Question
3.a. A 0.500 M solution is to be diluted to 500.0 mL ofa 0.150 M solution; How many mL of the 0.500 M solution are required?
3.a. A 0.500 M solution is to be diluted to 500.0 mL ofa 0.150 M solution; How many mL of the 0.500 M solution are required?
Answers
To what volume should you dilute $50.0 \mathrm{~mL}$ of a $12 \mathrm{M}$ stock HNO solution to obtain a $0.100 \mathrm{M}$ HNO $_{3}$ solution?
Let's solve the problem from the chapter solution where we are given a solution of it. Still having more clarity point to double zero moles per liter and the volume is 00.5 liter. Using the solution, we have to prepare the solution of its seal having polarity 0.150 moller. So we will prepare the solution by diluting the available solution to us, for which we have to calculate the volume of water, which is to be added now. First of all, we will find out the morals of a seal which are present in the solution. Moles of its seal is equal to volume multiplied by more clarity of the given solution that is 0.5 liter multiplied by 0.2 molds per liter and this gives the value as 0.1 moles. Now we will find out the volume of 0.150 muller at seal solution. This can be calculated by the formula. Volume is equal to moles divided by more clarity. That is 0.1 divided by 0.150 and this gives the value as 0.667 liters, which means 667 mL of solution will be prepared. Now volume of water to be dead is equal to 667 mL minus 500 mL. That is 167 mL. So we have to add 167 millimeters of water in the available solution of itself to make it small charity 0.150 Mueller.
In this problem were given four different methods for making a certain polarity solution of potassium chloride. We would like to know which of these methods will make a 0.5 Mueller solution. We can start with our first scenario where we have 0.5 grams of potassium chloride per mil a leader. So we can first divide by the molar mass of our potassium chloride. And this takes us from grams to moles. And then to get this in terms of polarity, we can multiply by 1000 milliliters to do a unit conversion. So we now have moles per liter and when we complete this calculation, we find that our polarity is equal to 6.71 Mueller. In our second scenario, we have 36 grams of our potassium chloride per leader. So all we have to do here is divide by the Mueller masked translate into moles per leader and through a calculation, we find that we have a polarity a 0.483 In our third scenario, we haven't amount in milligrams per mil it leader. So we can start by performing two unit conversions to get ourselves into units of grams per leader. So now that we have grams per leader, we can divide by our molar mass to have most for leader. And when we do this calculation, we find that our polarity is equal. 2.1 Moeller. In a final scenario, we have 373 grams of potassium chloride per tonne. Leaders of solution. So we just have to divide by or Mueller Mass here to translate into mom's per leader. And when we do this, we find that arm Olara T is equal 2.5 Mueller, which is our desired polarity. So Scenario D is what will give us the correct polarity that we're looking for.
First thing we will do here is to dissolve this compound in border will miss it, the conductors to see if the solution carries and electrical current. If solution is conducting, then we can determine whether the solution is a strong or weak electrolyte. By comparing its convicted, it's with that off unknown strong electrolyte, or it can also be done by using the APP critters shown in a textbook.
In order to have the correct moral issue. To solve the problem, we must start with the balance chemical equation. If you can determine the most off at seal in support it, we can then use the definition off polarity to calculate the volume off, etc. In needed from the volume and polarity off any rich we can then calculate pulls off any rich. Then using the moral issue from the balance situation, we can calculate molds off SL decorations in support to can also be handled. Similarly, the balance situation is a part can be written as a seal in a quest solution. Less any rich in across solution gives an a seal in a car solution plus water. The moral issue here between acid and base is minus one, which means that one mole off a seal will react with one mole off and marriage not to calculate the mole off a seal. We use this simple equation with their conversion factors and get the answer is 3.0 multiplied by 10 part ministry moves off, etc. The volume official can be done calculated from the formula the moles off a seal divided by dissolute, which gives us the final number as 6.0 mL. Using the same method, we can calculate the volume off a seal in second reaction. Here is the balance immigration for second reaction, and the moral issue here is to is to one unlike honest one in the it's about eight, the volume office seal using the same method as using support a sculpt urges as 8.0 mL.