5

An oscillating LC circuit consisting ofa 6.0 nF capacitor and a 2.0 mH coil has a maximum voltage of 4.0 V What is the maximum energy stored in the magnetic field o...

Question

An oscillating LC circuit consisting ofa 6.0 nF capacitor and a 2.0 mH coil has a maximum voltage of 4.0 V What is the maximum energy stored in the magnetic field of the coil?0 32 pJ16 pJ48 pJ32 nJ8 pJNone of them8 nJ16 nJ48 nJ

An oscillating LC circuit consisting ofa 6.0 nF capacitor and a 2.0 mH coil has a maximum voltage of 4.0 V What is the maximum energy stored in the magnetic field of the coil? 0 32 pJ 16 pJ 48 pJ 32 nJ 8 pJ None of them 8 nJ 16 nJ 48 nJ



Answers

An oscillating $L C$ circuit consisting of a 1.0 $\mathrm{nF}$ capacitor and a 3.0 $\mathrm{mH}$ coil has a maximum voltage of 3.0 $\mathrm{V}$ . What are (a) the
maximum charge on the capacitor, (b) the maximum current
through the circuit, and (c) the maximum energy stored in the
magnetic field of the coil?

31.82. We have an in doctor in an L C circuit. Um, we're told it's induct Ince's one and 1/2 Miller Henry's and also that the maximum energy it stores in its magnetic field is 10 micro jewels. So we want to find the maximum current or an inductive er. The energy stored is 1/2 l. I squared, and so the maximum energy is stored with the maximum current. So the maximum parent going to be the spare root of to you, Max provided by the inductive sense, which gives us 0.11 five.

Well, we are given an L C circuit in this circuit. CA best ins C is equal to 20. Microfilm rod and Time T is equal. Do five points. It'll millisecond and be current is equal to 25 1,000,000 pair. Now let us find out the reason Infrequency off, Given Elsie Circuit, Reason and frequency, Omega not is equal to two by times. If not, let's substitute, if not by one divided by t Do Pai into one divided by t. No, let's plugging T. Then we have to buy into one divided by 25. Multiply by 10 to the dollar minus Uh, sorry, it's not 25 five millisecond. So five. Multiply by 10 to the power minus three seconds and solving this weekend 400. Hi. Ready? And for a second No, let's go party. Okay, well, using omega not is equal to one divided by route. I'll see. And this imply state l Times c is equal. Do one divided by omega, not square. And from here, let's find out l well, inductions l is equal to one divided by. We'll make a not square times. The camp Aston's so one divided by omega not with Omega Noughties 400 I hold square multiply by capacitance Welcome. Baskins is, uh, X multiply by Welcome Boston sees 20 microfiber Rod So we have 20 Multiply by 10 to the power minus six Kiran and solving this we get l is equal to 31 point seven. Milly. Henry. Well, the expressions for the electric and magnetic energy is for TLC. Socket in the text imply that one divided by, ah, see times Weepy square is equal to one divided by l a times I p Square. And from here we p is equal to i p into square root of l divided by See right. No, let's substitute values. So we p is equal to 25. Multiply by 10 to the power minus three Multiply by square root oh, 31 point seven Multiply by 10 to the power minus three divided by 20 Multiply by 10 to the power minus six And there's more We p is equal to, um zero point Zito point 99 Life, Walt. Right? And this is equal to 995. Milly, Walt

We are given that this RLC circuit has a resistance of 50 Holmes, a capacitance of 200 times 10 to the negative sixth power. That's Micro Farage's, um, and induct INTs of 0.1 to 0 Henry and the resistance of the coil Our sub l I'm not sure like that. But anyway, resistance of the coil is 20. Um, the RMS voltage is 240. The frequency is 60 hertz. Well, that means that the angular frequency is two pi times 60. So that would be 120. Hi radiance per second. So initially, we need to calculate the RMS voltage across the resistor. Um, the equivalent resistance across both resistors is 70 owes 50 plus 20. So to solve a first, I'm going to write down that Z is the square root off R E Q squared plus x sub l minus X subsea. But XML is omega. L ex subsea is one over Omega Psi squared. Um, I, rms is v are a mess over z, and then that will give me the r. M s current. So let me put this in the calculator. Um, the square root of the equivalent resistance squared which is 70 plus omega l 120. Hi. I want one too minus one over Omega Psi 120. Hi. 200 guns. 10 to the negative. Six power. Don't forget to square it. That gives me 70 seven OEMs. So I take my voltage divided by that 240 divided by the 77 me 3.1 amps. Let's get back to the question. The RMS voltage across the resist er it's Ah, voltage across the resist er is going to be the current times the resistance, which is 50 owes. So I'll take the current times 50. And that gives me 156 22 significant digits. That's 160 vaults be across the capacitor. Um v ik was I back? See, I, um, one over Omega Psi. So So I are a mess is the 3.1 and I multiply that by one over Omega Psi. That gives me 41 volts. See, now the induct er has some resistance built into it, so I need to calculate the impedance. Um, that's going to be our sub l squared. Plus, um, Omega l squared. So let me get that square roots of our sub L. R Sabella's 20 plus omega l Omega l is 120 pi times 1200.12 squared. That gives me 49 homes for just thean Doctor. So v across the induct er is I times Ah zi sub l So take that times I What was I 3.1? And that gives me 150 154 rounded to two significant digits, um, votes.

On the topic of oscillations in L C circuit were given a capacitor off a given rating as well as being told that it is charged to a certain voltage before being discharged through an in dr we are asked to determine the maximum energy stored, the magnetic field off the doctor, the maximum value off the current as well as the frequency of oscillations in the circuit. So initially apart A. We want to find the energy that is stored in the in doctors million field. So this energy you we know is a half hour I squared where I was the induct INTs and eyes the current but the maximum energy stored. The magnetic field in the doctor is equal to the initial maximum energy stored the electric field of the capacity which is a half C v squared. And we know these values you know, the capacitance and the voltage so we can calculate this energy. So that's ah half into the capacitance of 5000 pickle ferrets, which is 5000 times 10 to the minus 12 parrots Times V squared, which is 100 squared. Hence we get an energy that they stored in the magnetic field that the doctor to be 2.5 times 10 to the minus five, and that's jewels. So that's our first answer. Now we know the magnetic field or the energy stored in magnetic field off the induct er. Now, for part B, we went to calculate the peak value off the current in the circuit. Now we know that you is equal to a half hour. I squared as above. So if you insist equation, we can find it. The peak current recall I not and I not is in square root off two times the total energy stored in the circuit to you not divided by the induct INTs. Our and again we know these values so we can put them into this equation. So that's the square root off to times the energy stored in the unique field. 2.5 times, 10 to the minus five jewels. We calculated this above divided by the induct INTs, which is 80 million Henry's or 80 times 10 to the minus three Henry's, which gives us a peek current in the circuit off 2.5 times, 10 to the minus two and piers That's 2.5 attempts into the minus two MPs. Yeah. Now that's our second answer for part B. So now the final part of this problem asks us to find the frequency off the observations in the circuit. So we know the angular frequency Omega Foran lt circuit is given by he square root off one over l C minus are over to our or square. Now, all of these values are known so we can calculate this angular frequency. So substituting our values in this is the square root off one off the induct INTs, which is 80 times 10 to the minus three multiplied by the capacities, which is 5000 times 10 to the minus 12 minus one when there are over 12 on squared. So that's the resistance. 2.5 times 10 to the minus two n piers over two times in doctors, which is to into 80 times 10 to the minus three. And this is all squared. So if we solve this so we have to solve each off these terms separately. So 1/80 10th into the minus three into 5000 tents into the minus 12 separately from the are over to out. Um, and we get omega finally, to be five times 10 to the four radiance for second. So now we have the angular frequency off the oscillations, but we wish to find the then your frequency f Now we know s is equal to the angular frequency Omega divided by two pi. And if we take the value for mega divided by two pi, we get the frequency off the oscillation of the circuit to be 7.96 I'm standing to the three huts and that's our final answer. No.


Similar Solved Questions

5 answers
Match each sentence to the most appropriate evolutionary concept:Transfer of alleles in and oute ofa population due to movement Gene flow of fertile individualsAlleles transferred to the next generation in portions that differ from previous generationMicroevolutionChance events that change allele frequencyGenetic bottleneckReduction in population size that alters gene frequencies of that populationGenetic drift
Match each sentence to the most appropriate evolutionary concept: Transfer of alleles in and oute ofa population due to movement Gene flow of fertile individuals Alleles transferred to the next generation in portions that differ from previous generation Microevolution Chance events that change allel...
5 answers
This assignment is past the original due date of Sun 02/09/2020 11:00 pm_ You have used LatePas Due in hours 51 minutes: Due Thu 02/13/2020 11:00 Hide Question InformationTextbook E?VideosThe current population of a small town is 5623 people: It is believed that town's population is tripling every 1L ycars Approximale the population of the town years from EPreview residents (round nearest whole number)Points possible: This attempt of 3.Submit
This assignment is past the original due date of Sun 02/09/2020 11:00 pm_ You have used LatePas Due in hours 51 minutes: Due Thu 02/13/2020 11:00 Hide Question Information Textbook E? Videos The current population of a small town is 5623 people: It is believed that town's population is tripling...
5 answers
Find ihe furcton tnat finally graphed after the follow 79 transfotiatons are appliedgraph ofy = Vx In the orcer [stedRellect abou: tne X-ax $ Shitt i Unuts Shh lelt 2 unts
Find ihe furcton tnat finally graphed after the follow 79 transfotiatons are applied graph ofy = Vx In the orcer [sted Rellect abou: tne X-ax $ Shitt i Unuts Shh lelt 2 unts...
5 answers
Question 2Not yet answeredMarked out of 2.00Flag questionWhich of the following is an oxidation - reduction reaction?Select one:Cu(s) - 2AeNO;324(9) Cuno } (2QHCI (aq) - NaOH (1q) H,o ()-NaCl (aq)Bac #,024Ns0. (19 Bs0_It,Hjo:AANO; (9 - HCI (aq)AICI ($) HNO; (~#jCO; (@Q - Cato;)- (#Q Jro (Ja cco
Question 2 Not yet answered Marked out of 2.00 Flag question Which of the following is an oxidation - reduction reaction? Select one: Cu(s) - 2AeNO; 324(9) Cuno } (2Q HCI (aq) - NaOH (1q) H,o ()-NaCl (aq) Bac #,024 Ns0. (19 Bs0_ It,Hjo: AANO; (9 - HCI (aq) AICI ($) HNO; (~ #jCO; (@Q - Cato;)- (#Q Jr...
5 answers
Explain how a polarimeter works and what it measures.
Explain how a polarimeter works and what it measures....
5 answers
Moving to the next question prevents changes to this answerQuestlon 1Write the mechanism of the following reaction to produce ethyl benzoate?CoHsOHbaseFor the toolbar; press ALT#FIO (PC) or ALT-FN+FIO (Mac} B Paragraph Arial14pX
Moving to the next question prevents changes to this answer Questlon 1 Write the mechanism of the following reaction to produce ethyl benzoate? CoHs OH base For the toolbar; press ALT#FIO (PC) or ALT-FN+FIO (Mac} B Paragraph Arial 14pX...
4 answers
Test the series for convergence or divergence.∞n2 + 54nn = 1
Test the series for convergence or divergence. ∞ n2 + 5 4n n = 1...
5 answers
Find the directional derivative Duf(−2,1,−1) for the functionf(x,y,z)=xy+yz+zx in the direction u parallel to the vectorv=〈1,2,−2〉.
Find the directional derivative Duf(−2,1,−1) for the function f(x,y,z)=xy+yz+zx in the direction u parallel to the vector v=〈1,2,−2〉....
1 answers
Many elements exist as polyatomic molecules. Use atomic masses to calculate the molecular masses of the following: \begin{equation} \begin{array}{l}{\text { a. } \mathrm{O}_{2}} \\ {\text { b. } \mathrm{P}_{4}} \\ {\text { c. } \mathrm{S}_{8}}\end{array} \end{equation}
Many elements exist as polyatomic molecules. Use atomic masses to calculate the molecular masses of the following: \begin{equation} \begin{array}{l}{\text { a. } \mathrm{O}_{2}} \\ {\text { b. } \mathrm{P}_{4}} \\ {\text { c. } \mathrm{S}_{8}}\end{array} \end{equation}...
5 answers
Have each group member study a different mode of radioactive decay (alpha, beta, gamma, positron emission, or electron capture) and present it to the group. Each presentation should include a description of the process, a description of how the atomic and mass numbers change, and at least onespecific example. Presentations should also address the questions: What do all nuclear reactions have in common and how do they differ from each other?
Have each group member study a different mode of radioactive decay (alpha, beta, gamma, positron emission, or electron capture) and present it to the group. Each presentation should include a description of the process, a description of how the atomic and mass numbers change, and at least one speci...
5 answers
(12) Sketch the solid_bounded by the cylinder 2=4-1 the planes 2 =0, y =0 ad y=4 Compute its volume as double integral:
(12) Sketch the solid_bounded by the cylinder 2=4-1 the planes 2 =0, y =0 ad y=4 Compute its volume as double integral:...
5 answers
A cil has IQ0 (urus, The indlucel GWrent in the coll Ix (,50 wlu ( maguetic (lux (hrough ,ch (urti 0 (he cil eltxes rato 0 (,(26 Tm' /s, The resistance of (he coil is; IA0 6) 0,nO 1.064 /0 "0 3 0.50 n 6.40x /0-* m
A cil has IQ0 (urus, The indlucel GWrent in the coll Ix (,50 wlu ( maguetic (lux (hrough ,ch (urti 0 (he cil eltxes rato 0 (,(26 Tm' /s, The resistance of (he coil is; IA0 6) 0,nO 1.064 /0 "0 3 0.50 n 6.40x /0-* m...

-- 0.021833--