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Three blocks are connected as shown in the picture below. Mass of object 1 (far to the left) is m1 =0.85 kg, mass of object 2 on the horizontal surface is m2 = 8.98...

Question

Three blocks are connected as shown in the picture below. Mass of object 1 (far to the left) is m1 =0.85 kg, mass of object 2 on the horizontal surface is m2 = 8.98 kg and mass of the third object to the right is m3 = 4.76 kg. What is the magnitude of the tension on string 1? Record your answer to two digits after the decimal point. No units

Three blocks are connected as shown in the picture below. Mass of object 1 (far to the left) is m1 =0.85 kg, mass of object 2 on the horizontal surface is m2 = 8.98 kg and mass of the third object to the right is m3 = 4.76 kg. What is the magnitude of the tension on string 1? Record your answer to two digits after the decimal point. No units



Answers

Three blocks are connected as shown in the picture below. Mass of object 1 (far to the left) is m1 =0.85 kg, mass of object 2 on the horizontal surface is m2 = 8.98 kg and mass of the third object to the right is m3 = 4.76 kg. What is the magnitude of the tension on string 1? Record your answer to two digits after the decimal point. No units

So one problem. 21. We're gonna see if we can find vertical ass and totes in the function. T minus one, divided by quantity, T squared, plus one. So what we need for a vertical ass and tote, as always, is to divide a non zero number by zero. So we've kind of make the bottom zero somehow. That's gonna be a problem here if I try to do that. No, I need t to be the square root of negative one. That's not a real number. That's a complex number. And since in this course we're only working with the real numbers, we would say that the bottom can't be zero, and so we can't have a vertical ass in two. So for this problem, no, over the glass and tilt.

This. This problem illustrates a special product. Um, if we have a plus B times a square minus a B must be square. No, that's just gonna equal a Q plus B cubed. Okay, So this particular problem we were given to M plus one times for end square minus two, M plus one, which fits that pattern where a is to m and B is one. This is gonna give us eight m cubed. Okay, Thank you.

We want to determine or what values of T miss function here is continuous. So we want to do is actually look at each of the components and figure out where are these components and then just take the intersection of all those sets. Well, eats the negative T is defined for all real numbers, and we also know it's continuous. So this is all road numbers for where is continuous? What about E to the negative people? This is also all road numbers now. Natural log of T minus one. Well, we know natural log is going to be continuous where it's defined on, and it's only defined where we plug in positive value, so we need to check. So where his team? I just one shook Lee larger than zero because we need to make sure the inside of the numbers were plugging in our positive. So that's gonna be t greater than zero. I'm sorry a t greater than one, because it would add the one over. So if we take the intersection of these three well, intersecting the real numbers with this interval over here would just leave us with that interval and weaken right this in interval notation if we wanted to be one to infinity and t being an element of one to infinity. So this is where our function will be continues.

We're finding the last last transform of one plus eat the negative t squared. Now we can write one plus e to the negative t squared as one plus two into the negative T plus each of the negative T square actually to the negative to tea. So applying linearity This is gonna be equal to the last blast. Transform of one What's two times the last blast? Transform of each of the native D plus the lack last transport of each of the native to the first of this is eagle toe one address the second it's going to be too over s plus one and the third will be won over Yes, plus two.


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