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TABLE Typical proton chemical shints 6 CH, protons Acetylenic protons (CH,)Si 0,0 HOCH,C ECH (CHAC 0,92 CICH C CH CH,CH,OH 0,7 CH,COC CH CH,COCH, 2,07 Olefinie pro...

Question

TABLE Typical proton chemical shints 6 CH, protons Acetylenic protons (CH,)Si 0,0 HOCH,C ECH (CHAC 0,92 CICH C CH CH,CH,OH 0,7 CH,COC CH CH,COCH, 2,07 Olefinie protons CH,OH 3,38 (CH,AC CH; CH,F 4,30 Cyclohexene CI; protons CH,CH CHCHO Cyclopropune 0.22 CI;C CHCI CH (CI) CH; L,25 Aromatic protons (CH,CILACO 2.39 Benzene CH,COCHCOOCH, 3.48 C,H;CN CH,CH,OH 3,59 Naphthalene CH protons a-Pyridine Bicyclo[2,2.1 heptane 2,19 Aldehydic protons Chlorocyclopropane 2,95 CH,OCHO (CH;LCHOH 3,95 CH,CHO (

TABLE Typical proton chemical shints 6 CH, protons Acetylenic protons (CH,)Si 0,0 HOCH,C ECH (CHAC 0,92 CICH C CH CH,CH,OH 0,7 CH,COC CH CH,COCH, 2,07 Olefinie protons CH,OH 3,38 (CH,AC CH; CH,F 4,30 Cyclohexene CI; protons CH,CH CHCHO Cyclopropune 0.22 CI;C CHCI CH (CI) CH; L,25 Aromatic protons (CH,CILACO 2.39 Benzene CH,COCHCOOCH, 3.48 C,H;CN CH,CH,OH 3,59 Naphthalene CH protons a-Pyridine Bicyclo[2,2.1 heptane 2,19 Aldehydic protons Chlorocyclopropane 2,95 CH,OCHO (CH;LCHOH 3,95 CH,CHO (CH,LCHBr 4,17 GICHO 2,33 2,40 3.17 4.6 5.57 6,05 6.45 7,.27 7.54 7.73 8.50 8,03 9.72 9,96



Answers

Complete the table. \begin{array}{ccccc} \hline \begin{array}{c} \text { Chemical } \\ \text { Symbol } \end{array} & \begin{array}{c} \text { Atomic } \\ \text { Number (Z) } \end{array} & \begin{array}{c} \text { Mass } \\ \text { Number (A) } \end{array} & \begin{array}{c} \# \\ \text { Protons } \end{array} & \begin{array}{c} \text { # } \\ \text { Neutrons } \end{array} \\ \hline \mathrm{Pd} & 46 & & & 54 \\ \mathrm{Ce} & & 136 & & \\ & 84 & 208 & & \\ \hline & & & 88 & 138 \\ \hline \end{array}

Within the context off NMR here, we're going to be looking at some Elektronik plea non equivalent protons. So I've got some examples up on the screen over on the left and I've also got the answers just to the right off the questions on. So I will run through the first example and then we will rationalize how we get the answer to which will then allow us to complete the set of examples that we do have up on the left of the screen. So firstly, we've got ch three ch two b r. So I've drawn out that structure just there, as you can see and so we have to non equivalent proton environments so I can identify those two environments as this set of protons hair. And then we have this sort of protons here. So now we know that there are different environments because they are in different carbons and they there is no element of symmetry, so they are unable to exchange place or be considered equivalent based on a symmetry factor. So we have a missile hair that's all ch three now because we only have single bonds present all of these protons can exchange places and therefore that considered equivalent. It's not our first group then. Secondly, we have two protons on our second carbon, which can see a bro mean, whereas all fast group of protons can't see a roaming out strongly. And so this is our second group of protons by where they're in a different environment. However, these two protons again they can exchange places because of our single bonding that is present. So we do not have a confirmation Lee locked structure, so therefore they are equivalent, given the fact that they can exchange places. So this has identified to none equivalent Proton groups, and then you can use the exact same rational to finish the rest.

In this question, we are asked to complete this table that has a list off chemical symbols. There are atomic numbers, mass numbers, number of protons and the number of new Trans present in those isotopes. So let's try to fill in the blanks for these isotopes. The first one is for technician, and we can use a periodic table to look up the atomic number for technician and receive that it is 43 so we can write 43 here and then we're given the mass number. And with all that, it's 95 eso. We don't have to worry about feeling that blank. And then if we move on to the number of protons, the number of protons is always going to be equal to the atomic number. So we can just write 43 over here and then the number off neutrons we can get from subjecting the number off protons from the mass number. So 95 minus 43. Well, give us the number of neutrons for this technician. My so talk and that is going to be 52 moving on to the second isa talk. They see that the atomic number for it is given on its 56. And if we take a look at the periodic table, we see that the atomic number 56 belongs to Barry. Um, so we can I bury him over here? And then, uh, the number of protons, as we mentioned previously, is always equal to the atomic number, which is 56 Barbadian. So I'm just like 56 over here, and the number of new chance we can get from subjecting 56 from 1. 28 because the mass number is the sum off the number of protons and the number of neutrons. So if we subject the number of protons from the mass number, we get the number of neutrons and so 128 minus 56 is 72. And then if they move on toe, the third isotope, it's called European. And if we take a look at the periodic table, we see that the atomic number for European is 63 and s o the number of protons should also be 63. And since we're given the number of neutrons, we can add the number of neutrons through the number of protons and did use the mass number. So 82 plus 63 is going to be equal. 200 45. Finally we have Francie, um and the periodic table does us that the atomic number for Francia Miss 87 and were given the number off neutrons in this isotope so we can deter mined the mass number by adding the atomic number to the number of neutrons. So 1 36 plus 87 is going to be 2 23. And as we discussed before, the number of protons is equal to the atomic number, which is 87 in this case and

All right. So we're going to fill in the blanks here. Um if we're given the symbol, that means the mass number is on the upper left hand corner and the element white atrium is going to on the periodic table. Atomic number 39. That tells us the number of protons, which is the same as the number of electrons. These are all neutral atoms. So we can actually just copy that over if we have protons and electrons. So 81 81 50 50 89 89. All right. Six year that neutrons is the mass number of minus the atomic number. So in that case it's 50. Okay, All right. Next we have um 78 protons and electrons. So to find the neutrons will take the mass number 1 95 minus atomic number 78. We got 100 and 17 for the symbol we put the mass number on the top left and we look at atomic number 78 to find the identity, 78 or 78 platinum. Okay. Next we have to get the mass number will add protons and neutrons 81 plus 123 is 204. That's what's gonna go at the top. We need element 81 which is sally Mtl mm. Freedom. Uh huh. Doesn't try to make it look not like an eye but whatever. Okay. Um if we have 50 protons, mass numbers 119 119 minus 50 is 69 neutrons. Mm. Put the mass number. Yeah. And we need atomic number. 50 corresponds to 10 sn lastly we have 2 27 minus 89 is 138 for the number of neutrons. Then we're looking for atomic number 89 to get the symbol. She's going to be eating an act any um A C. And we're done.

We have to fill in the blanks in the chart. Um So we have the periodic table down below to help us if we need. And oh, of course, the headings are cut off. Oh, no, that's fine there on the side. Okay, so, so TB 1 59. The mass number is given to us as 100 59. That's the sum of the protons and the neutrons. Um The protons will look at the periodic table. We see turbie in is atomic number 65. So then if you take 159 minus 65 give us 94. That's the number of neutrons. We're assuming that these are all neutral atoms. So whatever the protons is, that's what electrons is as well. To balance out the charge for 65. Next, if we have 29 protons, which is also 29 um electrons and 34 neutrons 29 plus 34 gives the mass number of 63 which will go in the corner and still get the element's identity will say what element has the topic number 29. Let's go down here and it's copper. Does this copper 63? All right, next, we have 53 neutrons 42 electrons. That means that the number of protons well add these two to get the mouse number. That's 95. And we need the element that has atomic number 42 which is molybdenum. Um Oh, so I'm over 95. Alright, next. If we have 34 electrons, that means we have 34 protons to get neutrons. We take the mass number 79 minus 34. I'm just going to be 45. We put the mass number in the corner 79. And which element has atomic number 34. Yeah, selenium esky mm mhm. Lastly 37 protons 37 electrons, 85 minus 37 is 48 neutrons. Mhm. We'll put the mass number up here and we need the atomic number 37 is rubidium. And we're done


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