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Question

WrtDojf -J/duBicoaFeneEOCmEnokac/eSut ImUfen Irom (Icuc Dcc>[email protected] Eacoitan PASMe Equurto PMt ucluteadlPPrrucl 3-Enei-ol-Jro-oic-jed Jcer-GioPaidjoDoqume-t]FEHICUJI Questions to be addressed in discussionsJOenze =tocicocinniandCompare your results with results obtained by other groups (same of different beverages)_ Comment on the alcohol content and relate with the type of alcoholic beverages Discuss the agreement of the results to the manufacturer and appropriate Food Standards account

Wrt Dojf -J/du Bicoa Fene EOCm Enokac/e Sut Im Ufen Irom (Icuc Dcc> [email protected] Eleito Eacoitan PASMe Equurto PMt uclute adlP Prrucl 3-Enei-ol-Jro-oic-jed Jcer-GioPaidjo Doqume-t] FEHICUJI Questions to be addressed in discussions JOenze =tocico cinniand Compare your results with results obtained by other groups (same of different beverages)_ Comment on the alcohol content and relate with the type of alcoholic beverages Discuss the agreement of the results to the manufacturer and appropriate Food Standards accounting for any differences in terms of experimental procedure or allowance within the regulations Comment on the agreement of the densities of the standard solutions you obtained with those given at 20PC. How do the density values ofyour standard solutions compare with the standard solutions at 208C? Alcohol is used in flavourings (eg vanilla essence) and cough medicines What is the major purpose of the alcohol? T" 755 ole 0 2 0



Answers

The industry standard for the amount of alcohol poured into many types of drinks ( e.g., gin for a
gin and tonic, whiskey on the rocks) is 1.5 oz. Each individual in a sample of 8 bartenders with at
least 5 years of experience was asked to pour rum for a rum and coke into a short, wide (tumbler)
glass, resulting in the following data:
(Summary quantities agree with those given in the article "Bottoms Up! The Influence of
Elongation on Pouring and Consumption Volume," J. Consumer Res. $2003 : 455-463 . )$
(a) Carry out a test of hypotheses to decide whether there is strong evidence for concluding that
the true average amount poured differs from the industry standard.
(b) Does the validity of the test you carried out in (a) depend on any assumptions about the
population distribution? If so, check the plausibility of such assumptions.

Hi, everyone. So, first, full rate given data that is the city of eternal C two h 50 age that is equal to 500.79 g per mall. G women. Then we do 50 ml, then w one and grade. Then Saul ability. More than 100 group celebrity. More than 100 group. More of them Mhm. I made a proof. And Oh, Sherlock. So you know, then city is equal to mass upon one, and therefore muscle C two h five or age that is equal to then sit into Walden That is equal to point 79 in 2. 50. That is equal to 39 point for you the next, right? Yeah. Yeah. Calculation of polarity of 50% solution of so McGarity of 50%. 32 h 50 age. That is equal to W two in 2000. Well, I do by I'm going to be Yeah. So that is a call to 39.5 in 2000, the other by 46.7 in 200 Mhm. So therefore okay, modularity of C two h five or H that is equal to eight point for you surrender 41 Oh, all right. Yeah. 41 more than more blood. Yeah, Yeah, I'm mm, Yeah. Mhm. Therefore, solution. Solution that are more than more than 8.5741 Moeller. That is mine. Moller. Yeah, your love and pain Moller, I think. And Penn Moller. Solution of solution. All he turned on. Yeah. Are having more than hard. More about it. Yeah, Mhm 100 poop. I'm dead, so Yeah, yeah, yeah. Mhm. Uh huh. Mhm. Mhm.

In this exercise, we want to determine if a sample provides evidence that wine tasters can distinguish between reserve and regular wine. Now, the way that the tasting is set up is that we have four containers. We have the reserve wine into the containers and the regular wine in the other two containers. And when a taster tastes, they are randomly selected three containers from which they taste. And they are supposed to identify which of the three tastes is the different wine. So that is, if they're. If they're tasting from three containers, two of them will have to be the same wine, and the third one will have to be a different wine. The taster's job is to just point out which of the three is the different one. So if a taster could not taste the difference and they just randomly guessed, then the probability of picking out the wine that was different would be one out of three. One of the three containers contains the different wine, so we can make our no hypothesis be that the population proportion is 1/3, and the alternative hypothesis would be that the population proportion is greater than one third, which would indicate that the wine tasters have some ability to distinguish the wines. To test these hypotheses, we have a sample of 855 Hastings and in 346 of them. The wine taster was correct, so we have 346 successes. So from this, our proportion estimator from the sample is this fraction, and this comes out 2.405 which is bigger than the third. But is it statistically significant? We can calculate our test statistic? This comes out to 4.45 and R P value, which since this is a greater than alternative hypothesis, is the probability getting a test statistic greater than 4.45 and this probability is approximately zero. So therefore, we are confident in rejecting the null hypothesis.

All right. We want to test the hypothesis. New equals 64.5 versus the null hypothesis or alternative hypothesis does not equal 64.5 for population standard deviation 0.6 given the following data at alpha equals 0.1 confidence. This question is testing your knowledge of how to conduct a hypothesis test for population renew. When the standard deviation sigma is known. We see through the five steps listed here to solve first, we verify normality. So from the normal probability bar on the left, in the box, on the right, we conclude that the data is normal without outliers. Thus we can proceed to solve so and be we calculate that sample size and X five simple meat. This is N equals 22 X 5 64.7 Thus you see we can calculate our test statistic, this is zero equals experiments were not over segment about 10, which gives negative 38.53 for alpha equals 0.1 We continue the critical value in step D. For two tailed tests using a Z. Table where the area H 2.5 are critical value is plus or minus 2.58 Thus we can conclude in step E the following first. Let's rewrite our critical Z score correctly. Since our Xena is to the left of our negative 2.58 we can conclude that zero is in the critical region. So we reject H. Not because you know it's a critical region. We also address the fact that ALPHA equals 00.1 is more reasonable than Alpha equals 0.1 because there are severe punishments for making the type point ever in this problem I. E. There's a severe punishment for making an area generally. So we want to keep the 0.0.1 stringent criteria.


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