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Homan Walk her entine welghl Momcrconiy Diacld pne nell ohner hion-hel_ed shce5 Calculato poulesuretoxerted floor thmhang Iae has an arua el1,43 cm? and the waran ...

Question

Homan Walk her entine welghl Momcrconiy Diacld pne nell ohner hion-hel_ed shce5 Calculato poulesuretoxerted floor thmhang Iae has an arua el1,43 cm? and the waran $ mass Is 57,0 k9. Express thc pressure pascale. (In tht eatly duys comrnorodl Inshl Hom cnrnure notanoncd Mumnt hlgh-heutud 4n04s Dacansealecrall (loorcaadothln #ilhttunu wuch Ioc presuigs:)Fams

Homan Walk her entine welghl Momcrconiy Diacld pne nell ohner hion-hel_ed shce5 Calculato poulesuretoxerted floor thmhang Iae has an arua el1,43 cm? and the waran $ mass Is 57,0 k9. Express thc pressure pascale. (In tht eatly duys comrnorodl Inshl Hom cnrnure notanoncd Mumnt hlgh-heutud 4n04s Dacansealecrall (loorcaadothln #ilhttunu wuch Ioc presuigs:) Fams



Answers

Dogs -like many animals - stand and walk on their toes. A photo of the rear foot of a dog is shown in Figure $\mathrm{P} 8.50 \mathrm{a} ;$ Figure $\mathrm{P} 8.50 \mathrm{b}$ shows the bones of the leg and foot along with relevant distances. The colored element corresponds to your foot, and the connection with the leg corresponds to your ankle. The Achilles tendon pulls on the end of the foot, along a line $4.0 \mathrm{cm}$ from the ankle. What is the tension in the tendon if a $20 \mathrm{kg}$ dog is supporting $1 / 4$ of its weight on one rear foot?

Here we have a bar which has got some weight and then say this distances X So the rest of the distance comes out to be zero foreign night five made out of minus X, the force to the left and is 1 57 new done on the floor to the left and is 89 mudo. So we have the daughter where it was 89 plus 1. 57 milion equals 2. 46 you know, And in order to find X, we have So that's got this point to be a dark about a equals zero. So we have w. Times X equals 1 57 times 0.95 So we have X equals 1 57 times. Little boy 95 divided by W. We just to 46. So x comes out to be zero born, 34 m from the west end or the front off the scale

The fourth diagram Looks like here is the weighed acting downwards. And here is the reaction force, if one. And here is the reaction Force F two. We are given that this hold and is 0.95 major and we are trying to find this distance X. Let's call this point to be a We have w It was, if one does have to it was 89 new done. Thus 1 57 new done. So w comes out to be 246 million. Now Jews dark about buying a Glock zero. So we have definite times x r, 2 46 x It was F 2157 times 0.95 So, solving from here we find that X equals 0.606 major, and this is measured from the rear feet.

We have a tear off 60 kilogram on area off one leg, 0.2 centimeters coil and us to calculate the pressure exerted by one leg off this chair. So we have a tear having four legs. So the bait off the chair is distributed equally among four legs on So one court off this latest a played on a single click on so we can write The pressure exerted tricked us B is they do fourth by a DEA. It is a grilled toe MD by four. So we should include the four here, multiplied by the A video fun leg. This is equal to 60 kilogram in do these 9.8, derided by food in do little 0.2 into attend rates to minus four because were given area in centimeters squared. But we should use the FAA units. It gives the pressure as seven point 35 indigent raise, too. Seven Newton permitted square or basket, and now we have an elephant waste 1005 100 kilogram on it is standing on a single food, and we are asked to calculate the pressure exerted by the elephant. Do you do this? Beed In one food having a area 800 centimeters squared so again using the same formula, Fisher is equal Toe Poor's My a d l. It just equal to MGI by idea gain. We should ride the area in meters core units 800 in do 10 days to minus four. Meet this square and we can write the pressure US 1005 100 and do 9.8. Divided by 800 in due 10 days to minus four, it is equal to one a three seven flies, little baskets. This is pressure accepted by the elephant if it is standing on a single foot, having 800 centimeters squared off 80 but

So the situation is such that the body is in this kind of position. Where this then Ty's 1 62 on This is where the normal four through the arm is going. The weight off the stop body is acting over here. The weight of the bottom body is acting over here. So now we have to find these distances and the anger's Let's got this angle. The angles to be Tedder and Fee. This is 90 degree over here. So if this is a judge, then the event over here is given to be 49 41. The events over here is 65 and 70 so this distance he's 90. Course I Integra. Now we have 19 course 90 sine theta. His age equals 65 plus 70. That is 1 35 sci fi and we have Ted up. Thus fee equals 90 degree. So from here we can solve them. We can find that cheddar is 56.25 degree on DFI equals 33.75 degrees. So this thing comes out to be 90 co sign Tetteh equals 27.2. Sending me down this distance comes out to be. This is the distance that we would need, which is 49 Goes on, Ted, uh, which is 27.2. And then you can find this just jen sweeties 70 co sign fee. So these distance comes out to be 1 60 to minus that which is 103 point eight centimeters. So now that's called this point. To be a so dark about point ache was zero. And what you end up having ease in autumn times 1 62 equals is to 77 times 27.2 plus for 77 times 103.8. So from here you can solve an A to be 350 Newton so forth through each arm. Equus half off an A equals 1 75 newton. Now force on the leg. If this is an leg force on the leg is half times and leg equals half times w stopped, stopped the bottom minus in a on Catholic days. It comes out to be 200 newton on each feet. Now we're trying to find a frictional force as well on the feed, so that can be solved by frictional force on the fate equals the movement down the 74.9 centimeter. So one with that minus 400 times 50 centimeter miners, 277 Newton is the fourth due to the lower body. Times 22.8 New done. So that comes out to be 1 82 foreign seven Newton.


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