## Question

###### The level of dissolved oxygen (DO) in a stream or river is animportant indicator of the waterâ€™s ability to support aquatic lifeand happens to be normally distributed. A researcher measures theDO level at 15 randomly chosen locations along a stream andcalculates the mean to be 4.7713 milligrams per liter (mg/l) andstandard deviation to be 0.9396 mg/l. A dissolved oxygenlevel below 5 mg/l puts aquatic life at risk. Can we conclude thataquatic life in this stream is at risk? Carry out a test att

The level of dissolved oxygen (DO) in a stream or river is an important indicator of the waterâ€™s ability to support aquatic life and happens to be normally distributed. A researcher measures the DO level at 15 randomly chosen locations along a stream and calculates the mean to be 4.7713 milligrams per liter (mg/l) and standard deviation to be 0.9396 mg/l. A dissolved oxygen level below 5 mg/l puts aquatic life at risk. Can we conclude that aquatic life in this stream is at risk? Carry out a test at the Î±Î±= 0.1 significance level to help you answer this question. (Links to an external site.) GeoGebra Probability Calculator (Links to an external site.) Step 1: State the claim and its opposite. Identify which is the null hypothesis and which is the alternative hypothesis. Step 2: Determine which hypothesis test you will use and check conditions. Step 3: If the conditions are met, perform the calculations, and conduct the test. Include the test statistic and the P-value. Step 4: State the result and interpret your result in the context of the problem. Please show work!