Question, and I value to look at the table as we go through this. I'm not gonna redraw the table. I'm just gonna go through this very quickly. Um, and, uh, make a few comments and a few notes as we go along the way here. But there's a lot to cover. So, um, when you look at these questions, you have to write whether they're in Hardy Weinberg or not. So the 1st 1 you could see everybody has a big A alil. So P is one. Hugh is zero. So there it's already where? Equilibrium? Because you wouldn't expect there to be any headers, I guess. Er, almost like it's recessive. Um, for the 2nd 1 the answer's no. It's non in Hardy Weinberg equilibrium. And the reason is that there headers, I guess turn, you'd expect when they, uh, mate and have offspring that some of those offspring would be. Homer Side gets for three answers. Yes, it is in hardy Wonder equilibrium and again, for the same reason is Number one is for four. It's not in Hardy Weinberg equilibrium, and you can simply do the basic math year to get P and Q. It's a little bit tedious, but not terrible for five. Again, not in Hardy Weinberg equilibrium. And if you look at those numbers, we would expect there to be more headers. I goods. And we're not getting that. Um, so again, these numbers here with people, he 375 and 0.6 to 5. All right, uh, for six. Um, this was also yes. As I lose track on my notes, this one was in Hardy Weinberg younger. And and you can win in their in equilibrium All you have to do to get the peace accused Take the square root of, ah, say the on the percentage proportion of him is, I guess, recesses. That'll give you Q And then you could just solve for P. So that's pretty straightforward. For seven. This is not in Hardy Weinberg equilibrium. You look at it. It's just such a strange set of numbers. I'm something is going on, um, and solving for it, you're gonna have half the Leo's will be, Uh ah. Big A and half will be little a eight is. Yes, it isn't Hardy Weinberg equilibrium. And again, it's easy when there are anywhere in your columbarium because you just have to take the square root. Let's say the number of from his, I guess in proportion of home a psychic processes to get the values, um, nine is yes, and it's simply the reverse of the number eight. So that's pretty straightforward. And then, finally, Number 10 has a tiny numbers involved with it, but it isn't Hardy Weinberg equilibrium, and that's plain 993 and playing 007 So that's a and B here. And in the questions, um, see is asking about unquestioned six. Um, remember the formulas here, and this is the mutation over selection formula of the balance. And then the selection coefficient equation, which is s equals one minus w and were given mu is five times 10 to the nine s six. So that's the mutation rate. And then we can solve for Q. Um, because where we have Q from the the questions were 4.9 times 10 to the minus fifth. Something like that, um, that we just have to play the sort of it equations in. That's you square. So, um so if we use this equation here, we have 4.9 times 10 to the minus fifth equals the mutation rate, which is five times 10 to the minus six. All right, it by s. And so if we saw for s, we get a value of 102 So there's some decker mint. There is selection acting against this Leo, and then we're just unplug s into this equation here. So, um, point 0.102 equals one minus w. And again, this is this equation here I'm using. Ah, And if we saw for W, we get 0.898 So that what we were shooting for in this question, and then finally d um, there's a little bit tedious, uh, and were given values or fitness of one. And then for the headers I goat. Well, you was 0.8 and then for the homeless, I guess. Recess, Ivo, it's 0.6. Um, and we're interested in trying to calculate p crime. That is the frequency of P and the following generation. Um, so they're different ways to do this, but I'm gonna use that to formula approach. First, I'm gonna calculate average fitness, and this is a formula that's in the textbook where you have P squared names. The Fitness of the Homicide, its dominant plus two p Q and the fitness of the Headers. I Go plus Q squared and the fitness of the home is that it's recessive and these air just frequencies cow times, a fitness values. And of course, that's going to give you your average fitness. And so if you plunge these numbers in and for time reasons, uh, I'm not going to, um, you end up with a value of 0.8, right? So this number goes here and then for peace squared, remember that will just be 0.5 and shoes squared would between five squared and those air those point fires come from the table about. So the average fitness is gonna re 0.8 and then we're going to use in that value, which we needed in our second equation. And again, this is from the textbook Ah, where you multiply the fitness of the homeless. I guess Tom meant going to pee and the fitness of the headers I go and divided by the average fitness that we just calculated. So keep prime equals 0.5, and again, that's from the table above, and we want to play all that by 0.5 times one. So that was the fitness of W. A. A. That's appear, plus Q. Just also 0.5, and to fitness of the um, header is I go. And that's 0.8. That's appear. And then if we divide that by the average fitness, which we just calculated his 0.8 a 0.8 and we do that math, then we get a P prime value or the P and the next generation of 25 6 I think the question asked us What the value for Q. Is that people cubicles one. We know that then the Q prime value will be zero point for for so ah, long question with a lot of work involved.