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A compound is composed of 26.58% potassium (K) and 35.45%chromium (Cr) and 37.97% oxygen (O) by mass.What is the oxidation state of chromium in thiscompound? +2+3+4...

Question

A compound is composed of 26.58% potassium (K) and 35.45%chromium (Cr) and 37.97% oxygen (O) by mass.What is the oxidation state of chromium in thiscompound? +2+3+4+5 +6One 591 mL bottle of Gatorade, a popular sports drink contains35 g of sugar. If the sugar compound is glucose,C6H12O6, what is the molarconcentration of glucose in Gatorade? Choose the closest answer. (Note: 1 M = 1 molL−1).3.4M1.2M0.11M11.0 M0.33 M

A compound is composed of 26.58% potassium (K) and 35.45% chromium (Cr) and 37.97% oxygen (O) by mass. What is the oxidation state of chromium in this compound? +2 +3 +4 +5 +6 One 591 mL bottle of Gatorade, a popular sports drink contains 35 g of sugar. If the sugar compound is glucose, C6H12O6, what is the molar concentration of glucose in Gatorade? Choose the closest answer. (Note: 1 M = 1 mol L−1). 3.4M 1.2M 0.11M 11.0 M 0.33 M



Answers

A compound is composed of 26.58% potassium (K) and 35.45% chromium (Cr) and 37.97% oxygen (O) by mass. What is the oxidation state of chromium in this compound?
+2 +3 +4 +5
+6 One 591 mL bottle of Gatorade, a popular sports drink contains 35 g of sugar.
If the sugar compound is glucose, C6H12O6, what is the molar concentration of glucose in Gatorade?
Choose the closest answer. (Note:
1 M = 1 mol L−1). 3.4M 1.2M 0.11M 11.0 M 0.33 M

In problems having a of chapter three chemical reactions of section to determine empirical and molecular formulas. So in this question, what is the identity of the compound? So assume 100 g of sample and find the number of moles of each element. So we have chromium and oxygen. Okay, so we have given that elemental analysis uh of the compound shows that it contains 68.43% chromium. So I can write 68 point 43 graham chromium into one mall chromium upon 52 graham Colombia. So this 52 graham is the small amounts of chromium. So on solving this weekend, 1.316 mall chromium. So and also we have uh given 31.57% oxygen. So similarly we can find the most of oxygen that is uh 21 point 57 g oxygen into one mall oxygen upon 16 graham oxygen. So this on solving we get 1.973 mall oxygen. So now you can write in this way. So we have a premium and oxygen mole ratio that is 1.316 ratio 1.973 So this 1.973 is close to, so this value is close to two. And uh so from these uh number of moles, the small value that we have to divide. Yeah by each of the following. So this small value is 1.316 So again divide 1.316 1.316 ratio 1.973 on 1.316 So that this become one. And this I can write 0.66 or this 0.66 This can also be written as 1.5, like I can 0.66 that is a call to and upon 15. So this can be written as one ratio stand up on 15 and this becomes 15, 10. And if we divide by then then but we get yes, we get one and this three by two and this is three short. So that means we have the formula that becomes out of the CR two or three. So this is the this is the identity of the compound, so the identity of compound based on the given analysis of chromium and oxygen is cr two or three.

Problems have one of chapter three chemical reactions of section two. The empirical and molecular formulas. So in discussion, what is the identity of the compound, I saw assume 100 g of sample And find the number of moles of each element. So we have given that the elemental analysis of the compound shows that it contains 68.43% chromium and 31.57% oxygen. So therefore the number of moles that chromium, that is a 68.4 Seagram chromium into one more chromium upon 52 g Chrome, and this 52 Graham is the mamas of chromium. So on solving this, we get 1.316 small scrawny, and similarly we can find the moles of oxygen. So that is uh 31.57 g oxygen into one more oxygen upon 16 g oxygen. So on solving week at 1.973 more oxygen. So I can write the mole ratio, that is chromium, a mole ratio, Malaysia of chromium and oxygen. That is uh 1.316 ratio 1.973. So as you can see this 1.973 value is close to two while one point 316 value is not close to anything. So we can divide each by 1.316. So on solving this we get one ratio 1.5 and this 1.5 can be written as 15x10. So if we multiply by 10 on both side we get 10 ratio 15. And if we divide by five on both sides, which we get two ratio tree on simplification, I get to reshoot so therefore the Formula. Or we can say the empirical formula of this compound or the identity of this compound that comes out to be cr two or 3. So hence we can write the identity of the compound, which is cr 203 So this is our final answer. An entity of the compound Cr 203

The chemical formula. Reputation per magnet is came in a few. The mullahs mass off each off the irons is here, which is key operation M n R magnus and all oxygen. The mamas off camera for can be calculated by adding the Mueller mask off position, which is wanna in here off magnets, which is my name and four times the mullahs Mass off oxygen, which is four ends here. During this calculation, we get the mullahs mask off position per magnet as 158.4 g per mole, 2.55 most off came in a four will be equal toe 2.55 multiplied by the conversion factor off one mole into grams off camera fault. We used the mamas off camera for here to convert into grams. This gives the final answer as faux 03 g off came in a full

Hello, everyone. I am going to solve this question. The question is right. The chemical formula. Reputation per magnate and then calculate the mass in grams off 2.55 model of the compound. So, firstly, the formula of reputation per magnet is K M N 04 Now we have to calculate the mass off 2.55 more For this we need the mask off. One more that is the molar mass of the compound. Somalo Mass can be calculated by adding the atomic masses off front elements. The different elements have following it off. Masters potassium 39.1 grand McNamee's 54 points 94 g an oxygen 16 grand. So Moeller mass off petition for magnet will be and the total value will come out to be 1 58.4 Graham. And this is for one mole. No. For two point 55 moles, the mosque will be calculated by multi point multiplying 2.55 with the border bus and the value will come out to be 403 grand. So we have both dancers now. The formula for petition per magnet is game enough all and the mass off 2.5 moles is 403 grand. Thank you


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