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Number of individuals with each genotype Population Population 2 Population 3 30Population 4 36Homozygous dominant Heterozygous36Homozygous recessive22...

Question

Number of individuals with each genotype Population Population 2 Population 3 30Population 4 36Homozygous dominant Heterozygous36Homozygous recessive22

Number of individuals with each genotype Population Population 2 Population 3 30 Population 4 36 Homozygous dominant Heterozygous 36 Homozygous recessive 22



Answers

Solve for the genetic structure of a population with 12 homozygous recessive individuals (yy), 8 homozygous dominant individuals (YY), and 4 heterozygous individuals (Yy).

Okay, so we're actually used a handy little equation to figure this out. So we're gonna use a number of al eels times our number of wheels plus one, and then we're gonna divide that whole thing by two. And this is gonna tell us or total number of Gino types. So we know that there are four circulating al eels, so it's gonna be four, and then we're gonna have four plus one, and then we're gonna divide by two. So what that tells you is it's gonna be four times five divided by two, which gets you 20 over to, which gets you 10. So we know that there are 10 al eels or excuse me. There are 10 Gino types possible for this circulating out You

This question asks any particular hardy Weinberg population. There are only two I colors brown and blue. Of the population, 36% have blue eyes. The recess of trade war, percentage of the population is Hedorah zaius. So if we know that the blue I treat is going to be recessive, we could call this Ah ho Mose August individual that is going to have to lower case be a leal's. So the lower case be Leo is going to be recessive and codes for blue, whereas the upper case of DiIulio is going to be dominant and it encodes for brown eyes. So we said that 36 were 0.36 are going to be lower case Blue. Lower case. Lower case. Be lower case. Be so homeless, I guess. Recessive. So how do we determine the percentage of the population that is Hatteras Iess? Well, we have to understand that our, um, Hardy Weinberg equilibrium tells us that if we have a homeless Vegas individual that could be labeled as p squared, then another Hamas August individual displaying a different set of traits. So let's say this one right here the dominant brown, this one is going to be Q Square. All right, So what you saw for P? We are simply going to take the square root and what we find. Well, we find that P is equal to 0.6, and then that means that if we are going to have our a Leo's right, we know that P plus Q will add up to one. So now we plug in for P and we get one is equal to 0.6 plus cute. That means that Q is equal to 0.4. So now what does that mean? Well, that means that we can now finally do the last portion which is apply this equation, which is to peek you that represents our hetero zaius individual with one dominant only on one recess of Leo. So we simply take two. We multiply that by 0.6 and we most by that by 0.4, and that will give us the percentage of the population that is going to be Hatteras itis. So multiplying two times 20.6 times 0.4, we're going to get 0.48 So that means that 48% of the population is going to be hetero zegas. We'll have the headers. Iess, Leo So going back to answer choices choice be corresponds with 48% and that is why choice these the correct answer.

Okay. So given this equation here and then we're also given the boundary condition Jean right, And that those people's you plus our minus one is equal to zero. So since the some of B is is equal to one, some of is equal to one you just get, um you can just subtract the one over. Yeah. All right. So if we want to maximize the probability p, we're going thio tough Thio, take the ingredient of both p and G and find Linda where that is, that we're growing in sh multiplayer. And use that to determine the maximo So we'll take our personals. Oops, This should be, uh, in peak. You are not to X y z So our variables R p Q and R so P Q and are is pique your door. So this is pretty easy all of to use the partial was one. And so what that means is when we come over Europe So the partial with respect to P is tu que close to war so two times que or then will be equal to lender because this is equal to one little old for all of them. Alright, So cue you're going to get to he plus our because, um so here and you see, take the derivative with respect. Q. You get to our here, you to pee, so you just get, um, two times the other the some of the other variables. So this will be to Q Plus P is equally under that. The people who vanda alright so that employees that Q Plus are is equal to P O S. R. Honestly, if you divide by two in these equations up here and you'll just get them to her two little equal lindo for two so we can write the following and Q plus PD. All right, so from these two here, you can subtract are in the obtain. Q is equal to P, and from these two here can subtract Q and get ours equals PN. So cue is equal to R is equal to p. All right, so we've done it. So now we just need to plug that in so you'll get three PM because plugging it into their you get people's people's peeing. I guess one is equal to zero. So P is equal to one third right? And so appear you're just going to be a p squared. So in this equation, P squared times three times to so two times three times p squared, which is one of her nine. Actually, it's just, uh, three square into them were clear. Alright, so that gives us two over three and we're done.

The explanation for the solution is dead. Habil Decision and Plants. WAAS, performed by Gregor Mandel For the first time, he made it to individual plants which were true breeding and had a different Greg's streets are the variation seen in the final type or opinions off heritable. Characteristic trust can either be dominant or recessive. The treads, which are in had a dude in a in an unchanged manner in hybridization, are dominant. Yeah, dominant trades are expressed in F one generation. The trades, which disappear or become Latin an offspring in hybridization are necessary. Restive trades are not expressed in F one generation, but are expressed 25% in F two generation. In a cross between two individuals had toe Z, I guess for our recessive a little, a little no homo zegas resistive offspring would be obtained. So the Xena Tepic ratio cannot be one ratio to ratio of one three ratio. One ratio two or zero ratio to ratio one. Hence the option A, B and D are incorrect. Now, in a cross between two individuals had toe zegas for recessive little elderly. The our strengths obtained will be Homo zegas dominant. That is our CRC too high toes ages that it are C R and one homo zegas individual which do not express the lethal l l at well, all our homo zegas restive offspring would not be obtained. Does the Xena topic ratio would be one ratio? Tourist zero has the correct answer is option C. That is one ratio to ratio zero. So this is the complete explanation off the answer. Please go through this. Thanks.


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