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7. The current going through an ohmic resistor (y-axis) measured function tbe voltage across (x-axis). Which ofthe following graphs could represent the data?...

Question

7. The current going through an ohmic resistor (y-axis) measured function tbe voltage across (x-axis). Which ofthe following graphs could represent the data?

7. The current going through an ohmic resistor (y-axis) measured function tbe voltage across (x-axis). Which ofthe following graphs could represent the data?



Answers

An electrical device has the current-voltage $(I-V)$ graph shown. What is its resistance at (a) point 1 and (b) point 2? [Hint: Use the definition of resistance.]

This problem. We have a graph and were asked to find the resistance at points one and points to We have the current, which is 0.2 amps and the voltage 0.1. Which is there a point? Three bolts homes laws B equals IR. We do not have the resistance, so we were isolate. The are I plug in the numbers 0.3 divided by 0.0 to the resistance at 0.1 is 15 Holmes. That point to the current is 0.4 amps. The bolt age is 0.4 volts. Do the same thing. Fall teach over current 0.450 point 00 zero four and resistance that point to if 10 Holmes.

Hi. In the given problem, Mr Fall, this is the car representing the variation of current passing through the conductor Victor Time. The current is being represented over my access in M Pierre. And time is being taken over. XX is and that is in seconds. First of all, the current is 2.5 m. Pierre in a time of two seconds, then it current. This current remains constant as 2.5 m. Pierre, up to our time duration of five seconds. Yeah, this is five seconds after a bitch. The current drops to a value of one point 25 m pierre and thereafter it remains constant up to a time of 10 seconds. No. In the first part of the problem, we have to find a total charge passing through the conductor for a time interval of 10 seconds. We dis clear that there was no current. Initially means from 0 to 2 seconds, there was no current. The current is 2.5 NPR for a time. Duration of this means this is five minus two seconds. Means this is three seconds. Is the current remains constant as 2.5 m. P r. For three seconds and thereafter for this much time. Obviously it will be five seconds. So the current remains constant as 1.25 ampere for the further five seconds Hence, the total charge passing through the conductor will be given by the addition of these two charges Cuban and Cuba for Cuban disease using the basic definition of current which says I is equal to you by t so that you will be given by I into t. So here this is I run into t even and for you to this will be I to into t two. So the total charge passing will be for Ivan. This is 2.5 or even deserves three plus four i two This is 1.25 into four time. This is five in Poland. It will be the total charge passing through the conductor. So here it becomes 7.5 plus 6.25 Fulham and finally it comes out to be per pinpoint 75 Coolum which is the answer for the first part of the problem, the total charge passing through their conductor? No. In the second part of the problem, we have to find the mm. If the energy can shoot across the conductor for the given time duration to 10 seconds for which we will use the relation for the energy, electrical energy from June that should be given by H and that will be equal to H one. Plus H two means that heat dissipated in the conductor in the two cases. So in the first case, the current was I one square, the resistance are in dying. Even in the second case, this is I two square into our into t two. And here the resistance of the vibe is given us 1.0. Mm. So, for even this is 2.5 to the whole square into 1.0 home into three seconds, plus 1.25 to the whole square into 1.0 on into five seconds, Jules. So it will come out to be 18.75 plus 7.8125 Jews. Or finally, we can say this total heat developed in the conductor comes out to be 26.56 Jews approximately. And here it becomes the answer for the second part of the problem. Thank you.

If we access bigger P 26 decimal too. Voltage and current sine wave graphs for a given resistor are depicted to calculate the value of resistance are for part A. It's simply the indicated values of 10 volts, divided in 2.5 amps to yield 20 homes of resistance for are for part A to calculate the AM frequency or frequency. In general, the cycles that occur per second will equate the frequency, and in this case, if we trace the sine wave for voltage, one cycle occurs every 0.4 seconds. So therefore, the E M F frequency part B is 25 hertz.

Okay, So this is the graph for the, uh, potential verses, currents, And, as you can tell and the graph for the potential, where's his currents? It's not a straight line they missed. Uh, all right, That's not obey the owns law, OK, and then this is the resistant worships Corrine graph, and these are the answers for these questions.


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