## Question

###### Fe can produce Fe2O3 in accordance withthis reaction equation:Fe2O3(s) + 3CO(g) â†’ 2Fe(s) +3CO2(g)167 g Fe2O3 reacts with 85.5 g CO andforms 72,3 g Fe. Calculate how many grams Fe can be formedand the percentage-wise yield?Given Molar masses:MC = 12,01 g/molMO = 16,00 g/molMFe = 55,85 g/mol

Fe can produce Fe2O3 in accordance with this reaction equation: Fe2O3(s) + 3CO(g) â†’ 2Fe(s) + 3CO2(g) 167 g Fe2O3 reacts with 85.5 g CO and forms 72,3 g Fe. Calculate how many grams Fe can be formed and the percentage-wise yield? Given Molar masses: MC = 12,01 g/mol MO = 16,00 g/mol MFe = 55,85 g/mol

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