5

Before collision8 kg4 mlsmzafter collision1.5 mls 8 kgVzfmz...

Question

Before collision8 kg4 mlsmzafter collision1.5 mls 8 kgVzfmz

before collision 8 kg 4 mls mz after collision 1.5 mls 8 kg Vzf mz



Answers

A $2.00-\mathrm{kg}$ ball moves at $3.00 \mathrm{~m} / \mathrm{s}$ toward the right. It collides elastically with a $4.00-\mathrm{kg}$ ball that is initially at rest. Determine the velocities of the balls after the collision. Example $7-8$

In this question were wanting to find the total momentum of the car on the truck before and after the car. Israel rear ended, so the car is traveling along at 14 meters per second when a truck RIA ends it and that is where it collides into the back of it. Now we're told in the question. Sorry. The trick for Clank looks like it's floating. It should be on the same plane as the girl. We're told in the question that the truck is 2000 kilograms. Andi that it is traveling at 25 meters per second. So this is the instant just before the collision occurs. The truck, It's super close to the car. They haven't quite collided yet. So we've got the truck going at 25 meters per second, the car going at 14 meters per second. After this collision, we will have the truck on the car touching each other on moving along at the same speed. Remember to out all your zeros in, as I almost forgot one there. So this question is asking us for the total momentum before and after the collision. Now, in this case, we have conservation of linear momentum, and that is because there is no external force acting on the truck or the car throughout the collisions. That means the total momentum before is equal to the total momentum afterwards. That means we only need to consider one of the cases to find the total momentum as it is the same. So we can ignore finding the total momentum in the afterwards case because we don't know the speed of the joint, um, truck and car combination. So let's look at the total momentum of the truck and the car before just the second before they collect with each other. So let's remind ourselves, the equation for momentum is mass times velocity. So let's begin with the truck. The mass of the truck is 2000 and its velocity is 25 meters per second. Let's add that to the momentum of the car, which is it's mass. 1200 times by its velocity, which is 40 so 2000 times by 25 is equal to 50,000 on day, 1200 times 14 is equal to 16,800. So if we add these together we get 66,000 800 being the total momentum of the car and truck prior to the collision, which is the same as the total momentum of the current truck after the collision and I've just added the units on their kilograms meters per second, make sure we're always adding our units on.

Good day. In this question we will be solving for the final velocities of the was. You see the the right formula from the more conservation of momentum and kinetic energy, exact location. So we have our for 0.17 serial kilogram ball. We have the one F. Is equal to M. One and M two Divided by um one last M two. The one I Our everyone is the .170 Finance .155 kg Divided by .170 last .1.5. Do you love Graham times the way one I. 04 m per second. So our we won F is equal to point 185 m/s. Next for the for or .155 kilogram ball. We have We do f equals to M1 divided by any wonders. M two times the we won I so we we have two times .17 serial kg Divided by .170 plus .155 kilogram times for winter's per second. Our V two F is equal to 4.18. The threes per second. Thank you.

In this question. We want to find the total momentum off to bulls prior to them colliding and after them colliding were given in the question that we have a three kilogram ball going to the right with a speed of four meters per second on a four kilogram ball going to the left with the speed of three meters per second. So in this case there is conservation of linear momentum. That means that the total momentum prior to the balls colliding on the total momentum after the bulls have collided is going to be the same. And that is because there is no external force acting on either of the balls. So let's begin by calculating the momentum of this system before. So that is the momentum of the ball moving to the right, plus the momentum of the ball moving to the left. So the momentum of the ball moving to the right is its mass times velocity. So momentum, remember, is mass times velocity, so that is three times for well, then add this to the momentum of the ball moving to the left size, its mass, which is four times by its velocity, which in this case now is minus three. And that's because remember, velocity has direction on this velocity is acting in the opposite direction to this velocity. So there has to be a change in sign there. We're in this case. We're taking velocity to be positive when it acts to the right. So lost, he hacked into the left is negative. Therefore, we have got three times four minus four times three, which I'm sure you can see is equal to zero. I remember our unit zero kilograms meters per second. So because we've said that there is conservation of Linux momentum, we know that the total momentum zero kilograms meters per second is the same prior to them colliding. And afterwards, so that answers the question. It is zero kilograms meters per second before and after.

Problem # 196. In fact, there is a body of mass five Kg moving with a velocity velocity. This is mass, this is you won okay along a straight line collided with the body. Two kg moving along the same line with the velocity. Okay, so another masses ah of two Kg. It is moving in the same line moving in the same line. So either in this direction or in this direction with velocity. You want. Okay, the collagen perfectly inelastic magnitude of the velocity of composed mass after the collision. So we'll be considering two cases first. We should write whatever it is being given five kg MAs four m per second. Five kg mass four m/s and then I am too two kg MAs An eight m/s. U. N. Is either eight m/s or uh minus eight m per second. If it's going in this direction, if we support these two positive. So there will be two cases. Case one Case one is when you equal to this get me the president. So momentum will be conserved from the previous question. They will be getting be equal to and when you win plus him to you too. Buy in one place. I am too. So the same one and one is Uh huh five kg five and two four plus 2 into eight, Divide by five Plus 2. Doing deep Bliss 16 37 36 x seven meter per second. So when answer should be this and second the equal to and when you on formula will be the same. But only thing is here it will be negative in place of positive. So 20-16 x seven pulled by seven meter per second. Okay so option numbers B and uh the korean. Okay option maybe. Andy are the correct answers. Thank you.


Similar Solved Questions

5 answers
8 H;C OH H;C Considering OH both 12 089 CH; MCHCH; regiochemistry 0 OH 2H OH 2: stcreochemistry CH,CH; CH,CH; uhat is the - H;c OH 82# major OCH 2 OH { Organic product of the CH,CH; CH; following ncaction
8 H;C OH H;C Considering OH both 12 089 CH; MCHCH; regiochemistry 0 OH 2H OH 2: stcreochemistry CH,CH; CH,CH; uhat is the - H;c OH 82# major OCH 2 OH { Organic product of the CH,CH; CH; following ncaction...
5 answers
Electric Dipole Moment, Torque and Work Puntos;5 Peit equz opposite charges 0 J1 separated by CM JrP placed Electric Field (E strength 8500 M{c shownthe diagram. What is the magnitude Df the dipole Moment?
Electric Dipole Moment, Torque and Work Puntos;5 Peit equz opposite charges 0 J1 separated by CM JrP placed Electric Field (E strength 8500 M{c shown the diagram. What is the magnitude Df the dipole Moment?...
5 answers
2 For the following wffs, indicate which variables are free and which are bound (a) (x) (y) (z) ((Fxy T-> Gxy) v (Hxa - -> Hzbu)) (b) (Ex) (Ey) Hxxy _ -> (z) (Gz v Hx) (c) (z) (Ex) (y) (Axayzw V Bxycuvz)
2 For the following wffs, indicate which variables are free and which are bound (a) (x) (y) (z) ((Fxy T-> Gxy) v (Hxa - -> Hzbu)) (b) (Ex) (Ey) Hxxy _ -> (z) (Gz v Hx) (c) (z) (Ex) (y) (Axayzw V Bxycuvz)...
5 answers
S . Cmsider the &raphs wih 4 ver tices 4 edazs. Does the follswig al fundamental Cases 2Ca)(b)Are t Graphs(2 )eqjivaleut 7 DQ(a ) & (b) 7
s . Cmsider the &raphs wih 4 ver tices 4 edazs. Does the follswig al fundamental Cases 2 Ca) (b) Are t Graphs (2 ) eqjivaleut 7 DQ (a ) & (b) 7...
5 answers
1 1 1 1 H 8 3 1 5 8 { 1 03| 3 1 8 | ~ 8 { 9 6 { la 8 2 1 1 93 J 5' 8 $
1 1 1 1 H 8 3 1 5 8 { 1 03| 3 1 8 | ~ 8 { 9 6 { la 8 2 1 1 93 J 5' 8 $...
5 answers
Una pledra es lanzada horizontalmente desde la altura de una colina con una velocidad de 30 mls: Si se abserva que cae una distancia de x 25 m , desde que altura fue lanzada? Utilice Ia ecuacion de Ia trayectoria de un proyectil para resolver el problema: 10 puntos
Una pledra es lanzada horizontalmente desde la altura de una colina con una velocidad de 30 mls: Si se abserva que cae una distancia de x 25 m , desde que altura fue lanzada? Utilice Ia ecuacion de Ia trayectoria de un proyectil para resolver el problema: 10 puntos...
5 answers
Find the minimum value (remember that this is the y-value not the € value) for the function f (c) = 2?_2 € on the interval [0, 10] Round your answer to two decimal places_
Find the minimum value (remember that this is the y-value not the € value) for the function f (c) = 2?_2 € on the interval [0, 10] Round your answer to two decimal places_...
5 answers
The complex $left[mathrm{Co}left(mathrm{NH}_{3}ight)_{5} mathrm{Br}ight] mathrm{SO}_{4}$ will give a white precipitate with(a) $mathrm{PbCl}_{2}$(b) $mathrm{AgNO}_{3}$(c) KI(d) none
The complex $left[mathrm{Co}left(mathrm{NH}_{3} ight)_{5} mathrm{Br} ight] mathrm{SO}_{4}$ will give a white precipitate with (a) $mathrm{PbCl}_{2}$ (b) $mathrm{AgNO}_{3}$ (c) KI (d) none...
5 answers
ChapterProblem 034elestron followe helica Vclority chanacs "Itntimeunifsrm magnetic field given by (157 _ 36k) mT: tne €leclron velc -ity qiven v = (177 - 34 + 471) M/s {a} What tha 8n9 speed change: #th tIme? (€) Do It5 angle changes with ome' (J} What i the radius tha helical path?between3 ? The electron'(2) NumberUnit(4) NumberUnits
Chapter Problem 034 elestron followe helica Vclority chanacs "Itntime unifsrm magnetic field given by (157 _ 36k) mT: tne €leclron velc -ity qiven v = (177 - 34 + 471) M/s {a} What tha 8n9 speed change: #th tIme? (€) Do It5 angle changes with ome' (J} What i the radius tha heli...
1 answers
A 1-oz bullet is fired with a horizontal velocity of 750 $\mathrm{mi} / \mathrm{h}$ into the 18-lb wooden beam $A B$. The beam is suspended from a collar of negligible mass that can slide along a horizontal rod. Neglecting friction between the collar and the rod, determine the maximum angle of rotation of the beam during its subsequent motion.
A 1-oz bullet is fired with a horizontal velocity of 750 $\mathrm{mi} / \mathrm{h}$ into the 18-lb wooden beam $A B$. The beam is suspended from a collar of negligible mass that can slide along a horizontal rod. Neglecting friction between the collar and the rod, determine the maximum angle of rotat...
5 answers
Find the shaded area. Round to the nearest tenth, if necessary.CAN'T COPY THE FIGURE
Find the shaded area. Round to the nearest tenth, if necessary. CAN'T COPY THE FIGURE...
5 answers
2k+ [ 2) l kkl
2k+ [ 2) l kkl...
5 answers
Phenotype number 6a 603 516 2 ; 1 6 89 06 81 m n02
Phenotype number 6a 603 516 2 ; 1 6 89 06 81 m n02...
5 answers
Part CIfa 6.0 ki resistor is t0 be connecled across 120 resistor?potenlial difference, whal power rating required (or thatExpross your answer with the approprlate units_ValueUnits
Part C Ifa 6.0 ki resistor is t0 be connecled across 120 resistor? potenlial difference, whal power rating required (or that Expross your answer with the approprlate units_ Value Units...
5 answers
Find the ared 0( the region.Need Help?
Find the ared 0( the region. Need Help?...

-- 0.021254--