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What are the products the following reaction?CH,_CH, C S_CH, CHCH_OHCH,CH;CCH,CH, CH,SHCH,CH,CCH, CH,CH,OHCH,CH,C_O_CH, CH,CH,SHCH,CH,C _CH,CH,CH; HOThe followring...

Question

What are the products the following reaction?CH,_CH, C S_CH, CHCH_OHCH,CH;CCH,CH, CH,SHCH,CH,CCH, CH,CH,OHCH,CH,C_O_CH, CH,CH,SHCH,CH,C _CH,CH,CH; HOThe followring compound isH -CHck_CH,CHz25LE[_ ether anhydride: ketal. hemiketal:How many storeoisomers are possible having the following strucrure?OH OH OHCH _CH-CH_CH_CH,

What are the products the following reaction? CH,_CH, C S_CH, CHCH_OH CH,CH;C CH,CH, CH,SH CH,CH,C CH, CH,CH,OH CH,CH,C_O_CH, CH,CH,SH CH,CH,C _ CH,CH,CH; HO The followring compound is H -CH ck_CH, CHz 25LE[_ ether anhydride: ketal. hemiketal: How many storeoisomers are possible having the following strucrure? OH OH OH CH _CH-CH_CH_CH,



Answers

a. What are the products of the following reaction? b. How many stereoisomers of each product could be obtained?

When we treat vinyl cyclo hexane with diatonic romaine, there are four possible products and that's because there are two al canes that each can react with the booming. And then uh the products exist in pairs of an anti MERS. So if the terminal alkaline outside the ring reacts with grooming, we get a dobro mo compound with one of the bro means on a chirality center, so we get equal amounts of the R. And the S. And anti us. In the other case where the AL came within the ring reacts with the booming. Again we get to an anti America products. But here there there are two chirality centers within the structure. So um both chirality centers are inverted in the mirror image or the and anti americ structure. But in both cases the two bro means our trans to each other.

This is the answer to Chapter 24. Problem number 39 Fromthe Smith Organic chemistry Textbook. This problem asks us what four compounds are formed from the cross two clays and reaction of Ethel Penton, O E and Ethel Propriety Pro pi in it. Okay, um and so basically, our four products are going to be, um, the two crossed condensation products on then the two self condensation products s O. The 1st 1 is gonna look like this. Okay. Ah. And so, uh, then have 123 Let me draw those lines a little tighter. One, 23 There we go. 12345 Okay, so that's the product where the, uh Ethel Propylene eight is the Electra file. So then we have the other cross product where the Ethel Propriety. It is the final eight. So that's gonna look like this. Then we'll have just one more carbon. Their case. So there is There are our two crossed products on. Then we'll have the two products of self condensation. So when the Ethel pro prying eight pro pion eat self condenses, that's going to look like this. Okay. Ah. And then when the Ethel Penton. 08 Self condenses That is going to look like this. Okay. Ah. And so these are the four, uh, plays in condensation products from this reaction. And again, it's the two cross products on then the two products of each of the starting materials condensing with itself. And that is the answer to Chapter 24. Problem number 39.

This question asked with what product is formed when one bro mo put propane reacts with each of these nuclear files. So starting with water? A, we have, um a primary. Well, these are all primary, bro Means, um, with the letter A is a very good nuclear viral. So we're gonna have an Essene to reaction here. So this negativo will come in and attack this carbon from the back and will kick off the brome at the brimming. And we will get this product plus a br minus ion. Um, part B. We have the same thing here. Good nuclear file is gonna give us this s end to your reaction. So we will come in and attack this carbon from the back and kick off Herb roaming, and we'll get a primary amine as our product. Plus the bro mean I on same thing for part C will do that backside attack and kick off the Breault main. This will give us a bio ether this time. Plus our bro, Ming ion left over, um, again, for part D will attack that carbon and kick off The bro mean this one is going to give us a file and our paro mean I on for part E again attack that carbon with a leaving group and kick it off. This one will give us, um, and ether plus the roaming ion. And lastly, for part F, this is still a good nuclear file. Even though it is neutral, it's basic enough that it still good one so again will attack that carbon and kick off the bro. Mean? And that will give us a secondary amine. And that will have a positive charge. Now, since we've added a bond to an arty, neutral androgen and, of course, our broening ion left over.

For a free treat. Pent. No again, hydride with vinyl chloride. We're not going to get any reaction. Um, big. Remember, when you treat and anhydride with water, you're going to hide. Relies it and you'll get two halves of it back as car back. Sell gas it. When you treat pension, OIC and hydride with water, you get two equivalents of pension. Our gas it, uh, for sea when you treat it with a new alcohol, alcohol is going to access nuclear file the alcohol. Will nuclear physically attack the Electra Filic carbon in the carbon. You, um And so this is assuming that we're using only a single equivalent of methanol. And so we would get one equivalent of the meth a Lester on. We would get one equivalent of the carb oxalic acid off. Sorry. That would be, uh, even with with multiple equivalence of methanol. This is what we get. We get this mixture of methyl ester and on the carb oxalic acid for day. If we just treat it with salt, there's not gonna be any reaction s so far. I don't I don't know that we've learned anything. Any molecule in organic chemistry that when treated with salt on, only salt will undergo a reaction. Pension only acid, sir, Our pension No again, hydride certainly won't won't undergo reaction under those conditions for E we're treating treating the anhydride with an excess of a secondary mean in car box Late I on which we have here complex with in the car box Late ion complex with the ammonia on. So that is the answer to Chapter 22. Problem number 46.


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