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If a reaction responsible for spoiling a foodstuff has an activation energy of 54 Kj / mol, by what factor is it slowed down in a refrigerator at...

Question

If a reaction responsible for spoiling a foodstuff has an activation energy of 54 Kj / mol, by what factor is it slowed down in a refrigerator at 5 ° C and in a freezer at 18 ° C , compared to the temperature of 25 ° C? A catalyst keeps this foodstuff at 20 ° C the same time as if it were in a refrigerator at 5 ° C. What is the activation energy of the catalyzed reaction?

If a reaction responsible for spoiling a foodstuff has an activation energy of 54 Kj / mol, by what factor is it slowed down in a refrigerator at 5 ° C and in a freezer at 18 ° C , compared to the temperature of 25 ° C? A catalyst keeps this foodstuff at 20 ° C the same time as if it were in a refrigerator at 5 ° C. What is the activation energy of the catalyzed reaction?



Answers

An increase in temperature from $23^{\circ} \mathrm{C}$ to $36^{\circ} \mathrm{C}$ increases the rate constant of a certain reaction by $50.0 \% .$ What is the activation energy of the reaction?

Okay, so problem 81. We're given the change in activation energy were given temperature and were asked to calculate the right in Greece. Okay, so rate increase would be calculated by dividing gate to over. Okay, one. Right. So that's why I have the Arrhenius equation right here and we're going to use. So we got me too. Over K one equals a to time. Did a negative e um, to over rt and same thing for okay, one a one over rt. So, um, the only thing that changes is the activation energy. So that means you can see factor should stay the same. So we're left with we're left with faced a negative e a two over rt over ta wan. Over. Okay, so since this is division, that means you could just, um, subtract the exponents. But since this is a negative number, when you subtract a negative number, we need to add, So this one equal to e race to negative. Mm. No e a to thus e one. All of that over rt. So the denominators the same. Okay, so all that's left for us to do here is plugging numbers, right? So Oh, move over here to get more space. We got K two over K one equals negative e. They're not negative. E race to negative. Ea to is five killed, Jules, for more the 55 individuals Permal Blush e a one which is 1 25 And all of this over are we need to express it and killed you. So it 0.314 I understand that a minus three still Jewell spur more Koven and our temperature is given, but but it's given Social. So I converted it to Calvin. Got to 98. And of course, this e doesn't really belong. There has to be here. He raced. Do this whole thing like you. Okay, so just check. Let's see of our, um, units, cancel this Golden Councils Kelvin. Right? And then they killed you'll sperm all cancel as well. Okay, so if we put this into the calculator, it gives us in 1.8. I'm stand to 12. Right? Which is about just entered it off. So that would be our final answer

To determine the increase in rate, we're going to use a ratio of the Iranian equations or will say that K catalyst is equal to a E to the negative E A over R T and Kenyan catalyst is also equal to a negative EA over RT. The only difference here is the activation energies, the temperatures are the same, the A's, which is the frequency factor because it's the same reaction are the same in each case, so they cancel. So to calculate the ratio of catalyst to an catalyst, we simply need to finish the calculation over here, E to the negative 55,000 over 8.3, and 2 98. That number divided by this number here gives us 1.9 times 10 to the 12. So that means K catalyst is 1.9 times 10 to the 12 times faster or greater in value than K. Uncapped a list.

Hello, everyone. My name is Ah, Magali. I will answer thes question this question. Suppose that a capitalist lower the activation energy from along to five killed June 255 killers June By what factor would you expect their action? Rito increase at 25. Solicitors assumes that the frequency factor for catalyze and the kung catalyzed reaction on I identical to answer this question We were right. The arena's question But by other form, which is link a equal lin a negative. Ah e activation. Divided boy. Artie, this is the second form off the arena's squish. This four will help us. How? We will right eight toe time for uncle allies and imprisons off cattles. So I will call on catalysed one and imprison off. Catalyst is too will write it in. Uncle Allies, We will said Lenk. A one is equivalent Lin a and remember here assumes that the frequency factor is similar. Did you mean a not change? Negative. The value off E Activision is one toe fine divided by our tea. And remember that the activation here is kilos. You so must choose our with all points 314 times by 10. Negative three and the temperature must be killed in which will be to nine. A boy's some toe to Fire Tau 73 Then we were right again. But with the presence off catalyst, it will be Linke to equal the same, eh? And you get there. 55 Divided boy Artie, which is a similar value. Eight points we want for times vitally needed. Three and the temperature is 29 a. Now we have equation Juan and their equation Tau, so we will subtract toe negative one. Toby's ants link it to negative Linky want. It's right as a full way Linky toe bike. You want that? We want to know the increase. Kato Bill. Come on, it's a lin in negative lane, it's, say, canceled each other, then negative negatives is This will be positive. So it will be as the four way 1 to 5 negative 55 divided by diseases common, which is our team. Divided by eight points, 314 times biting negative three and time's white tulle ni ng a. So now Z's value in use calculator. It will give you to a boy too. Fine, so now we will Golan. In other side. Toby Exponential. So K two divided by Kyu Wan is equal e exponential a two going toe fi which he is one point a sex times by teen Bob are wet. So in presence off catalysts and activation energy decrease by this value The read of reaction increase by Iowa. Thank you.

Given activation energy. We need to find out. The ratio operates for a reaction to temperature, assuming that initial concentration are same at two temperatures. And the ratio operates will be the ratio operate constant given divide work. You two. We use the question 14.21. So first even equals two 50 degrees Celsius Last 2 73. That is because too 3 23 Calvin. No, do you to given any question? Gerald Davies health. Yes, We add to 70 three. After that it convert in Calvin. That is to 73 Calvin. Now from equation 14.21. We can write as alan Given by K two. It calls to E. A. By our Mhm Into one by T one minus one by T two. Now simply put the value alan given my kid too. Because to feel that is activation energy given in a question that is 65 seven kg jule bottom, all divided by gas constant. That is 8.31 port jule caramel. Multiply by 1000 jule Part of one kg tool. We need to convert jules mm We need to convert kilos well into June so we multiply 1000 jewel After that. Multiply one divided. But even his question is 2 73 -2 equals two 3 23. No, after calculating we can write us Ellen. Do you want to buy Get two equals 2. Seven point 902 Into 10 to the Power three. Multiply by pi point 670 Plus 10 to the Power- Port. That is it close to 4.4. 4.481. Now we can write us, we can take the anti log on both sides. So given by K two equals 2 88 point three. That is equals two. Approximately calls to nine into 10 to the Power one. So we can see that the reaction will occur occurred 90 times faster At 50° cells. Yes. A dooming a cool initial concentration, concentration and Iranians kinetics. Sure, this is our final answer for this question.


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