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How lfar; fu u from 4 Ibase of the building m does the rock land?...

Question

How lfar; fu u from 4 Ibase of the building m does the rock land?

How lfar; fu u from 4 Ibase of the building m does the rock land?



Answers

An astronaut drops an overhead rock on the Moon. Discuss what force(s) act(s) on the rock as it drops.

Our villain. That's what we have. Here is a question that is dealing with forces and motion in one dimension. It's basically one dimensional kinetics, and what were given to us is that rock is dropped from a very tall tower, and we know that it takes one a half seconds for this rock to reach the ground. And what we're asked to solve for is the height of this tower. So we know the initial velocity is zero because the rock is dropped and the only forces that are gonna be acting on this rock is just the way force that's due to gravity. So the way that we're gonna be solving this question is by just using our one dimensional cinematic equations for constant acceleration and directly Saul for this height. So let's go ahead and started. So the king thematic equation that's especially useful for us here in this particular case is saying that why why is equal to y zero plus V zero times t plus one half eighties for so we can go ahead and move y and y 0 to 1 side so we can just say this is Delta y, which is equal to our height is equal to V zero times T plus one half a T squared. We know that our initial velocity zero for this term goes away. What we're left with is A J is equal to one half a t squared. Now we know that our acceleration is just gravity and our time is for access. So we can directly compute this age by saying that this is equal to one half times 9.81 m per second squared times 4.5 2nd square. And this gives us a height that's equal to 100 m. That's your finances.

So here we have a kinetic energy initial this gonna equal kinetic energy, and we know that this is going to come to arrest. So in coming to arrest, we know that Tel toe ass is going to be equal to Q over tea. And here energy becomes unusable. Here are only envy becomes unusable because none of it's harnessed. None of it's transferred to electrical energy or thermal energy or any type of energy. All of it's going to be transferred to the environment. So unusable, Ah, are all energy transferred to the environment. And then we're going to say that the temperature of the rock equals the temperature of the environment and this again equal some temperature ti calvin. So our delta s will simply be equal to cue the total amount of energy. And this is going to be equal to the Connecticut and G k E divided by sum temperature teen Um and then the units will, of course be Jules per Calvin. So this will be our final answer for the change of entropy of this rock after it. The change in the entropy of the universe after this rock stops moving because again, all of the energy becomes unusable, all of it's transferred to the environment. The temperature of the rock is equal to the temperature of the environment equal to some temperature in digger in Calvin. And we simply need to take the kinetic energy divided by the temperature. And of course, the units are jewels per kelvin. For the change in entropy. This is our final answer. That's the end of the solution. Thank you for watching.

Okay, so you're a softy. That is the Ordo 16 d square. Right? So the aggression represent the distance s in feet, that an object will fall in the seconds. Right? So first of all, take it easy, called 03 So here and so three that is equal to 16. Money by by three square three squared is according nine and you're 16. Money. Grab by nine. That is equal to 1 44 Right now. Take it easy. Call due to severe s off through that is a total of 16 money that I threw. Square two squared is equal to four and 16 multi. But before that is equal Drew 64 right now. Take me. That is s 03 minus s off to your sa threes. 1 44 and s off to that is 64 of your 1 44 minus 64 that is equal to 80. So we can said that D during the 3rd 2nd Baroque drivers. 80 feet, right. Thank you.

So here in this question, we will use the working of the tour um To solve the problem, apply work energy to them. We can write work done is equal to in in kinetic energy or work then is equal to final kinetic energy minus initial kinetic energy. So the work done, even in our question is -211 June. So this is equal to this is a request to the final kinetic energy. That is how um the F. B square minus initial kinetic energy which is given as 346 Zul From this we get 346 -211 is equal to multiplied by the mosque. Given us 2.15 Kg entrepreneur LV square the Episcopal final velocities. But and from this equation figured the final velocity V. F. Will come out to be 11.2 m/s. Go post again. This is the so this is the finally spirit of Iran and option option is correct.


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