5

(a) Write down the expression for the height of a projectilemotion. (b) Suppose a ball is throwntoward a target 22 m away at a speed of 25.0 m/s and at angle 40degr...

Question

(a) Write down the expression for the height of a projectilemotion. (b) Suppose a ball is throwntoward a target 22 m away at a speed of 25.0 m/s and at angle 40degree with the horizontal. (i)How far above the release point does the ball hit the target? (ii)What are the horizontal andvertical components of its velocity as it hits the target? (iii)When it hits, has it passed thehighest point on its trajectory?complete as soon as possible

(a) Write down the expression for the height of a projectile motion. (b) Suppose a ball is thrown toward a target 22 m away at a speed of 25.0 m/s and at angle 40 degree with the horizontal. (i) How far above the release point does the ball hit the target? (ii) What are the horizontal and vertical components of its velocity as it hits the target? (iii) When it hits, has it passed the highest point on its trajectory? complete as soon as possible



Answers

You Throw a Ball You throw a ball toward a wall with a speed of $25.0 \mathrm{~m} / \mathrm{s}$ and at an angle of $40.0^{\circ}$ above the horizontal (Fig. $5-33$ ). The wall is $22.0 \mathrm{~m}$ from the release point of the ball. (a) How far above the release point does the ball hit the wall? (b) What are the horizontal and vertical components of its velocity as it hits the wall? (c) When it hits, has it passed the highest point on its trajectory?

This is chapter for problem number 50 way have a projectile and two and two equals seconds. T equals two seconds. The range that the horizontal displacement undergoes these 40 meters and the hype that it reaches is 53 meters. So important favor asked the X component of the initial velocity of your circumstances. So since there is no exploration in the extraction, the range travel this kind of equal to be not x times time that it takes to reach that works on time displacement. So it's pretty straightforward here that we divide both sides by time. Getting the ex proponent of the initial velocity as our over time are being 40 meters of timing. Two seconds we find the ex comported velocity to be 20 meters per second being part Beaver asked the initial well lost this white compliment this time. So in order to do that, we're gonna take advantage of what's given to us. Develop Hawaii is given into being not why Times t minus 1/2 g t square delta y being our each year that's given to us is 53 meters. So then I'm gonna solve this equation. Corvino. Why? So we know way times time equals H plus 1/2 gt squared. If I do by both sides by tea, break one of tea then I'm gonna get Vina. What do we know? Why equals each being 53 meters plus 1/2 9.8 meters per second squared times time that that is toasters. Two seconds squared. Big brackets won over two seconds. From here, we find a white component to the 36.3 meters per second. Now. Important. See, um we asked what the new R is. What is the distance? Travel will result Feli when the particle, when the projectile or textile is at maximum height. So we need to calculate the time that it takes to reach the maximum height for this purpose. Protect. How are we gonna do with the simplest way is you know, when we're at the top of the projectile, the loss It is purely in the extraction. So they're being final. Why Hester v equals does he read to top? So then the final why is you know, we used to be initial y minus g times t did it take attended it takes to reach the top. Um is given my this equation that's the final component wife upon is zero. So the not why equals G time, Steve, about both sides gravitation, inspiration. And now you know the time that it takes red we not. Why From part native, calculated to be 36.3 meters per second, divided by 9.8 meters per second squared, we have 3.7 seconds. So it takes his project. Alice, which is an excellent frequent seven seconds now. But we're asked the distance traveled with then this time. Right? So it's not X component times time to get there. So it's gonna be We have calculated the ex composed of initial velocity to 20 meters per second times to meet 17 seconds, so we get 74 meters.

Okay, we have a projectile fired at a 30° angle at a speed of 520. Now we're asked quite a few questions about that scenario, but first let's remember some of our formulas. So remember your co sign component is going to be in your eye direction for velocity and your sign component will be in your J. You also have gravity. So as you have a positive velocity going up, gravity is pulling you down. Now for position you consider that those velocities need to be multiplied by time. You've also integrated your velocity, so you end up with a one half G T squared and then if you also have a initial position, you would also have that in the in the vector. Now there's also equation for range, it's visa, not squared times assign a tooth data all over G. So our first question asked us about range. So fortunately we do have this range formula that we can use and so we'll be putting in our 520 and squaring it And multiplying by the sign of two times are 30° angle, all divided by gravity of 9.8. So when we multiply that out we get 23,895 and that would be meters. Okay? So now the next question is about the time of flight. Well so this range is also um you know that was if we didn't have t we use that value but we have another equation that tells us how far we've moved in the I. Direction and thats rvs of not cosign theta times T. So we can use our 5 20 times the co sign of 30 times T. Will equal that 23,895. This allows us to solve I. T. By dividing both sides by that 520 co sign of 30. So we end up with a range time of five or 53.06 seconds. So if you consider that, that's how long it took for the whole time of flight. If we're going to find the greatest height reached, um we do have a symmetric parabola and so at half the time we can find our height. So if we take that 63.06 and divided by two we can put that time into our position vector. And when we do that you can see that. We also have to then subtract our acceleration component times at times squared and we get a maximum height of 3449 m.

The given question is accessing quotes to be no toe the advice because to be north Ruto B minus 16 T square we'll be notice given us 400 feet per second in the motion It is giving the president honest thrown head a attending for different bigly. So from the information we can conclude these are questions So many in a part We need to find the timing then near Esten valid here to step down. So if it hits the ground we know that this part must be zero This value must 30 because it will start at zero and with zero So we can say like this the graph local like this from here it will start and from here it will end. So if you see then by value here in zero. So if this is zero people get we know why two times t minus 16 80 square is equal to zero We not value is 400 Let's take one tea common that we will get for trade route Dubai to minus 16 The quotes 201 Cancer We will get Daisy Question zero debt indicates this position the other position We will get then sick. This this d there because And it becomes zero. So we will get 400 group toe by toe minus 16 d is a quote stoop zero that will give us b is equal stole toe red rule toe by 16 or tea is Cuba unwto approximately close to 17.7 2nd in second part. They are asking for the range this range. So go find that this strange. We can substitute this value off, be in this in question. Then we will get range is in questo X is equal stow. We know Roto two times t and that will be equals to be not the new 400. I don't know why do and duty at 17.7, that value comes out, do we? 5000 feet for the sea part. They are asking the value high. Yes, every do this will do to find this value. We know there at the highest. Only knew the time will be half so we can substitute their value in this equation half off key and get the answer. So let's do it here. So why is it wants to We know when you 400. So I go t is 17.7, developed by two minus 16 into 17.7. Divided by holy square. If you can clear, this will comes out to be 50 feet. So this is the solution.

This is chapter for problem. Number 112. 22 on. We have a project down motion. The initial speed is given to us is 12 meters per second. And then when the, uh at the top wouldn't be velocity is purely and horizontal direction, it hits a target. This wall hits a target that is age equals five meters above the ground and were asked this angle initial launch angle in part A in order to find that, let's use that information that's use the fact that if a final of why equals b initial, why squared minus two g h can This term is here at the top, right? There is no a why component of the loss of either so the not why squared equals to G h. Um, from there, uh, be not why it is, you know, you can see from here being milked by actually cools to Oh, be not signed, Peter. Right? So do you not find it elsewhere? Then left inside me that signed data squared equals two J to G H and sign spirit A close to your age Shoulders squared, um, thrown their science data equals the root of T h over Reno squared from here. Um, by plugging in the values for H, which is five meters g. Let me just plug in the bellies right on the next speech then so sign data equals square root off two times life coming years for seconds for five meters. Deal. I did fine. 12 Minister second squared. We have a plug in the numbers. Data comes out to be a piece of glass from 60 greets. So in part, we were asked the range dub. This place is in the extraction. So our equals B not x times, times, you know, Athena ex being be enough time to find a tough time. Steve, there's no acceleration of the extraction. However, we don't know what t is here, So let's go back to the white component of velocity and figure that out. Right at the top again. Final opponent off. What vehicle pointed in the final lots of zero. Then be not. Why equals G time, Steve. We divide both sides by g forgetting the time being at why gaining enough sign data over 50 so we can plug this in the range equation rage equation because he knocked bull side they had at times for you. Last time stayed out over G b enough being 12 meters per second. But we have to in terms of her taking a squared consigned 55 or six times. Uh, this was all this. Is it art me? Um sign 55.6, divided by on unemployment meters per second squared R is gonna be found from here. Eyes asked. Explain The five meters in Farsi were asked the speed final speed as it reaches to target. So the final speed is you as we discussed before equals to be initial component X component of the velocity because there is no exploration that particular direction in next direction. So we now call sign Pita. It's simply going to give us the final velocity. So being that these 12 meters per second time's full sign out 55.6 degrees is gonna give us 6.78 meters per second


Similar Solved Questions

5 answers
5 . Use Leibniz's rule to find L(tsin(bt)) for 8 > 0_
5 . Use Leibniz's rule to find L(tsin(bt)) for 8 > 0_...
5 answers
Write the equilibrium equation and the Kap expression for each of the following: Ba(CzH;OzhzAlz(SOa)s
Write the equilibrium equation and the Kap expression for each of the following: Ba(CzH;Ozhz Alz(SOa)s...
5 answers
000 'IV 0 { I 00 W 9 I 1 V 1 HH H H # } ] 1 1 L E [ 1 1 1 X M 1 1 1 1 E W 1 1 ' 1 ; 1 1 H HJ 1 N 1 1
000 'IV 0 { I 00 W 9 I 1 V 1 HH H H # } ] 1 1 L E [ 1 1 1 X M 1 1 1 1 E W 1 1 ' 1 ; 1 1 H HJ 1 N 1 1...
4 answers
ProblemsUsing a visual representation (picture, chart, Or other) to solve the problem on the leftCreating real-world Solve the problem using situation for the given rules procedures or problem on the left strategiesDivide: 1.2 + 0.24
Problems Using a visual representation (picture, chart, Or other) to solve the problem on the left Creating real-world Solve the problem using situation for the given rules procedures or problem on the left strategies Divide: 1.2 + 0.24...
5 answers
Find the mass of a thin plate occupying the smaller region cut from the ellipse x2 + 4y2 =12 by the parabola x = 4y2 if the density of the plate at the point (x,y) is given by p(x,y) = Sx.
Find the mass of a thin plate occupying the smaller region cut from the ellipse x2 + 4y2 =12 by the parabola x = 4y2 if the density of the plate at the point (x,y) is given by p(x,y) = Sx....
5 answers
Whal Iho crankshaft's angular acceleration at t = 5 87 Express your answer to two signlilcant ligures and Inciude the appropriate units.ValueUnitsSubmilRcqucst Answcr
Whal Iho crankshaft's angular acceleration at t = 5 87 Express your answer to two signlilcant ligures and Inciude the appropriate units. Value Units Submil Rcqucst Answcr...
5 answers
The quantity of charge Q in coulombs (C) that has passed through point in wire up to time (measured in seconds) is given by Q(t) 2_ 2t2 + St [See this example_ The unit of current is an ampere A = 1 C/s;]Find the current when0.2Find the current when t = 1At what time is the current the lowest?
The quantity of charge Q in coulombs (C) that has passed through point in wire up to time (measured in seconds) is given by Q(t) 2_ 2t2 + St [See this example_ The unit of current is an ampere A = 1 C/s;] Find the current when 0.2 Find the current when t = 1 At what time is the current the lowest?...
5 answers
6,The mean "f 60 0 mele students '5 75kg. and waghta,_ the stundart tion 6' = 10 kg 1) How many students ess thxln 6kg; 8o min. Itnve & successfull exam ")Ho w many' 5 tudets mcre ~hion thdn 84 ka
6,The mean "f 60 0 mele students '5 75kg. and waghta,_ the stundart tion 6' = 10 kg 1) How many students ess thxln 6kg; 8o min. Itnve & successfull exam ")Ho w many' 5 tudets mcre ~hion thdn 84 ka...
5 answers
A) Calculate the moles of anhydrous salt formed after the dehydration The molecular weight of the anhydrous salt is 437.20 g/mol. b) From the weight of water lost during the dehydration, calculate the moles of water lost The molecular weight of water is 18.02 g/mol.
a) Calculate the moles of anhydrous salt formed after the dehydration The molecular weight of the anhydrous salt is 437.20 g/mol. b) From the weight of water lost during the dehydration, calculate the moles of water lost The molecular weight of water is 18.02 g/mol....
5 answers
Evaluate each of the following iterated integrals by reversing the order of integration (a) ( (sin> 'Z-dydx (c) J $ atevnvi->-ydydx (b) J $cos- dx dy (d) $ dydx (x+y)2,1+y2
Evaluate each of the following iterated integrals by reversing the order of integration (a) ( (sin> 'Z-dydx (c) J $ atevnvi->-ydydx (b) J $cos- dx dy (d) $ dydx (x+y)2,1+y2...
1 answers
Find the first term and the common difference. Find the 12 th term of the arithmetic sequence $2,6,10, \dots$
Find the first term and the common difference. Find the 12 th term of the arithmetic sequence $2,6,10, \dots$...
5 answers
Point)Find a vector n normal to the plane with the equation 4x + 2y + 2z = -5.n = (4,
point) Find a vector n normal to the plane with the equation 4x + 2y + 2z = -5. n = (4,...
5 answers
72% of the students in Faculty of Economics and AdministrativeSciences are females.a) What is the probability that the sampleproportion of a sample of 30 students will be within 0.67and0.77?b) Visualize the problem using the function“area_under_normal.R” and validate your answer in part“a” usingR.c) Using the relevant “predefined function”, crosscheck youranswers using your answer in parts a and b
72% of the students in Faculty of Economics and Administrative Sciences are females.a) What is the probability that the sample proportion of a sample of 30 students will be within 0.67 and0.77?b) Visualize the problem using the function “area_under_normal.R” and validate your answer in p...
5 answers
Unknown amount of oxygen gas is mixed with 2.00 g 0f SOz at container; The total pressure of the mixture was tound to be 706 torr:C in an 800.sealed gasQuestion 10 (2 points) Calculate the mass of oxygen gas in the mixture in (grams)Question 11 (1 point) Calculate the partial pressure of oxygen gas (in torr)Question 12 (1 point) Calculate the mole fraction of SOz gas in the mixture:
unknown amount of oxygen gas is mixed with 2.00 g 0f SOz at container; The total pressure of the mixture was tound to be 706 torr: C in an 800. sealed gas Question 10 (2 points) Calculate the mass of oxygen gas in the mixture in (grams) Question 11 (1 point) Calculate the partial pressure of oxygen ...
5 answers
Describe the above distributionUniformRight skewedBlmodalNormalLeft skewed
Describe the above distribution Uniform Right skewed Blmodal Normal Left skewed...
5 answers
E for A H M get: the for hertwa Please tryl pue H shown Holweverh eThere oretfel four resonance and three
E for A H M get: the for hertwa Please tryl pue H shown Holweverh eThere oretfel four resonance and three...
5 answers
QUESTION 93,5 pointsDetermine the (X,v) coordinates of all points at which the graph the function f(x) =x? 3x + 12 has horizontal tangent line:A (- 3,0) and (3,0) (- 1,0) ad (1,0) (0,12)(-3, 6) and (3,30)OE ( - 1,14) and (1,10)
QUESTION 9 3,5 points Determine the (X,v) coordinates of all points at which the graph the function f(x) =x? 3x + 12 has horizontal tangent line: A (- 3,0) and (3,0) (- 1,0) ad (1,0) (0,12) (-3, 6) and (3,30) OE ( - 1,14) and (1,10)...
5 answers
6. Average employee satisfaction per number of hours scheduled per week is modeled by the function S(r) = 1.4(0.00522 + 2)(0.082 What is the optimal number of hours to schedule each employee for maximum enthusiasm?
6. Average employee satisfaction per number of hours scheduled per week is modeled by the function S(r) = 1.4(0.00522 + 2)(0.082 What is the optimal number of hours to schedule each employee for maximum enthusiasm?...

-- 0.020135--