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Given the following combustion equation of octane:C8H18(l) + 25/2 O2(g) ---> 8CO2(g) + 9 H2O(g) + 5075 kJFinda) How many litres CO2 ( At SATP) are released to th...

Question

Given the following combustion equation of octane:C8H18(l) + 25/2 O2(g) ---> 8CO2(g) + 9 H2O(g) + 5075 kJFinda) How many litres CO2 ( At SATP) are released to the atmosphere per each liquid litre of combusted octane (assume complete combustion and pure fuel) (Density octane at 25 C : 703g/L , gases : VM SATP ~24 L/mol)b) How many kg CO2 are released to the atmosphere for each 1.00 TJ energy produced by octane combustion?

Given the following combustion equation of octane:C8H18(l) + 25/2 O2(g) ---> 8CO2(g) + 9 H2O(g) + 5075 kJFinda) How many litres CO2 ( At SATP) are released to the atmosphere per each liquid litre of combusted octane (assume complete combustion and pure fuel) (Density octane at 25 C : 703g/L , gases : VM SATP ~24 L/mol)b) How many kg CO2 are released to the atmosphere for each 1.00 TJ energy produced by octane combustion?



Answers

The combustion of gasoline produces carbon dioxide and water. Assume gasoline to be pure octane (C8H18) and calculate the mass (in kg) of carbon dioxide that is added to the atmosphere per 1.0 kg of octane burned. (Hint: Begin by writing a balanced equation for the combustion reaction.)

So first we need to write a balance to come. Koyuk Ocean off the combustion reaction. I saw the octane Oh, to most of octane react with 25 more off oxygen, we'll get to six more of carbon dioxide on 18 more water based on this palace to come. Equally caution. We can see the ratio of octane with carbon dioxide is one over eight. So the most off octane E host to its mass divided by a smaller mess on then the mass of carbon dioxide Nicole's through the most of carbon dioxide, which is also aged times off the most off octane times. The muller mess of carbon dioxide we can get way will know the mass off carbon dioxide is 3.1 kilograms.

Hallucinated. Three. The amount of carbon dioxide that will be produced on giving up into the atmosphere. When one case your for activities burn is re calculator. So the composition of off team off course my digression. C eight. It's 18. Yes, 25 by two Giving eight You do plus nine. It's too. This is the equation for the conversation. The more amounts off obtain is 114 and we have to find the amount off. Carbon dioxide on government had moral masses 44. So the basis of our culprit needs one more off. Okay. Burns to produce hate most off carbon dioxide on Develop the same thing expressing plants. So one kg off glutinous burned so one month for Katie is burned Means 18 to 41 Grandma Governor York City's police So one Grammys burn means 18 to 41 upon 114 grand Bargain your citizen, right? Therefore one kg is burned. Means one kg is burned. Means eight into 41 aboard. What you for the 44 year we should rate is 44 18 44 upon 114 Indu one both into Graham. That is one Casey can you get This is 3.49 kg off. Family Oxy

So now work on Problem ninety six from chapter twenty one here were asked to calculate how much how much math and kilograms of carbon dioxide is produced from the complete combustion of three point eight kilograms of N eight octane. So the first thing that we have to do here is we need to get a balanced equation to figure out the story Geometric ratio between Penn Sorry, Obtain and Karen Backside. So we know that combustion of octane means reacting with oxygen to form carbon dioxide and water. So we're going to go ahead and put in ever, um, coefficients here. We're gonna double, uh, the arcane, which means we're going to need sixteen current backsides and just to verify that everything else is correct And this is this is fun forward. We can calculate the amount of water which we would need. We're going to need thirty six hydrogen Sze has shown from the left. So that means we're going to need eighteen waters. And then if we calculate the amount of oxygen that we need, it's eighteen from water and thirty two from carbon dioxide, which is fifty. So they put a coefficient of twenty five in front here. So this is our balanced equation. And from then what we need to do is we need to convert kilograms of carbon of arcane two kilograms of carbon dioxide so we can start with three point eight kilograms of ch teau eighteen. We multiplied by a thousand grand. It's on dried by one kilogram to convert from kilograms to Graham. We multiply by the Mueller Mass of We are sorry we divide by the Miller mess of octane to get moles. We're conservative here from Graham's two moles of obtain. Then we multiplied by the strike geometric ratio. Here we have sixteen moles of CO two for every two moles of octane, so that gives us moulds of carbon dioxide. So then we multiply it by the Mueller massive carbon dioxide, which is forty four point zero one grams, Jamal. So that gives us grams of carbon dioxide. And then we moved to Ojai. We'd serve you divide by thousands. We multiply by one over a thousand to once again get back to kilograms. Since the questions specifically asked for kilograms and if we do this calculation, multiply three point eight by one thousand divided by one fourteen point two two multiplied by sixteen over two were eight and then multiply by forty four points were one and divide by thousand. We get when accounted for significant figures, twelve kilograms of goto.


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