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Question

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Answers

The table shows the cost of a year's tuition, room and board, and fees at 4-year public colleges for the years $2006-2014$. Letting $y$ represent the cost in dollars and $x$ the number of years since $2006,$ the function $$f(x)=13,017(1.05)^{x}$$ models the data quite well. According to this function, in what year will the 2006 cost be doubled? $$\begin{array}{|c|c|} \hline \text { Year } & \text { Average Annual cost } \\ \hline 2006 & \$ 12,837 \\ \hline 2007 & \$ 13,558 \\ \hline 2008 & \$ 14,372 \\ \hline 2009 & \$ 15,235 \\ \hline 2010 & \$ 16,178 \\ \hline 2011 & \$ 17,156 \\ \hline 2012 & \$ 17,817 \\ \hline 2013 & \$ 18,383 \\ \hline 2014 & \$ 18,943 \\ \hline \end{array}$$

Okay, So in this problem, it's asking us to find several values for a solution that is your 0.2 75 smaller, appropriate tannic acid and this concentration of hydro acetic acid asking us to calculate certain values versus asking for the concentration of Hydro Nehemiah in solution. To see this, I will create a nice table even though it's not going to require much calculations and I'll show you why. So let's see here. First we start out with 0.892 older pipe hydro biotic acid. And since it is such a strong acid has such a high peak K value. I'm sorry, uh, much smaller PK value. So I'm going to say that the peka h I is much smaller peek a of no panic acid. We can safely assume that 100% of the hydro I'd take acid is going to dissolve. And for every part of hydro biotic acid that dissolves, we generate that same amount. Hydro Nia my on And, um, I died I am because they have a 1 to 1 ratio. So, um, we can say that with high certainty that the concentration of hydro Nehemiah in solution 0.892 Yeah. Okay. In part B, they want us to calculate the concentration of O h minus and solution. And to do that, I will be using the equation. Okay. W e cause this remember, K w equals 1.0 times 10 to the negative 14. So utilizing the concentration of a journey, Um, ion in solution that we just gave, um, they should come out to 1.1 times 10 to the negative 13 more, which is much smaller than the concentration of hydro Nehemiah, which makes sense because hide your eye, dick acid is such a strong acid. Now, here they want us to find the concentration of, um, ionized form of probiotic acid. And to do that Well, first, I'm just going to illustrate the equilibrium equation, and I'm going to be using the K A value which is given to us. Okay, so here we know the K because it's given to us. We just saw for the hydro knee. Um, I mean concentration. Um, And for this pro panic ion, we can actually um actually, that's what we're solving for. But the concentration of this the pope Janek acid we can safely assume that it is 0.275 more. Why? Because we have so so much hydro Nehemiah on due to the strong acid, the strong acid hydrochloric acid. So according to a list shot tears principle, this equation should be driven to the left. So which means that you can solve for this sense it is the only unknown. And if you do that, um, the answer should come out to four times 10 to the negative Fifth more party is asking us to calculate the concentration of iodide ion in solution If you go back to part A Since we assume that all the hydro, acetic acid dissolves and iron Isis, this concentration of I died is the same concentration of hydro acetic acid that was initially dissolved in solution which would give us 0.892 more

Okay, This equation has three variables Z squared equals x squared plus y squared. So, we had to be given extra information. DX DT is two. Dy DT is three. Find DZ DT when X is five and y is 12. All right. So every one of these is changing with respect to T. So when you take the derivative of the square, you get to Z times the derivative Ozzy, which is DZ DT equals two X times the derivative of X. Dx DT plus two Y times the derivative of Y Dy DT. So we can divide the twos off of all of them. Okay? So find DZ DT when X is five, Ny is 12. So five is gonna go here. 12 is gonna go here but we don't have anything for the Z. So we have to stop and find that first. Use the original equation. So, Z squared equals five squared last 12 squared. That's 25 plus 1 44. That's 1 69. So, Z is plus minus The square root of 169, which is 13. That's where he's positive 13 1st. So 13 DZ DT equals five times two plus 12 times three. So DZ DT equals 10 plus 36. 46/13. Okay, And then when you plug in uh minus 13 for Z, you'll get dizzy. D T Equals -46/13

XCF six on idolizes XCF six on high dialysis gifts XC 02 F two as well as x c o F food and ACSI rotary as the no doubt therefore, option A, therefore, option A. Of sand B and of some B uh, correct here.

We have been given these two functions p X and Q X, and we have to find out three bx minus Q x. Okay, No, we will multiply this by three. So we get 39 extra deep. Our five minus 66 after the power for minus 108 x Q plus 1 20 x squared. Plus it be next plus 25. Now we have to subtract it with you ex so minus 42 extra deep our five plus 37 extra REpower for minus 50 X Cody Power Cube plus 28 x squared minus 34 x minus 100. So this becomes minus three extra deep our five minus 29 x to the power food minus 1 58 extra. The Power Cube plus 1 48 x squared minus 16 x minus 1 25 is the answer.


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