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Whon sensors i 0 car deled collision, Iey CbUce Ihe reatton of sodium azike NaNz whkch generies gas t Mi thu Mmin 3767,807500CaetHon MangedetuuducodSIPIita Djo cont...

Question

Whon sensors i 0 car deled collision, Iey CbUce Ihe reatton of sodium azike NaNz whkch generies gas t Mi thu Mmin 3767,807500CaetHon MangedetuuducodSIPIita Djo contdins Jith thu appropriate unlaE0 RRa?Liotes5 YuurValueUuitssuomilRemeuier [

Whon sensors i 0 car deled collision, Iey CbUce Ihe reatton of sodium azike NaNz whkch generies gas t Mi thu Mmin 3767,807500 Caet Hon Mangedet uuducod SIPIita Djo contdins Jith thu appropriate unla E0 RRa? Liotes5 Yuur Value Uuits suomil Remeuier [



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In a collision of sufficient force, automobile air bags respond by electrically triggering the explosive decomposition of sodium azide (NaN $_{3} )$ to its elements. A 50.0 -g sample of sodium
azide was decomposed, and the nitrogen gas generated was collected over water at $26^{\circ} \mathrm{C}$ . The total pressure was 745.5 $\mathrm{mmHg}$ . How many liters of dry $\mathrm{N}_{2}$ were generated?

Late taxes with the number of colleagues in here which is equal to one by food and everybody. Which is equal to be now I can write the ratio of breeders by B. Physical to end us. My duplicates on this by anne Marie duplicates on this which is equal to one by an under would be death by T. When the gases expand and times and decreases by a factor. And also I can write the expression of it. Is this market duplicates and P. To the power to buy. I. Is equal to T. V. To the power Dubai I. On further simplification I can develop today's is equal to this to the power to buy. I'll multiplication. So the value of appearance by P is equal to This. By this multiplication. Teach to the power -1 by I. Which can be further written something like this. So this is the final answer. So he had collision decreases by a factor later be defective. Why? Coalition decreases by a factor? Why and why can be written into the power and I plus one by I hear the value of I. is equal to fight

Hello students welcome back and this question we are given the connectivity of NSL to be equal to 1 26.4 Okay and similarly we are given linda nod for a tear To be equal to 425 .9 And we are given Linda not for any at sea to be equal to sorry it's at sea and they accede to be equal to To be equal to 4 25.9 4.25.9. Okay so these are the given. Sorry I'm sorry this is any easy. Okay see the compound this is N A A C And it is given to be 91 91. Okay so I'm giving these values and I have to find out Linda not four HAC. Okay so if I just break London or for any H H A C. So what do I get is I will be needing the London or for each place and the London or for a C minus. Right so if I get these two values I'll read the London or poor H A C. Okay so for that I am given some conditions so I'll find out this way these two values from here. So if I just break it okay if I just break these values what do I get is and they can not offer any plus and linda northward C l minus. Okay and this will be equal to lend an out of edge place let's land another sale minus and this will be quick to learn a lot of Annapolis in London order? Yes you like this. Okay so you can clearly see that if I if I just add these two equations, if I just add this situation and the situation I'll get lambda edge place and linda easy. And then I have to subject this situation. I have to subtract the situation. So if I'll subtract this equation this will cancel the sale minus and this will cancel this a necklace. Right so I can write that Lebanon not for H. A. C. Will be equal to linda North for N. A. C. Plus lambda North for at C. L minus the London or food Anisha. Okay because this any will cancel this any and the cl will cancel the sale and we will be left with a C. N. H. Okay so putting these values, what do I get is 4 25 point night plus 91 -126 1 26.4. So if I was calculated it comes out to be 3 90 white fight centimeter square Farmall. Okay so this is the value of London order H. S. Okay so that's it. Thank you

Aren't with our particle theory and sort of our gas work that falls under the bridge of our thermodynamics in physical chemistry. So the first equation that we need just to offer you some contextual understanding B is eight r t over pie, um, the power of a half that's also written a square root. So what we get from this point is value of 300.22 meters per second and I'm following on from this. We're looking at density, that is P and a liver r t. What we get from a value of this is 2.43 times 10 to the 25. Meat is the minus three. Next we plug these follies in to the following equation. Two squared dance deep I D squared, See got a value of 9.59 times 10 to the nine seconds to the minus one. Now, if we take a look at the second part, well, we substitute the values off dead 11 and density into the following equation. Well, that's divided by to it's not very clear, divided by two. That's a said that's also said, What we get is the following 1.94 times 10 to the eight malls Police tas Second, that is the collision density of chlorine and a molecule at one bar pressure and 25 degrees C.

So here we were just looking at the idea that gaseous sodium atoms do absorbed quanta out several energies. And so the ionization energy off the ground state is known to be 9496 killer jewels pummel. And so here we've just calculated the ionization energies for the our several states as well as ours at F energies. And then lastly, we just looked out the energies for are far and l values So all of this data is listed on the left. As you can see, we fastly got our ionization energies. Next we have all said f another bottom There we have our our Barbara, please. So the more deeply and orbital can penetrate I eat the close of the orbital is to our nucleus, the greater it is thief ect nuclear charge felt by the electrons that are present. So the four US orbital's will experience the biggest effective nuclear charge on the that F values. The three p on four p orbital's should be greater down the sad F charge for our three de orbital's


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