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Solve: 4) A pulsed electric voltage that is offset by dc component of 3V is defined by 0<t<14 V(t) = 143t<28 28 =t < 42 where is time (in As). Find &...

Question

Solve: 4) A pulsed electric voltage that is offset by dc component of 3V is defined by 0<t<14 V(t) = 143t<28 28 =t < 42 where is time (in As). Find &0 (if it is not zero) two nonzero cosine terms (if they exist), and nonzero sine terms (if they exist) of the Fourier series for the time-dependent voltage_ A) 8 COS 2 cos: 2ut B) J0 4+ cos [ - Ncos 2t + ',-4+. cos 3-+_ cOS ZuL 21 D) J0 4+ cOS 4-+ cOS 2 3

Solve: 4) A pulsed electric voltage that is offset by dc component of 3V is defined by 0<t<14 V(t) = 143t<28 28 =t < 42 where is time (in As). Find &0 (if it is not zero) two nonzero cosine terms (if they exist), and nonzero sine terms (if they exist) of the Fourier series for the time-dependent voltage_ A) 8 COS 2 cos: 2ut B) J0 4+ cos [ - Ncos 2t + ',-4+. cos 3-+_ cOS ZuL 21 D) J0 4+ cOS 4-+ cOS 2 3



Answers

For another electrical circuit, the voltage $E$ is modeled by $$E=3.8 \cos 40 \pi t$$ where $t$ is time measured in seconds. (a) Find the amplitude and the period. (b) Find the frequency. See Exercise $51(b)$ (c) Find $E$ when $t=.02, .04, .08, .12, .14$ (d) Graph one period of $E$

So we're going to have a similar problem as before. But more importantly, we want to look at a different function. So that function is going to be 3.8 co sign. Okay, 40 piping. Um, and we see that if this were to get zoomed out a little bit more So let's say we didn't negative one. The one we see it. This repeats very quickly over a very short amount of time. Um, then we're gonna want to restrict this to bring about negative 5 to 5. We get a better view of what a graph looks like. Eso with this. We want to determine the amplitude in the period. It's clear that the amplitude will be 3.8 and then the period is gonna be two pi over B. But in this case, RB is 40 pie. So we see that our period as 400.5 or 1/20. This means that our, um, our the number of cycles that we go through will be 20. There will be 20 cycles because each period is 1/20 of, um, each cycle is 1/20 of a second, so we'll have 20 cycles in a second and then we want to plug in. Some different values will plug in f of zero. Then we'll plug in after a zero point 02 That's why we get them 04 We get that value amend 08 zero. I will do 10, 12 and 14. So we see it. We keep getting a lot of the same values going back and forth. And then lastly, we want to graph one period of E. That means we're going to graph it from zero toe 1/20 Onda. When we do this, we will see that we get exactly one period of our graph.

Um so it says the voltage e in volts in an electrical current current is given by the function, and the function is given to us. So capital E is equal to 20 times co sign of pi times teeth were t is time in seconds and we're going to go through all six pieces of this problem and answer these questions the 1st 4 parts of this problem. So eight rue de it will require us to look at a graph to look at the characteristics of our graph and be able to use those to answer these questions. So to do that, I'm going to go to Desmond's and I'm going to start graphing here. Does most is a great graphing tool. It allows you to do so many different things. Um, but number one of all is being able to see your graph and be able to pinpoint specific parts of your curves and able to study what that means to this scenario that you're given. So we're going to start by typing this in here. You can click, she'll keep out here, and everything will come up in reference to variables. Um, your grated in less than signs your absolute value and your functions here. So we want to select a coastline function because that's what we're using so co sign of pie Now, usually in any problem that we work with in mathematics, where we're dealing with Bruel scenarios and graphs, your X axis represent your time. Whether time is in seconds, minutes, hours, days, years it is usually represented by the variable X. So instead of putting t in here, we're gonna put I'm gonna put eggs and we'll look at that grass and I'm going to close parentheses. And as you can see, the 20 that is in front of our function here is stretching on our graph. It's tricking it out, and it's giving us a range of negative 22 positive 20 on our Y axis. So that is one thing we need to keep in mind. We also need to keep in mind that for part A, we are graphing this equation, but they tell us a specific interval we need to grab on. So let's make those changes here, right? So once again, X and t are going to be inter changed. Throughout this problem, we're gonna go to settings. And I know now that my ex values need to be represented between zero and two on our graph and then our why access which is going to be our range is represented from negative 20 to positive 20 because of that coefficient in front of our Trigana metric function in our equation. So you also want to make sure that you have everything set up in radiance does most will usually already set up everything in radiance. But just to be sure, you always want to check back in the graphing settings of here and see if everything is correct. So once you do that, you can come out of that screen. Now you see the curve way better than we did before. We can still do a little bit of tweaking to make sure we see everything we need to see. So I'm going to zoom out by pressing this minus sign. It's you zoom out and now you see your curve from X equals zero X equals two. So the 1st 2 seconds of our electrical I'm circuit, we see the occur for that. So that's part eight. We have a good graph, but part eight now awful part be here. What is the voltage off the electrical circuit when t is equal to one? Remember and tell Do T and X are going to be interchangeable? So what we're gonna do is we're gonna go to X on our graph X equals to one, and then we're going to follow it down to our curves. And as you can see where X is equal to one on our curve, our vaulted would be negative. 20. Now, the same thing will happen in our equation here, right? If I put it in one hair for X. All right, which is where T would be. When you simplify this, you'll get co sign times, pi or co sign of pilots. Just meaning that time. Fine. Co Sign up. I will be negative one and then negative. One times 20 would be negative. 20 right. So we would get the same exact answers whether or not you used a graph or you use the one as an input and got an output of negative 20. All right, so that's what part be now for part C and D, they kind of go hand in hand, so just follow along. Pay attention to what I'm going to do now, right? So when we graft this, we also have these little boxes in between is also us to figure out what these boxes represent. You can set them from the graph setting the pair, but I think the graph itself did a pretty good job. Right, So we have that each box on the Y axis is worth two units. So we have 2468 10 12 units up. And this is the line that's going to represent the 12 volt output that we want to study. So if you go from zero on our X axis here, so zero and you follow this 12 straight across, you'll hit the curve one time here and you'll hit it again. We're here, even though you can see that the lines cross so that should be answered for C. The answer for C would be that the why equals 12. The voltage of 12 happens to times within the 1st 2 seconds about a circuit. Now we want for party to get more specific specific numbers. So in order to do that to get the specific numbers the best way I know how would be to put y equals 12 here and graft that holds onto line so that you get the pinpoint off where these curves cross each other, right where that line crosses to curve. So you have here the first time we're at a voltage of 12. Your time it's 0.295 seconds. And in our problem, they want us to round two the nervous hundreds place. So when we around this, we get 0.30 seconds, right? So I was there a 0.3 seconds We see the first time our voltage, which is to 12 and then the second time a voltage reached 12. In our interval, we have a time of 1.705 seconds. And when we round that to the nearest hundreds, you get 1.71 2nd So that was kind of part C and B. Together we have two intersections on our curve in which the voltages 12 in between the intervals of 0 to 2. And then we pinpointed the exact volumes by typing and why equals to 12 creating hours onto line and getting our exact point of interception. Okay, so Now we've completed parts A, B, C and D of having 29 in this section. And we are moving on to part one and part two of the last two parts of this question, and it requires us to use a whiteboard. So here we are, in part one. They want us to make sure we let Fada equal high equals pi times T Yes. So data is equal to pi times t So that's something that they want us to keep in mind while we go through these latte last two pieces and we want to enough First part solved the equation that they've given to us. So the equation is 20. Call sign saver equals 12 right? So we want to look at this as doing inverse operations, just like we would do with any other function. Any other equation that we've been given right. We want to make sure that I would Trick function is isolated, and the way we do that is to move that 20 to the opposite side by dividing. All right, whatever you do, the one side due to the next side or the other side these twenties, cancel and then you'll get coasts on. Data is equal to 12/20. Okay, Once you have this set up, you can look at this and say I'm looking for angles. I know. I'm going to use the inverse of the function. Give it so I'm looking for Fada. They does our angle. And I need to use the inverse. Of course. Science. I'm going to rewrite this as an inverse function before even put it in my country, Their ego. So now we have the embers of coal sign. We have our ratio. And then we have no that. Once we do this in the calculator that we are going to do this to get an angle in our anguish be fatal. So when you put the CIA calculator, there is one thing you need to remember. You need to remember that you're using radiance. So whatever scientific calculator you're using, whatever calculated that you're using, that's allowing you to use trig functions and do operation with trig functions. What? To make sure you're using it in radio. When you do the work for this, you're going to get 0.93 equals to fade up. I'm gonna put a one hair and I'm gonna explain why I put that one there. Okay, so I put this one hair because we need to make sure that we're accounting for all of the possible data that can result in this problem. The one thing that we need to go back and look at is our original ratio off 12/20. So we're gonna look at this, and we need to look at whether that ratio is positive or negative. So in our case, this is going to be positive, right? Possibly shoot. And now we need to account for all of the quadrants in which coal sign would be positive. Ok, so we do this. All of us have a different way of remembering this, right? The way I remember it is all students take can't give us right where they represents. All trick functions are positive in the first quadrant, Sinus positive in the second. Tension is positive in the third and cold Sinus positive in the fourth. So we have our data sub one, representing the first progeny it. And now we need to find out data. So four representing the angle Andy, fourth quadrant asked him to be positive for Colson function. Right? So the way we're going to do this is we're going to take this original data off 0.93 and we're going to subtract that from our reference angle in the fourth quadrant. What should be true pie? Right. So you gonna do to pie minus 0.93? And when you do that, you'll get five 0.35. Rights in 5.35 is going to be on Seda some four, which is representing the data and the fourth quadrant, in which coal Sign is positive. Okay, so now we're gonna write our solution set. So we have a bracket. Wait. 93 comma. Five points eyes. Right. So also in your book, they have a notation. And what you add a to high end where end has to be an integer. Right. Um, we do that formal notation to indicate the modern rotations that can possibly occur for our purpose of this problem. We do not have to include it because we know these are the two measurements that we're gonna be working with. And we already know our interval and out of rotations. Right? We know our interval is going to be zero to two pi that we're dealing with. So we don't necessarily have to worry about the rotation of possible rotations, But it is good etiquette. Mathematics advocate to write that in there. Um, so we're gonna focus on these two numbers here, and I'm gonna change colors so that we understand what needs to happen. That's so I'm gonna make this ready. Here. Here. So remember at the beginning, right? We were working with the fact that we are now indicating that stato is equal to pi Times T this is going to bring us into part two. And the last part of this question we have to date is here. So now we have to do some substitution in order to find our t for time. So what I'm gonna do is we have a fate off 0.93 here. I'm gonna do data equals hi terms, T. And I'm going to substitute my fatal one year. So my data oneness 10.93 just equal to pi times t. And then I'm gonna do basic inverse operations. You know? I want to move high to the opposite side. They isolate the tea soft at the time. And once I do that, I get tea is equal to point to knowing five. And when we around that to the neighbor's 100. So let's say we keep with the hundreds as we did in earlier parts of the problem. We end up getting tea. It's equal to 123 Okay, and then once again, we're gonna do another substitution without 5.35 So five want 35 is equal to high. Some see, we divide both sides by the Bible sides, parts canceled, and then you end up with tea equals two 1.7 city, which is also 1.7, right. So these are two times in reference to the data's that we received in the first quarter. We use it Data's from the first part to get the times that were asked of us in the second part. So I will finally answers would be 0.3 karma. 1.7 calls the bracket, and this is representing two did two points in time where the voltage is 12

Okay, so this is problem 29 in chapter 13 Section one. And in this problem, we're pretty much studying a Trigana metric equation that's given to us in reference to voltage as an output and time and seconds as the input. So the first thing that we're going to do is we're going to create the grass to match this trigger metric function, and we're going to use decimals to do it. So there are six parts to this question, and the 1st 4 ports kind of require us to look at the graph. So let's get started with the graph. So our function is going to be 20 and then we're going to click show keyboard. And here's all the function that you can use within decimals to have your variables. You have your symbols, you have pie there, which were brought to use in a second. And we're gonna use costar in for that. Our trick function Better put pie. And now any time we're dealing with time on a graph and reference to real world scenarios and situations, it's usually represented by the ex access So wriggle room to put X hair instead of the T we're going to keep Inter changing X and T throughout this problem. And look at the grass. This is amazing, but we can't see everything, right? So we need to keep in mind that we also have to set our intervals. So if apart, a they want us to set our intervals or the X axis, we want our T, which is our X axis, to be in between zero and to right. And we know that this 20 in the front of our trick function hair stretches our graph. So that's why it looks like, you know, a graph is expanding, um, vertically. But in actuality, now we have a very large range. So our range is going to be from negative 20 to positive 20. So we put pies of 20 here, and once again, we're working ingredients. So we want to make sure that when we're graphing, we're doing our calculations. Today everything is in radiant, so we're in radiance were in good standings. At this point, we can click up the screen. Now, this is clearly way better looking than the previous graph. We can make this look a little better. Let's kind of alter this a little bit. So I'm going to zoom out by pressing this subtraction sign and sometimes a lot, a lot of it. And now we have a really good look at out grab. So this is what we needed to do for part a of our problem. Part of our problems said we needed to grab our function. Trick function. Um, keeping in mind that we wanted to show the interval or study the interval from X equals zero X equals two. So the neck. So now, for part B, we are going to show what is our output for our voltage when our X is equal to one. So when our X, which is our time I r t is equal to one X and T, we're going to change it right When our X is equal to one, we go down until we meet our curve and we meet our curve at Why are voltage equals to negative 20. So when we're doing this, you can use the graph to do this, which is the easier way, right, because you can just follow the curve and see what our output would be. But you can also do the substitution method, which is to take this 15 x substituted in to our function here. Right, So co sign off pi times. One would just be cool. Sign off by co Sign of pie works out to be negative one and the negative one times 20 would get us to that negative 20 which is the same as our graph shows here. She could do it either way. Now, for parts C and part D, they kind of go hand in hand, right. Once you figure out part D automatically figured out parts C and part C is a part of our d. So let's go into that now. Now, each one of these boxes represents a number of units that we are operating on just like any graph that we've done before And are y axis hair is going by twos. So 2468 10 12 12 was our magic number because in part C, they're asking us how many times in our interval of between zero to do we reach a voltage of 12. So what you're gonna do is you're going to simply just ride out that why equals 12 vertical line. See how many times he hits are curve So his crib once here and then I continue to go and I go and I go and I go and I go on a hits again. Ah, hit our curve here. Who's still out of water? Depth of 12? We're still in between zur into on our X axis for our time and the hits for the second time there. So the answer for part C would be two times now when I want to get more specific as in finding the answers for Part D. I want to create the line. Why equals 12 and I do this because I want to see in greater detail more specifically exactly what is the time when my voltage is going to be equal to 12. So the first time I bolted just equal to 12 the time is 0.295 right, and going back to the problem, we need to make sure that we're also rounding to the correct place while you and they want us to round to the nearest hundreds. So, for us swimming around this 0.295 we want to make sure we round that and it becomes 0.3. You know, Um and then that is the first time out voltages 12 the second time out. Voltage is 12 right? Cause that's everywhere that this blue line will hit our curve between zero and two on the x axis. We want to make sure that we're rounding this correctly as well. So we have a time of 1.705 and we want around that number to the nearest 100th place. So now we have a time of 1.71 seconds when our voltage is 12 for the second time, so you can use this graph to look at other characteristics. We've already used this graph to answer parts eighth, indeed. And I'm going to move to the white boards, end toe, answer the last remaining parts of this question. Okay, so now we're at part one and were at the white board, and we're gonna work through some of this now algebraic lee and in part, one of the two parts. Towards the end of this question, they're telling us one thing, and then they're asking is one thing. So they're telling us we need to let the Fada Fada be equal to pi times t And that's gonna be important throughout the solving process for the next two pieces of this question. And then they're asking us to solve this trigger equation that they've given us. So it's 20 coal sign data equals to 12 right? And there's 12 once again, is representing some type of output. But we're gonna work with this now. I'll go at this point in the problem is to get the trick function by itself so that we can revert back to trig identities that we know right and rewriting the trigger identities as we know them. So the first thing I'm gonna do is to fired both sides by 20. And in doing this I am making sure that I am isolating district function of coal sign and I'm moving that coefficient of 20 to the opposite side. So now I have coal sign, say, though is equal to 12/20. Now I'm going to leave. This ratio do weight is. But I do want to know any time that you're looking for a fade up, any time you're looking for an angle inside of a trick function, you know that you're using your inverse trick function, so I'm gonna be right. Cool. Sign to the negative First power. It is more power. Um, which is deceiving Ussing. Inverse of coal. Sign 12 divided by 20 is equal to Sana. Now, at this point, this is going to be inputted into your calculator. Whatever calculated you choose to use that has the option and can calculate trig functions. You just want to make sure that the calculator that you're using that it is ingredient OK has to be in radiance. If there's not ingredients, you will get the incorrect answer needs to be ingredient. It's OK. So once it is in radiance and you enter your inverse trade function inverse coastline function and to your calculator, you should get a answer off 0.93 equals two. Say, though, and I'm gonna put someone down here and then I'm going to explain why I put it, Okay, so when you're doing these sort of questions, you need to make sure that you account for all angles that can possibly show up with in your solving process based on our unit circle, you know, unit circle that we've been working with So what you need to do is you need to go back to your original ratio hair right. There's 12/20 and you need to figure out whether it's positive or negative for us, is clearly positive. So listen that make a note of that. So this is positive. Okay? And then after you make note of whether you have a positive or a negative ratio, you need to make note of what quadrants do. I have Cole sign as a positive function, and that's when you go back. Teoh those little pneumonic that you learn. Everyone learns them different the way I learned it is. All students take calculus right in the first quadrant, all of the trick functional positive in the second quadrant. Sinus positive. The 3rd 1 10 is positive. And the 4th 1 full sons positive. So we're dealing with Data's that end up in the first larger, and fate is that end up in the for profit. Okay, so we already have the one for the first. Roger it. And now we need to figure out the one for the fourth largest. The way we're gonna do that, we're gonna take out terminal side So this is 25 and we're going to subtract our 0.93 from that. Okay, When you subtract, you get five 0.35 And once again, please make sure that your calculator is in radiance. It is very important that it is in radiance. You may get a different answer if it is not in radiance. So when you do the subtraction, this is getting us to our data for our fourth quadrant, which is positive because we're doing with Wholesome. So dado sub for meeting if they didn't quite it for is equal to 5.35 Okay, so these are your two favors that we're gonna be dealing with. You always want to make sure you write it as a solution. Set. This is going to be the answer to part one of the remaining two parts of this question. Okay, so this is what we have here now in the book it references adding a two pi n. You can do that if he This is where you were going to stop because we already know what rotation we're dealing with and what intervals were working with. There's no need for us to add that. But if you were stopping here and it was more generalized, you would definitely need to add that to pie. So don't get alarmed if you see it differently. Okay, So I am going to work through part two now, using these numbers from part number one and keeping in mind that fatal is equal to pi times teeth in part two, they want us to solve or the time in reference to the bolted being 12. So that's where this 12 comes from. The voltage being 12 as our output and they want us to solve for the time. Now, using the data is that we found in the part room. So let's do it. Okay. And won't erase. Are you using? Okay, so we're gonna leave those status alone. And, as always, you need to be ingredients for this to be the correct answer. And I've been such the color to red. So you know that I'm doing part to read, So this is hard to Okay, So if a part two we have a safe one equal 2.93 and we have a fate of four. Meaning fourth quadrant data off 5.35 Why? Point sarees? Okay, so we're gonna do is simply just substitute right? We have a beta in that equation with data is equal to pi times t so 0.93 is equal to pi times t and we need to get t by itself. Units on selected t We need to move the pie away. So we're going to use Emperor separations we're left with t is equal to now When you divide 0.93 by pi the calculator you get a 0.295 right now additional very familiar because this is the volume we got for tea earlier on our craft. That's another way you can check yourself, right? So what I around this to the neighbor's hundreds? Since you started with that early only models will continue with it. We're going to get t is equal to point serie so t is equal 2.3 when you around that and then we're also going to do the substitution for our theta in the fourth quadrant. This is 5.35 is equal to pi terms t we want to get t by itself again. So we're isolating, So whatever you do to one side due to the other. We're dividing both sides by pie. Cancel on that side and T is going to be equal to one 170 There was a other digits hair, But when you round today, there was hundreds. You just get t equals to 1.7. Okay, so these are the values National. Very familiar, because once again, we did get 1.7, really. 1.71 earlier, not graph. And this is 1.7. So give or take a rounding digit or two. These answers are almost identical. Okay, So for part two, once again, you want to make sure you're right in your solution set with dealing with seconds. So we have a time of 0.3 seconds at a time of 1.7 seconds. And that is the answer for part number two. Using the information from part number one and reinforcing it with all the previous characteristics we've seen on our ground.

So for this problem, we first want to graph our function on we see the oftentimes it's not so easy to determine things just by looking at a graph. So rather than looking at the graph, we more want to focus on the numbers and the formula itself. So we know that the amplitude is gonna be five. Because cosine can only ever be one or negative one at Max and minimum, So five will be our amplitude in the period has to be two pi over b. But since RB value is 120 pie, that gives us ah 1/60 as our period. So that means one period is 1/60 seconds. So that means in a second we end up getting 60 cycles. Then we want Thio. Look at these different values. So we have f of zero is five and f of 0.31 point 545 That's six. We get this value nine. We get this value 12, we get this value again. Those are the values that we end up getting on the last one. You just want a graph it for t from zero 2, 1/30. And this is what we end up getting


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The shape of a hyperbola is determined by its eccentricity e. This is half the distance between the foci divided by half the length of the transverse axis: (IMAGE CANNOT COPY) For all hyperbolas, $e>1$. Determine the eccentricity of the hyperbola. $$x^{2}-y^{2}=1$$...
1 answers
Evaluate each exponential expression. a. $9^{1} \quad$ b. $1^{9}$
Evaluate each exponential expression. a. $9^{1} \quad$ b. $1^{9}$...
5 answers
771 (be)a (6)a € <_ ()3 + (s)av z (s) 'uollenba Ieojuayo Kue UI pUl '7 'uoljenba |ejiuay? e jo eiduuexe ue Sl Mojeg Kiejauab nok s6uly} aNJ &41 1S17 036i0 * :!%kc '0 a6u8y? Ieojuayp e Jo ajduexa &uo &N5 Anbc 0l '' ' ; "O abuey? |eoisKyd JO aiduuexa auo aNS cn20"]' 1"7"' ){ ''<eabuey? Iejiuay? pue abuey? |eoisKyd uaomjaq ajuajayip 341 Sl Ieym (SI) Suogsano Kpms 48T-J44JJUeN lea
771 (be)a (6)a € <_ ()3 + (s)av z (s) 'uollenba Ieojuayo Kue UI pUl '7 'uoljenba |ejiuay? e jo eiduuexe ue Sl Mojeg Kiejauab nok s6uly} aNJ &41 1S17 036i0 * :!%kc '0 a6u8y? Ieojuayp e Jo ajduexa &uo &N5 Anbc 0l '' ' ; " O abuey? |eoisKyd ...
5 answers
8.1,53Supnose that you are headud loward plateau 70 m hign It Iha arale eluy Wlon Ure top Ina Dutoilu The plitonu Maoteyty (Do nCI tound Unla Iho fnal unuruc Thon rouna Io docimal piazos nadod )hoxLoulan Ine ba60 Of (ho platonu ?
8.1,53 Supnose that you are headud loward plateau 70 m hign It Iha arale eluy Wlon Ure top Ina Dutoilu The plitonu Maoteyty (Do nCI tound Unla Iho fnal unuruc Thon rouna Io docimal piazos nadod ) hox Loulan Ine ba60 Of (ho platonu ?...
3 answers
Let A, B and C be square matrices of the same order: (a) Prove that if A is nonsingular and AB = AC, then B = C_ (b) Give an example of A, B and C,such that AB = AC, but B # C.
Let A, B and C be square matrices of the same order: (a) Prove that if A is nonsingular and AB = AC, then B = C_ (b) Give an example of A, B and C,such that AB = AC, but B # C....
5 answers
Sulfur; or a Halogen CHAPTER 14 Some Compounds with Oxygen, 472 be formed by dehydration of the 14.47 What alkenes might product possible; following alcohols? If more than one indicate which you expect to be major: CH; CH; (b) CH;CHZCH,CCH; OH OHCHCH,CH;CH;(c) H;COHOHOH(e) CH;CH_CCH;CHs CHACH;
Sulfur; or a Halogen CHAPTER 14 Some Compounds with Oxygen, 472 be formed by dehydration of the 14.47 What alkenes might product possible; following alcohols? If more than one indicate which you expect to be major: CH; CH; (b) CH;CHZCH,CCH; OH OH CHCH,CH; CH; (c) H;C OH OH OH (e) CH;CH_CCH;CHs CHACH...
5 answers
The two data sets are dependent Find & t0 the nearest tenth. Women Men X1 =12.9 hr] *2 = 16.3 hr s1 =4.2hr 52 =4.4hr n] =14 (n2 = 1746.337.048.1 22.2
The two data sets are dependent Find & t0 the nearest tenth. Women Men X1 =12.9 hr] *2 = 16.3 hr s1 =4.2hr 52 =4.4hr n] =14 (n2 = 17 46.3 37.0 48.1 22.2...

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