrimm ConcantnamonUne (eaconCH ' Camed G Ecmeremderamune Kn0 011 M,Find Ine aquilibrivm constaniaiinis lemperaluje2IPiate Your enerar uino (ro aionmcanttloura?AzdSubmilPpueu anatm Recare m [Inconoct; Tly Agah; ettampts retnainlngrovlde FeedbackNen >

Far & Conedder Ine lollo vino tcacIion 2CHa(g) CHa(g) 3Ha(g) concantemon CH] 0.0S6M equilibrimm Concantnamon Une (eacon CH ' Camed G Ecmeremderamune Kn 0 011 M, Find Ine aquilibrivm constaniaiinis lemperaluje 2IPiate Your enerar uino (ro aionmcanttloura? Azd Submil Ppueu anatm Recare m [ Inconoct; Tly Agah; ettampts retnainlng rovlde Feedback Nen >



Answers

Given $F_{R} \cdot r_{R}=F_{E} \cdot r_{E}$, find each missing quantity. $$ \begin{array}{cccc} F_{R} & F_{E} & r_{R} & r_{E} \\ 37 \overline{0} \mathrm{~N} & 12 \overline{0} \mathrm{~N}
& \_ \mathrm{~m} & 1.12 \mathrm{~m} \end{array} $$

As we know that, as we know that under root burk is equal to and is equal to reflective index is equal to reflective index, which is demands. And lace. Richard diamonds and diamonds and Elise went pretty so diamonds and so diamonds and will be equal to am not L not he not option D is the correct answer for this problem. I hope you understand the solution.

This question asked us to take a look at comparing some salts and the Civic Cat ions that can come from the salts in general. Wasn't really clear entirely what this question was asking for, but I believe we're being um as to determine which is the more acidic solution based on the salts and their concentrations here. So that means the lower ph solution that's going to be more acidic and it's gonna have a higher K. A value associated with it. And so we take a look at this. Um In the first set of examples we have nickel two plus chloride um at the same concentration of sodium chloride, sodium chloride with the sodium cat iron we should know is a neutral cat eye on. So it's not going to contribute any acidic properties at all to the solution. But Nicol two plus can I on has a K. A. Value associated with It's pretty small but nonetheless um will furnish some acidic properties to the solution. And so as a result here, The more acidic solution is going to come from the Nickel two plus here. And that would have um the lower ph overall for the solution as well. In the second set of examples, we have a tin two plus solution be compared to the same concentration of a cobalt two plus solutions. Were comparing tin and cobalt here. So the K value for 10 2 plus is four times channel the negative four for cobalt two plus, it's much lower, It's two times 10 on the negative 10. It's the higher K. A value that's going to give me a more acidic solution or a lower ph. So therefore the Tin two plus with the higher K value will furnish the more acidic solution. In this set of examples.

Solving part of this problem here linda is greater than adults if speed smaller than Katie by under due to buy the square L. Now we can also write the value of Katie by route to buy the square For 02 of all, each .7 p. eight. Not solving part B. So the corresponding and is often by dividing by Katie and and is equal to one pointed for multiplication tend to depart 20. But me, thank you. Going forward. I can write the corresponding mean. Distance acts is equal to L by end to the power one x 3, which required to 10 to departments to buy .184 to the power one by three multiplication tend to the power fight which is equal to .18. Um um I just changed the unit in the last step.

Solution. We are given that a body of mass M is moving upward, inclination plane. And it comes to rate at a certain height. We need to find the distance traveled by this body on the inclined plane and the work done by the friction force. So first of all we need to represent all the force acting on this body of mars M MG downward normal force upward and the friction force in the opposite direction of the motion. The body is moving up so the friction force will act in the opposite direction of the motion. Take the component of the gravitational force. Mg. We have mg caution cosell for in this direction and MG sine alpha in the direction of friction force. We can easily calculate that an equal to MG go sell fa normal forces balanced by MG coast alpha and in the inclined direction in the inclined direction. Body is moving up so total force and F will be equal to MG sign alpha plus F. We can write F S. M. A. That means MG sine alpha plus put the value of F. We know the value of help. We can write Fsk and cayenne and and can be written as MG goes alpha and can be written as enjoy yourself. From here we can get the value of the solution. That is G sign alfa plus key goes alpha. Thanks plus G. Cause alpha from the equation. From the 3rd equation From the 30 question of Newton, what are the question states that we square equal to We zero sq to a S. Here we have taken minus saying because this is the deceleration we have given By solving this week equal to zero. So as equal to the zero sq Divide. We zero sq do eight to A. Where is the X solution? V zero Square. Put the value of acceleration two. That is sign alpha plus K. Oh self to and to G. This is the value of distance traveled by this body of Masum before coming into the rest. Now we need to find work done some mm by friction force. Yeah by friction force. Let it is A. F. Then it will be equal to friction force, friction force into distance. That is as since both are in opposite direction. So we put a minus sign over here. Value of friction force is equal to speaks MG. Go sell fa and put the value of S. That is equal to V zero square divide to G. Sign alpha plus. Gay goes alpha. From here we can write the work done by the friction force is equal to minus mm. Key. V zero square divide two. 10 alpha plus. Okay


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