Given problem position, Doctor. From point A to a our way will be nine minus sign 30. I kept minus cost. 30 jacket. Okay, so from here are we equals to nine. Minus one by two. I kept minus route three by two. Jacob. Okay, Now velocity appoint a V equals two. We know less omega, but they are so substituting values we get. Or maybe we're not is equal to zero. And Omega is five. K cap. And are you A Is nine minus one by two. I came minus three by two. Jacob. Now, using cross product rules, we get the but the quit school 39 0.0. I get minus 22.5. Jacob, meet up for second. So this is the velocity at point A for the part of the problem. Okay. No moving forward to calculate acceleration of point A. We can write that acceleration at point A, but there will be equal to a note. Plus, alpha are away. Bless omega, but glad, by the way. Okay. So now, substituting the values we get, acceleration at point A will be equal to a note is equal to zero. Plus, alpha is minus 10-K cab cross and cross our way across nine minus one by two. I get minus Route three by two Jacob Bless Omega Cross. The Omega is five. K cab. Of course we is this value for From part A 39.0 I kept managed 22.5. Jacob. Okay, so now solving it, we get a vector. Acceleration of point. A factor comes out to 34.6 plus 2. 14 Jacob inch per second square. This is not in meter. Okay, this is indeed inch, but second. Okay, Inch per second squared. So this is the answer for the but a of the problem. Okay. Now, for the velocity and acceleration of part B weekend, calculate the position vector R o b. As are we, plus our baby. So now, substituting the values we get R o B question. Are you A s nine minus sign 30. I kept minus cost 30 Jacob and our baby is three. Because 30 I get minus sign 30. Jacob. Okay, So after solving we get r o B vector, it goes to three by two. Go three minus three. I get minus one plus 3 to 3 Jacob inch. Okay, so this is the uh huh. Hobie Vector. So the velocity point to be will be equals two. We not plus Omega Cross R o B factor. Okay, so substituting the values we notice equals to zero, So we'll be vector will be calls to zero. Plus Omega is five. K. Cap cross three by two. Bracket under three, minus three. Jacob bless. Minus mhm. Minus one plus 3 to 3. Jacob. Okay, so now solving it, we get we b equals two. 46.5. I kept minus 9.51 Jacob inch per second. So this is the velocity of point to be of the given problem. Okay. No moving to the acceleration we can write. Acceleration at point B will be close to you. Less Alpha Alpha cross R o B plus Omega Cross week B Victor. Okay, these are all in the vectors. Okay. So substituting values we get a B vector equals to notice again. Zero and alpha is minor. Stand K cap across our O. B. S three by two. Through three minus three. I kept minus one minus 33 G k. Okay. Plus omega is where you kick it. Cross we be is 46.5 cap minus 9.5 on Jacob. Okay, so after my plane, we get a director equals two minus 45.4 I kept, plus 20 2 51 j k. Inch per second squared. So this is the acceleration of point.