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Yuni experiment thc paths fromWannani thc sreen differ in length cning coxeInuctiy Irilcu ciclce 4L Illc poInG. Which puth diffcrence, wpuld cuilse thl e cxxhatnuct...

Question

Yuni experiment thc paths fromWannani thc sreen differ in length cning coxeInuctiy Irilcu ciclce 4L Illc poInG. Which puth diffcrence, wpuld cuilse thl e cxxhatnuctive intet(ciCice

Yuni experiment thc paths from Wannani thc sreen differ in length cning coxeInuctiy Irilcu ciclce 4L Illc poInG. Which puth diffcrence, wpuld cuilse thl e cxxhatnuctive intet(ciCice



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The clcctronic configurarions of four clemcnts arc givcn as undcr: (I) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{5}$ (II) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{4}$ (III) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{3}$ (IV) $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6 \mathrm{i}} 3 \mathrm{~s}^{2} 3 \mathrm{p}^{1}$ Which of rhe following arrangemcnts gives thc corrcct ordcr in rerms of increasing clectroncgariviry of the clcments? (a) $\mathrm{III}<\mathrm{II}<\mathrm{IV}<\mathrm{I}$ (b) $\mathrm{II}>\mathrm{III}>\mathrm{I}>\mathrm{TV}$ (c) $\mathrm{IV}<\mathrm{III}<\Pi<\mathrm{I}$ (d) $I<$ II $<I I I<\Pi V$

First of all, let's have a look at what all is given in the problem. It is given that The activity of tetra hydro Sinem beall, which contains 70% of hydrogen atoms. That means carbon atom is 70% of hydrogen atoms. And it has given that hydrogen items is 15 times of oxygen, atom. 15 times of oxygen atom. And it is also given that one g one g contains 0.00318 moles of tetra hydro Kaname Beall. So what we are supposed to find out her, we have to find the molecular formula of the compound. We have to find a molecular formula of the compound. So first of all, let the number of hydrogen atoms react. Let hydrogen atoms equals two X And oxygen atoms equals two wife. So according to the conditions given, we can say that number of carbon atoms is 70% of X 70% of X. And a number of hydrogen atoms is what according to the given conditions, number of hydrogen atom ish 15. My. So this will change to 70% of 15 by so now the number of carbon items will become number of carbon atoms will become 70 502, 15 by so it will be like seven by 10 into 15 by this will be the number of carbon items. No let's tabulate bees for carbon for hydrogen for oxygen atomic ratio is work atomic ratio for carbon, it is seven by 10 to 15. So 5 to 10, 5, threes of 15, it will come around 21 by two For hydrogen at this 15 for oxygen. It is one. Now simple atomic ratios will be 21 30 and two. So from here we can calculator empirical formula empirical formula will be C 21 H 30 or two. This is the m vertical formula. Now it's molecular formula will be its molecular formula will be 10 times of C21 age 30. and go to we can calculate the molar mass from here more landmarks of the compound that is And Times 21 and 2. 12. Flash 13 to 1 Plus 16. In total, this will be the molecular mass. So we will get approximately the Muhlemann z equals two. This will be the molar mass of the molecular formula given now we know that one g contains 0.00318 more. So one mole of compound will have how much we can calculators by cross multiplying So x equals to one and 2. x 0.0031. It This will come around 314.5 g. No, If we make considerate as one and this is to if we create both of these we will get N equals two. We will get approximately equal to 314 and plus 314.5. So we will get the value of an approximately equal to one. Does the molecular formula of the compound ish molecular formula of the compound is C 21 H 30 02. Hence the correct option is option number B, That is C- 21 H- 30 or two.

So we're looking for the probability that a subject tested positive or used marijuana. So that is going to be testing positive. Trust Me, these two. And then the ones that they did use marijuana would be those red ones as well as this. So that would be the probability of positive or um using marijuana. Mm hmm. So what that's gonna be is actually it's going to be this and that. So basically what we're going to have is 119 plus 24 Plus three. Those are gonna be our three they were taking together. Mm. And we're going to divide that by 300 for our total and 100 19 plus 24 plus 346. Divided by 300 48.66% or 0.487 oh

Try to look at this question. It is given that among 143 subjects with positive test results, So let over here, let this be positive people who are actually positive like this with people who are actually negative. And let this be the test side. So who have tested positive? And these are the people who have tested negative. All right, So it is given that among 143 subjects with positive test results with positive test results, which means that the some of this column is 1 43. Yeah, right. In this case, Okay. 24 are false. Positive results. 24 are false. Positive results. Which means this is 24. They're actually negative by the tested positive. So what is the remaining one? 43 minus 24. That it's 119 after that, Among 157 negative results. This is 1 57 among 1 57 negative results. There are three false negative results. There are three false negatives, false negatives. What is the meaning of false negatives? That means that they are actually positive, but they have tested negative. So this is three. This is 1 53. Okay. How many subjects are included in the study? How many? Some things are included in the study 300. How do I find this? The addition of these two 300 subjects are included in the study. What is the next question? The next one is how many subjects had two negative result. How many subjects to negative result 1 53 1 53. After that. What is the probability that a randomly selected subject had a true negative result? The probability that the randomly selected subject had a true negative result. It will be 1 53 upon 300 1 53 divided by 300. Now, what is going to be the answer? In this case, we need to use a calculator. And so just give me a moment. This is turning out to be 0.513 By the way, what we're doing wrong is 1 57 minus three is 1 54. So this is 1 54. So this answer is 1 54. This answer is 1 54 and hence this is also 1 54. Now, let's try to calculate this 1. 54.300 0.513 This answer is zero point 513 These are my ancestors. Thats all I needed, right? Yeah, these are my answers.

This time, I want to find the probability off the subject either testing positive or not using marijuana. So subject testing positive is 1 43 by 300 1. 43 by 300 by 300 or or means addition. Not using marijuana, which is the addition of these two 24 plus 1. 54 is 1 78 by 300. Is that Is there something common? Yes. This is the intersection part minus 24 by 300. So what does this turn out to be? This turns out to be 0.99 So this is the probability that I want 0.99


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