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Vinegar usedConcentration NaOHTrialTrial 2TrialMass of empty flask (g)104.32104.85104.75Mass of Ilask wilh vinegar (g)107.42107.74107.65Mass of vinegar (g)Initial ...

Question

Vinegar usedConcentration NaOHTrialTrial 2TrialMass of empty flask (g)104.32104.85104.75Mass of Ilask wilh vinegar (g)107.42107.74107.65Mass of vinegar (g)Initial NaOH volume (mL)1.000.010.60Final NaOH volume (mL)26.7027.0027.62Volume of NaOH used (mL)Moles of CH;COOH in sampleMass of CHSCOOH in sample Percent by mass of CH;COOH in vinegar sampleAverage

Vinegar used Concentration NaOH Trial Trial 2 Trial Mass of empty flask (g) 104.32 104.85 104.75 Mass of Ilask wilh vinegar (g) 107.42 107.74 107.65 Mass of vinegar (g) Initial NaOH volume (mL) 1.00 0.01 0.60 Final NaOH volume (mL) 26.70 27.00 27.62 Volume of NaOH used (mL) Moles of CH;COOH in sample Mass of CHSCOOH in sample Percent by mass of CH;COOH in vinegar sample Average



Answers

A $25.0 \mathrm{~mL}$ sample of vinegar with a density of $1.01 \mathrm{~g}$ $\mathrm{mL}^{-1}$, containing acetic acid, was titrated using $0.504 \mathrm{M}$ $\mathrm{NaOH}$ solution. The titration required $42.54 \mathrm{~mL}$ of the base. What was the molar concentration and the percent by mass of acetic acid in the vinegar?

And this problem. We're given a lot of information about a base in an acid and asked to calculate the polarity of the asset. To this end, we're gonna use the equation for malaria and a peaceful to number of moles divided by volume and leaders. I noticed that this equation can be written in three different ways. We can solve for polarity, consult for moles, and Ripe says, and the times, um, is equal number of moles. Or we can call for volume and find the volume A sequel to number of Moles by mole Aridity. These will serve you well as you move through these. Now, I'm gonna go to this thing a lot of detail if you're just here for the solution and you want to see the one step shortcut way of Stoke Yama tree pill tree. Um, but I will take the time to explain each step conceptually. So if you want to skip ahead to the end, you can go ahead and do that. So we have, uh, a lot of information about the space over here knows we have volume and the polarity. So we're gonna use that information to find the missing piece that's the number of mulch to our first step is going to be to find the number of malls of anyway. H the reason why we want more than a wage. Because in this reaction, we're told by nature of the reaction that one more of any U. H reacts with one roll of acetic acid so that I can use the multi more ratio to find malls of the feet of Katherine. So notice that would that does is it gives us more of this substance, and with the volume we can then find the polarity that we're after. So that will be. Our final step is to find similarity up the acid history seal, too. So let's start with that. First, I need my volume in leaders. So this is 0.947 leaders. Polarity it serves us to remember, can be written as you're appointing 00 molds for every one leader. I noticed that when I multiply these together, the leaders cancel out nicely and their product is you're a point. You're a point hero who want each night four well, sodium hydroxide. Okay, now recall that we said that for every one more sodium hydroxide. We have one more of acetic acid, so I don't really need to do any math here. I just know that because of this want to one ratio that I have just as many moves of acetic acid as I did sodium hydroxide. No math involved. I just already know the next step. And then now what? I have multi story of acetic acid volume of the Vedic acid. I confined the polarity by the fighting, given the definition, Willard. So I have 0.1894 more divided by the volume, which in leaders his Euro point Nero to 50 leaders motive units of molds divided by leaders. This is equal to 0.7576 mold over leaders, which is the same thing. Moeller and I'm going to round three significant figures, given that I had three significant for years and all of my initial givens with 0.758 look okay, now let's talk about the shortcut. You have a good grip on all of these things. You can kind of conceptual work your way through it all in one go. So let's start with the volume of acid, just as we did at the top. I have this many leaders of nitric acid, so I need to multiply by the polarity of nitric acid you can treat this polarity is a conversion factor. She could write it either with moles in the numerator, leaders in the numerator and the unit that comes before is gonna guide you. I mean, those us to cancel Next. Remember, we had to change substances. We do that using multiple ratio. One more of acetic acid reacts with warm bowl. Sure, I am. Keep writing H in the three. My God. And the problem back there should be any Uhh you don't really know when will the new age. And finally, I can't divide this results by the volume. Remember, that's for what I have, leader. So your small small This whole product gives me multiple acetic acid and I'm gonna divide mulled by leaders Europe with 0 to 50 beaters, acetic acid solution And what that will give me Smalls, former leaders or polarity. All of that is equal to the same 0.758 Moeller. I don't know, it's the same. I basically did the exact same process the whole way down. This is it in one

So in this problem, we're given with a sample off vinegar which contains obviously acidic gas it and which were actually sodium hydroxide. According TTO, this equation given here and were provided with the data is where to say that if this volume of finegar needs this volume off and this concentration of sodium hydroxide to reach the given spined unit iteration, how many grams of acid I guess ID are in one quart sample off this vinegar? So what we will do first is we'LL find out the number ofthe malls off sodium hydroxide for this much volume and thiss much morality and from that number of malls using this equation, we'LL find the number off most of the acid acid for the's volume of finegar. And if we can find out the number of malls off acidic acid in this much volume of vinegar, then we can find out the number of most of acidic acid in one quart sample of vinegar and from the number of malls of acidic acid in one quart symbol of finegar confined the mass offensive against it in grams in their example of vinegar. So first we'll find out the number of Mme. Also sodium hydroxide from the Cuban data, so number of balls off sodium hydroxide will be equal to It's more clarity. Time's volume in later. So the morality of sodium hydroxide given is the sirah planned one one five Mueller are more per liter times we have the volume. As for the two point five million liter, and we'LL write it as forty two one five times, ten to the four minus three later. And this will give us value off sirrah point zero zero four nine more off sodium hydroxide. So this is the number of moola sodium hydroxide, which is reacting here now from the banister question, you can see that one mole of sodium hydroxide reacts to it. One more of acidic acid. That means the small of sodium hydroxide will react with the same number of mall of gastric acid that with the number of Mall of acid, E has said in three point four five ml of vinegar is also zero point zero zero four nine small. Now what we have to do is we'LL find out the volume in militar for one word sample of finisher so one quart is equal to nine forty six point three five three Mil eater. So one quart off sample of vinegar means nine. Forty six point three fifty millimeter of vinegar. Now if three point five millimeter of vinegar contains this much matloff acid, Agha said. Weaken raid three. Plant for five million litter. Finegar contains zero point zero zero four nine more off acidic acid. That means thiss militar of vinegar nine. Forty six point three five three militar all finegar will contain zero point zero zero four nine more over nine. Forty six point three five three militar out. No, I didn't mean but it is reforming over three point for five mil eater times nine. Forty six point three five three millimeter And this will give us a bell off one point tree for more off acid. I guess it. So this is the number of malls off acidic acid in one quart or nine. Forty six point two five three mil of finegar. So from from this number of morally confined them mass offensive, gas it in grams in one or symbol of vinegar. So the mass ofthe city and sit in the sample will be equal to ah, the number of malls times the molar mass. So the number of mall is one point three formal times the molar mass offensive. I guess it is sixty point zero five Grandpa Armel. And it will give us eighty point five one Graham answer to guess it. So this is the massive acidic acid in grams in, um, one court. Simple off finegar.

So here we have the following reaction. We have HC two H. 302 at N. A. O. H. But sodium hydroxide also in the acquis phase. That is an equilibrium way of H 20 In the liquid phase at N. A. C. To age 302 In the acquis space we have one mole of sodium hydroxide that is needed to neutralize one mole of HC two H 302 So you can calculate the moles of sodium hydroxide which is equal to 9.115 mola multiplied by 42.5 mil. We have to divide that by 1000 because we need units of letters that is there for equal to 4.888 times 10 to the minus three moles. And because we have a 1 to 1 straight geometric relationship between are we agents? We have a 1 to 1. So the malls will be the exact same for HC two H. 302 So you can combat one Q. T. Into milliliters. So one Q. T. Multiplied by one liter divided by 1.57 Q. T. Multiplied by 1000 male divided by one liter. That's equal to nine for 6.7 millimeters. So we can calculate the malls of H. C. Two H. 302 over on the next page here. So we have 4.888 times 10 to the minus three moles, divide that by 3.45 millimeters. But multiply that by 946.7 millimeters. What we get out is 1.341 moles HC two H. 302 We can calculate the mass as well of the same material. So we have 1.341 malls multiply that by 60.5 g per mole. That's the molar mass. We got about 80 0.5 g.

First thing we will do here is to dissolve this compound in border will miss it, the conductors to see if the solution carries and electrical current. If solution is conducting, then we can determine whether the solution is a strong or weak electrolyte. By comparing its convicted, it's with that off unknown strong electrolyte, or it can also be done by using the APP critters shown in a textbook.


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