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Pina tho Maclurin sarles tor H{*) uslng the definltion K) In(1 2Hacitunn scries [Astume Iha: / has DomeEidansOnHonRa(*)FlndEsdociatdo Indiuaconvecoence...

Question

Pina tho Maclurin sarles tor H{*) uslng the definltion K) In(1 2Hacitunn scries [Astume Iha: / has DomeEidansOnHonRa(*)FlndEsdociatdo Indiuaconvecoence

Pina tho Maclurin sarles tor H{*) uslng the definltion K) In(1 2 Hacitunn scries [Astume Iha: / has Dome EidansOn Hon Ra(*) Flnd Esdociatdo Indiua convecoence



Answers

The sccond ionizarion cncrgics of the $\mathrm{C}, \mathrm{N}, \mathrm{O}$ and $\mathrm{F}$ aroms are such rhar (a) $\mathrm{C}>>\mathrm{N}>\mathrm{F}>\mathrm{C}$ (b) $\mathrm{F}>\mathrm{O}>\mathrm{N}>\mathrm{C}$ (c) $C>\mathrm{O}>\mathrm{N}>\mathrm{T}$ (d) $\mathrm{O}>\mathrm{F}>\mathrm{N}>\mathrm{C}$

This is the A. C. T. Practice test five problem 44 we have answer choices, F G H and J. And the our goal is to look at the underlying selection. Well, we have verbs in the sentence in this underlined section and something we need to consider is the correct form of the verb. We need to correct look for a tense and form. Well, it seems like our main focus of this question is the verb form. The sentence can have multiple verbs and still be a fragment because an I N G ver by itself can never be the main verb in the sentence. So we need a helping verb. But as written, the sentence doesn't have one. So it is a fragment. We'll eliminate answer choice, F, choice, G and H. Do not address the air. The only one to do so is J, jay is correct by giving because it gives the sentence a correct main verb or predicate verb, which makes the sentence complete.

And so for the given question, we have a session, given position is Gcl too and SNCf to exist together in equal solution. The reason for this, Given ization is on heating GCS to supply times. So here we have the correct option for the given statement is the option D exertion is falls, but the reason is two. So here we will write the correct assertion for the given reason. So correct position is Gcl too, and SNC and two cannot exists cannot exist together in a glass solution. And the reason is here on heating. Yeah, Gcl too. Sublime songs. So here is false and but are is true. So the correct position is GCL to end. SNC cannot exist together in a solution.

In this problem, the reaction will happen. Something like this. R. C. People won't see our in presence of Ash, too. And then the large cat based it will produce. It will produce the product ID and she double won't see uh, AT AT as the product according to the option option, a correct answer option. It's correct answer for this problem. I hope you understand the solution.

This is the answer to Chapter twelve, number fifty eight from the Smith Organic Chemistry textbook. And so, in this problem, we are asked to figure out the structure of molecule a molecule called Die sido patera nor Dice site Top Teran D Prime. Sometime calling indeed, just for for ease, of writing it. So I don't have to rewrite this word several times on DSO. The first piece of information that we're given is that treatment of D with hydrogen gas and palladium gives us this skeletal structure here, Uh, that I've, uh Let's circle it so that I'm circling in red right now. And so we know that this has to be the basic skeleton of this molecule. So it's ah, seven member dring on then a beetle group branching off the rain. The next piece of information that we're given eyes that owes analysis of the with ozone followed by diamond sulfide, gives us thes three pieces. And so Ah, this is actually all the information that we need and all that we need to do now is figure out how to assemble this molecule so that we fulfill this skeleton that we've been given, um, and That's pretty much it. So as we've done before, Uh, we just sort of connect a Carbondale Carbon Teo Carbonell carbon. That wasn't so good. So let's let's try this. So you just kind of connects carbon. You'll carbon to carbon carbon on anything. Do that over here. And if you want to count your carbons One, two, three here for five, six and seven And so that's going to make our seven member dring, which is great, Andi. We will have to double bonds in it on then. We can also connect this piece to this piece thes two carbon eels on the once count here will be one, two, three, four There's our beautiful group on, so we'LL have a double bond in there as well. So, over here to the right, I've drawn the two possibilities for D. I'm. So if seven member dring with our two double bonds in the correct positions that we got from assembling these pieces that we were given from the O's analysis on then are our beautiful group has double bond in it as well. Andi, we actually cannot tell just from this information that we've been given whether it's assists or a trans Al Keenan in this. Ah, in the beautiful side chain here. Um, and so the answer is is either or, um so this skeleton is definitely right on. The only thing we can't really determine is the stereo chemistry around this Al Keenan, the side chain on that is number fifty eight.


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