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Consider the balanced equation:2C2H2 + 5O2 →4CO2 + 2H2O , How many grams ofcarbon dioxide can be produced when 1.15 moles ofC2H2 react completely? Substan...

Question

Consider the balanced equation:2C2H2 + 5O2 →4CO2 + 2H2O , How many grams ofcarbon dioxide can be produced when 1.15 moles ofC2H2 react completely? SubstanceMolar Mass (g/mol)C2H226.06O232.00CO244.01H2O18.01

Consider the balanced equation: 2C2H2 + 5O2 → 4CO2 + 2H2O , How many grams of carbon dioxide can be produced when 1.15 moles of C2H2 react completely? Substance Molar Mass (g/mol) C2H2 26.06 O2 32.00 CO2 44.01 H2O 18.01



Answers

A mixture of C3H8 and C2H2 has a mass of 2.0 g. It is burned in excess O2 to form a mixture of water and carbon dioxide that contains 1.5 times as many moles of CO2 as of water. Find the mass of C2H2 in the original mixture.

Question. Number 79 is definitely a question that incorporates an extension of concepts beyond what is traditionally introduced in a general chemistry textbook. However, it still does incorporate some of the concepts associated with this chapter, namely the balancing of a chemical reaction, recognizing the stoy geometry involved in your calculations and calculating the amount of product that can be produced. But most specifically, this question is what we often call a two equation to unknown question. Let me show you. We have to chemical reactions that are occurring. The C three h eight is going to react with oxygen and produce carbon dioxide and water, and the C two H two in the mixture will also react with carbon dioxide. I'm sorry with oxygen to produce carbon dioxide and water. We need to balance the chemical reaction, and we see that to do that for the first one, we need to put a five in front of the oxygen, a three in carbon dioxide and a four on water, and then for the settling. In order to get into your values and not fractions, we're going to need a two on a settling a five on oxygen before on carbon dioxide and a two on water. This is the first step, and it's a very important step. Once the two chemical reactions that are occurring are balanced, we can then write what we know. I'm going to define X as the mass of C three h eight that we have in the mixture. And why, as the mass of C two h two that we have in the mixture. So X plus y will be equal to the mass of the mixture, which was told to us as 2 g. We also know a mole ratio. The moles of carbon dioxide produced, divided by the moles of water produced, is equal to 1.5. So is there a way from if we knew these masses that we could actually calculate this ratio and we could we could calculate the moles of carbon dioxide produced from X plus the moles of carbon dioxide produced from why, and that would be the total moles carbon dioxide. We could do the same thing for water, divide the two numbers and get our ratio, but they've given us our ratio without giving us the masses. But we could still set it up the exact same way. If we knew the mass of C three h eight, we could divide by its Moeller Mass to get the moles of C three h eight and then convert those moles into moles of carbon dioxide, recognizing the 123 relationship. But C two h two is also reacting and producing moles. Carbon dioxide. So if we had its mass, we could convert its Mass two moles c two h two by dividing by its smaller mass and then use the stoy geometry of its balanced chemical reaction to convert moles c two h two into moles of carbon dioxide. Then we would divide that by the moles of water. Well, how would we get mold water in a very similar fashion? We would take the grams of C three h eight, divide by its smaller mass to get moles and then use the stoy geometry of its balance. Chemical reaction to convert moles c three h eight in two moles of water. With the 4 to 1 relationship, we would then add on the moles of water that were produced from C two h two by taking its mass divided by its Moeller Mass. 26.4 and then converting moles c two h two into molds water. This is how we would calculate the ratio if we knew X and y, but we don't know X and Y. We have two unknowns in this equation, but we also have this equation with two unknowns. So we have two unknowns and two equations we should be able to solve. First, let's get numbers for all of these calculations, we'll get 0.68 x plus 0.768 Why in the numerator and 0.907 x plus 0.384 Why in the denominator, we then recognize that X is going to be equal to 2.0 minus why we can plug 2.0 minus Why in for X? And now we just have one equation with one unknown, and the rest is some algebra where we're going to distribute this through in the numerator and the denominator and then combine our like terms and we'll get this for our numerator and 0.181 minus 0.523 y in our denominator, we then need to take this entire denominator and multiply it by 1.5. When we do that, this is what we have left within. Combine our like terms, the wise and the numbers without wise and then divide both sides by 0.8725 And why becomes 1.55 g of settling or to just two significant figures, which is all we started with? This would be 1.6 g a settling if we were to subtract that from two. We would then get appoint fought or 0.4 or 0.45 with this number of the grams c three h eight.

This question is often what we refer to as a two equation to unknown stoke geometry problem. We do have two unknowns. We don't know the mass of our C H R c three h eight. Nor do we know the mass of C two h two, but we know the some mass, which is 2 g. We also only know a relative amount of carbon dioxide and water. The amount of carbon dioxide produced is 1.5 times as many moles as water. So with that information, let's get started. There appears to be to chemical reactions that are occurring because the C three H eight and the C two h two are being combusted. They're reacting with an excess amount of oxygen. In order to produce carbon dioxide and water, we have to separate combustion reactions for which we need to write the balanced chemical reaction and determine the stoy geometry for the first one. Combustion reactions always produce carbon dioxide and water, so the balance it we have three carbons, so we need to put a three in front of the carbon dioxide. You have eight hydrogen, so we need to put a four in front of the water. Now we have a total of 10 oxygen's. So with the carbons, the hydrogen is now balanced. Ate the oxygen's will be balanced. A 10 if we put a five there for the next one. A settling, reacting with oxygen, we produce carbon dioxide and water. We have two carbons, so we need to put a two in front of carbon dioxide. We have two hydrogen and two hydrogen, so we're good. We have two times two, so that's four. Plus. The one over here gives us five oxygen's, so we need to put a five halves here, so five have times two gives us five, but we don't want a fraction in our balanced reaction. So we'll multiply everything through by two to, and then this becomes five and then four. And to what else do we know? We know that the summed mass of the settling and the propane equals 2 g, so let's define a couple variables. X is going to be equal to the mass of a settling. Why will be equal to the massive propane and together the equal a massive 2 g. We also know that the moles of carbon dioxide is equal to 1.5 times the moles of water that is produced we could solve for the moles of carbon dioxide if we knew the mass of a settling and propane, the masses of a settling and propane, and how we would do it is we would take the mass of a settling, which we don't know well, So we'll say it's X. We'll divide that by the molar mass of a settling to get the moles of a settling, and then we'll use this toy geometry. Two moles of a Settling produces four moles of carbon dioxide. This would be the contribution to the formation of carbon dioxide from a settling. But propane also makes some of carbon dioxide. So if we take the mass of propane, which we don't know, we'll call it why divide by the molar mass of propane? We'll get moles. Propane. We can then convert most propane, two moles, carbon dioxide using the one 23 relationships. So this would be the moles of carbon dioxide if we knew the masses X and Y the moles. Carbon dioxide, though, is equal to 1.5 times the moles of water. We could also calculate the moles of water. If we knew the masses, we would take the massive, a settling divide by its smaller mass. And then we would use the stoy geometry of two moles of settling makes two moles water. And then we would add to that the moles of water produced by propane, which we would calculate by taking the mass of propane divided by its smaller mass, to get moles, propane and then from the stock geometry, we could go from moles. Propane one two moles. Water. Four. Now we have two equations and two unknowns. Here's one equation, and here's the second equation. So all we have to do is combine these equations in order to solve for X and y. So let's finish with some algebra. We'll take and combine all of these terms so we'll have a number multiplied by X. Combine all of these terms so we have a number multiplied by why and do a similar thing on the right hand side to remember to multiply everything through by 1.5. Then we'll combine our ex terms and will combine our white terms then because we're solving for the mass of a settling we need to solve for X. So we need to replace why with something in terms of X. We can do that with this equation up here. Why is going to be equal to two minus X? So we'll replace this. Why? With two minus X, Then distribute this through and then combine our ex terms. Divide both sides by 0.87 to 3 and X is equal to 1.56 g of a settling.

Yeah. All right. So it's first rate or unbalanced equation, and then we'll get around to balancing it. We have. Heck. Scene. What's oxygen Yield Co two and water. So you see that we have six carbons here. We need a six here. We have 14. Hydrogen is we need to put seven here. That's gonna leave us with an odd number of oxygen's, um here. Right. We're gonna have 12 plus 7 19. So we're gonna end up doubling everything because we need even number of oxygen's here. This goes to 12, supposed to 14, and now we just need to put 19 oxygen's here, uh, to balance it. And the second part of this question says we have 7.2 moles of hex scene. Okay? Wants to know how many moles of oxygen we have. We just need to use a more ratio. So that means that vied out by moles of vaccine, that's too Yeah, And if we multiply by our moles of oxygen since these are balanced, the surf fraction here is just equal to one or not actually changing our number. We're just changing the units on it from moles of oxygen. Two moles of vaccine. And if you do this calculation, you get 64.8. I'm sorry. So that backwards 68.4. Mhm, mhm.

Hi, everyone. So, in this question, you know, consider the following and balanced chemical equation for the promotion of propane C three h l gas plus auto gas. Here, see what gas plus water. Gas. What volume of auction gas at 25 degrees searches and 1.4 atmosphere is needed for complete commotion of 5.53 g of propane. So they have given what we are Lim of auction. So given data one level of oxygen question mark, then temperature 25 degrees. And Sears, that is 25 plus 2 73. That is 298. Cal win, then pressure 1.4 atmosphere, then w propane. That is 5.53 grand. So we know the balance. Yeah, chemical equation. Okay. Creation fall. That's not commercial properties. Come with you Now. Road pain is forget it. C three a change because you guys bless for you or two guys gives 302 guys, I guess, plus four water gas. So, you know, first calculate and therefore to and that is equal to W of 33 ancient. They were. They were Yeah. Mauve C three h eight Malema's into Why are you more love? Right? Oxygen divided by one more love C three h eight and that is it. 1 to 5 point 53 into five, divided by 44.1. And that is equal to 0.627 moles of secondly, One limb of oxygen. Uh, you know that one level folks season We're not like, okay. Tonight previously contain Artie. And therefore we off or to their physical, too, in our camp on B. Yeah. Yeah. And therefore, volume of oxygen. My physical too young. Find 6 to 7 into our 0.0 82 n two t, 298. Mhm. Divided by one point, not four. And that is equal to 15.3214 About one point. Not for so that is equal to four. 10.732 And therefore one wing of oxygen that is equal to 14 point 732 leaders. Okay? Yeah. Mhm. Yeah,


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