5

(ii) Calculate the induced EMF at time ( = L.0O second and indicate the direction of the induced current on the diagram above . (5+2 points)...

Question

(ii) Calculate the induced EMF at time ( = L.0O second and indicate the direction of the induced current on the diagram above . (5+2 points)

(ii) Calculate the induced EMF at time ( = L.0O second and indicate the direction of the induced current on the diagram above . (5+2 points)



Answers

[II] The square coil shown in
on a side and has 15 turns of wire. It is moving to the right at $3.0 \mathrm{~m} / \mathrm{s}$. Find the induced emf (magnitude and direction) in it $(a)$ at the instant shown and $(b)$ when the entire coil is in the field region. The uniform magnetic field is $0.40 \mathrm{~T}$ into the page.

Problem. 53. And this problem a rectangular loop of length uh L and with the W is moving inside a magnetic field and where the magnetic field is of constant magnitude be and loop is moving with velocity V. As soon in the figure, we have to determine electro motive force that is induced E M F. In the loop. So, first of all, we will assume that that entered the entered a portion of the loop inside the magnetic field is X. So basically this length is let us say X. So area of the law that is inside the magnetic field will be, this is area A. And that will be length multiplied by X. No. Therefore flux linked with the loop will be be multiplied by area. And We have just calculated the value of area that is Ellen two X. Now we know that E M F induced the M F. So mm induced his equals two D five IDT. No. We have just calculated the value of floods and it was B L X. So we can we have to differentiate this with respect to time B L X now B and L are constant. Therefore we can take it this term outside outside the differentiation. So this will be B L d X by D t not dx by DT is the rate of change of rate of change of with with respect to time. And this changing length is given by rate of change is given by the velocity. Therefore we can replace the term A dx validity by velocity. So this will be be LV. Therefore induced E m F will be B L V from the given absence option. B is the character absent.

The induced Yemen is caused by a change in flux and can be found by calculating the rate of change in flux. So this will be called you negative. If you just want a magnitude, then this is destroyed. So this is equal to defy over DT. More flux can't deter Mined by the area off the multiplied by the magnetic field passing through the loop. So D off Dave millions of here that change so gentle flags will be changing magnetic field times idea. Now the amount of flags will change as the loop is moved with velocity V through the magnetic field. Big when a linear land off wire l. And there's the magnetic field the IMF generated in the What wire can be determined by using this formula. So we have the lent off the wire on DDE. The velocity off the loop. It's his feet. So area off the Luke any afternoon is equal to. So if it's a sky, so every off the mobile bay, it's a lent off. The look times Atlantis given Toby Dines X, the area code, the distance covered by the loop. So this is the length off the wire and This is the distance covered by the looks of that skips us The area covered over D. D. Now over here the magnetic field and let off the wireless constant so we can take them out off the derivative. And we're left with DX over DD. But as I said before, access the distance traveled by the look And this is the time taken to travel that distance. So since we already have the velocity off the loop, we can say that this is in fact, the X over DT on. We can use this expression over here. On that, they get the M f induced. You may have to be equal toe magnetic field times let off the wire times velocity off the loop. So the codec option is going to be option B. Thank you.

You're a civilian. Chapter 26 Problems for everyone. So it says determined the net resistance in this figure for are a between points A and C and then for B It says points once A and B. Okay, so and it says assume our prime does not equal, are it Gives us a hint. This is apply it in yet again E m s and determined currents using anuses use symmetry of junction. Okay, cool. So that's a good hand and must take advantage of it. So this is our circuit. Let's modify this toe where received where we apply in the IMF. Here. Somebody's son Hi. In Yemen. Oh, so we add on this blue circuit to this basically where this is absolutely Mm. So now what this does is it creates a current I going clockwise here. From this, we can now defines in quantities. So we should see that down here We have. I want I'm Nicole. Three. We know here we have. I won. So I hear is total I in across this way? We have I too. So the current split cedar and 123 ways become up T Here we see that the current is going to split again. It's called this current I four, the current down year I spy. Lastly, there's one more current We haven't talked about this one, which we call ice six. Okay, so now we know that the equipment resistance is given at us. The math over total I This is what we want to find. Okay, So how do we do this? We exploit group's role are cute problems Look, laws. Okay, so let's talk about this boob autumn loop here, right? If we'd talk about this loop here, weaken, set it up so that Emma and it travels. Just threw one resister and the currently labeled here is I freeze. And this eye three and we know that that's kind of equal to zero. Okay, good. So now let's talk about another. Let's talk about this triangular room right here. So we talk about this one. We know that we're gonna start out with the negative are times I won. We're going for traveling. It's clockwise in our minds. We now go negative our times down top. And now we're opposing the current on its last leg of this Luke. So we add, I'm two times are Well, this equals zero. Okay, so there's another loop. Let's move on to early talk about this. Similarly, we can write our equation negative. Over too. Minus are times by six course. Our times are three. And that equals Okay, Well, as you can guess, there's one word here we can do. So let's go ahead and I wantto do that one Red. So we have negative are prime times I four. Then we have a plus. I six times are plus I five times are in the sequel. Zero. Okay, so here's some other loops. And now there's some more we can fix within this because we know how some of the current's really So, for example, look at this point right here. Coming in. We have I and coming out because I want us to plus I three. So we have this relation. We can do the same saying up this top junction where were coming in I won and coming out. We have I for no, I'm fine. We have another junction. We can do this at which is right here where we have coming in. I too, and coming out. Who's we have high six. But we also had coming in five, so we can just subtract. I awesome. So this is seven equations. You're very daunting. But there's one thing we want to figure out. We'll figure out what our crime is so that we can figure out the cover equivalent resistance. Well, we know, actually think. Are we gonna figure out what I was so into ground? What are you this? So if we rearrange this equation and we know that I three is getting, you know, over our we can plug that in, how can we play that in there? So what's our first equation? That I think this one doesn't have it. One does. So let's go ahead and put that in. But we have negative are by two minus R by six plus human cool zero. And we have two plus I six course Vienna over our awesome. This red equation does not have ice to get it. We don't have to rearrange that one. Then we can also say that our but we can can rearrange it in terms of all time if we want. So art I five plus by six schools are prime terms for We also know that I equals eye one loss by two plus Deena over our because of what I three said his Okay, so let's do some more. Substitution is here. Seems like we're not getting anywhere, but we will. So we can rewrite too. I too plus five equals m f over our by putting in Where's the proving in this equation? In here. Okay. So we can also rewrite that as to I to Plus I won minus four equals that song over our So we know that I equals I want us I two plus excellent over our very happy with that. Take that back from Let's rewrite this one. So now we have eye to eye one last to I four plus by two ukuleles are prime I or and keep on moving. We can take equation three. So he was substitute to the I to minus I one course absolute over our cool. So we put that one back into this red equation year. We see that are negative. 352 plus two cups on over our This equals our prime times five I too minus two. Absolute. Over our Okay, Let's keep going here Now we have I You are a plus I to plus so never are These will cancel out miss because for two well, we know that by two equals I over for now we can continue on so that I wear are condoms Negative three I was plugging what I waas eye to eye over four plus two sons are this equals our crime This was five times on to before minus two is long over are Okay, so our cue is given as absolute Where I So how do we really want to reign? Right this in terms of ups on over I so I'm gonna take the whole thing and divide by I So now we're left with our over my times Negative three over four Waas two over our are you. This equals our prime over I times five over four minus two over our are cute. Okay, so now it's not a point by our virtue Are you on both sides? So we had our swear over to that We're far over by times. Negative three are over eight plus are you equals our prime over cars five are over eight minus. Are you okay? um, let's combine these together so that we have these eyes will cancel our homes. Then we're left with our over our crime squared. Making three over eight close are are cute over. Our prize equals five are over eight miles. Are you this up here? Now we're left with five are over eight. Close three r squared over a crime equals R r Q over our crime. Plus are cute. So now our Q equals are five are prime was three are all over. The times are plus up front. Wow, that was a whole lot of work to get there Me surplus and read. This is our final answer, though, for part a just party. But we finally got there, um, lets out a new pager party. So Part B asked us to do the same saying, but between points, eh? So now we can use symmetry, which is good, because that means we don't feel we can avoid being awful. So let's draw this out real fast to see what the symmetry is like. That was a bad drawing parties here. Yeah, we are. Are are a B. This is D No. Another one over here, Mrs c are are Okay. So in this case, we can put her there A symmetry because there's no current through the our prime resisted. Okay, so that's easy enough. So we know that the upper left to resistors from a D to be friends. No, I just read, which means the upper to upper sisters These in these are in Siri's. Okay, so we can start out by adding those two in Siri's. But they are in parallel with this resistor. So if they're in parallel, we are that in peril. Here we now see that this one and this one are in Siri's, but also in parallel. The original paid Izzy. So we had that like this. And since they're in peril, we take the inverse it, Ian. So this is simple enough to do. We just add this up. This becomes for over two, are all in verse or are over too much, much easier than doing the terrible, terrible out there we did for party

So in the phone spot. Because the current is gone stern, there will be no change in flux. So the induced current will be Siegel mine. The second body. They're decreasing current in the wire because they're decreasing field into the page through the loop. Notto oppose this decrease. The induced current in the loop will produce if Locke flux into the page so that there is, ah, a net increase in the flux. Now, this state read this results in the direction off the induced current Ah, to be clockwise. So let me just explain the sounds of one second. So the other decreasing current on because of the decrease. In current, we will have a decreasing fink on the direction off. This field will be into the pace through the through the loop. So we have a decreasing field into the page through the loop on to oppose this decrees that induced current in the loop will produce it flocks again into the page because we're opposing the decrees so that induced current in the loop will produce a flux into the page and therefore the direction off the induced current will be clockwise. Now, the third part is also similar to the second part. So there is a decreasing current on the decreasing current will cause a decreasing field. But over here that the prison field will be out off the base through the loop. Notto oppose this decrease that induced current in the loop will produce a flux out off the beach and therefore the direction off the induced current Guilty. Don't go clockwise coming to the last fund. The current is increasing and the increasing current in the wire will cause an increasing field out off the bridge through the loop. To oppose this increase the induced current in the loop, we produce a flux into the beach. So the direction off the induced current will be Girl khweis. Thank you.


Similar Solved Questions

5 answers
The absorbance ofa 5.34 x 10-3 M solution of a compound is 1.822 at a wavelength of 466 nm in 1.00-cm cell: Calculate the molar absorptivity at 466 nm.
The absorbance ofa 5.34 x 10-3 M solution of a compound is 1.822 at a wavelength of 466 nm in 1.00-cm cell: Calculate the molar absorptivity at 466 nm....
5 answers
Felll) can be precipitated from slightly basic aqueous solution by bubbling oxygen through the solution; which converts Felll) to insolublc FclllI}:4Fe(OH) + (aq) 4OH (aq) +Oz(g) 2H,o()AFe( OHJz($)How many grams of Oz are consumcd - precipltate allof the iron In 50.0 mL 0f0.0550 M Felll)?
Felll) can be precipitated from slightly basic aqueous solution by bubbling oxygen through the solution; which converts Felll) to insolublc FclllI}: 4Fe(OH) + (aq) 4OH (aq) +Oz(g) 2H,o() AFe( OHJz($) How many grams of Oz are consumcd - precipltate allof the iron In 50.0 mL 0f0.0550 M Felll)?...
5 answers
7. [2] Ben wants t0 tile his patio with square tiles: all the same size. The patio is rectangular; and measures 84 inches long and 70 inches wide: The square tiles Ben has chosen are available in all whole-inch sizes X [,2 *2, etc) What size are the the largest square tiles that he could use without needing t0 cut any tiles? Explain your reasoning:
7. [2] Ben wants t0 tile his patio with square tiles: all the same size. The patio is rectangular; and measures 84 inches long and 70 inches wide: The square tiles Ben has chosen are available in all whole-inch sizes X [,2 *2, etc) What size are the the largest square tiles that he could use without...
5 answers
T2 lineari zaton of fat {e Gind number Xo) nd use jt bo fnd Siver Standard Unearappximatton 04f fl)_ dbe O X Y= 2 96= 1, 4=1.2 7+1
t2 lineari zaton of fat {e Gind number Xo) nd use jt bo fnd Siver Standard Unearappximatton 04f fl)_ dbe O X Y= 2 96= 1, 4=1.2 7+1...
5 answers
LiNE R' T#at LET BF TUE PassES Tieough TXE Pot NT $ (1,7, -2) AnD (2, - 1, 1) . LET BE T#E PLANE DEFINEB B Y; X + Y - 32 + 6 Finb An EQuaton For 1 Awb Equation For THE PLANE Vz An T+AT CONTAINS LiNE Atb IS PERPEN BILuLak T6 Vi
LiNE R' T#at LET BF TUE PassES Tieough TXE Pot NT $ (1,7, -2) AnD (2, - 1, 1) . LET BE T#E PLANE DEFINEB B Y; X + Y - 32 + 6 Finb An EQuaton For 1 Awb Equation For THE PLANE Vz An T+AT CONTAINS LiNE Atb IS PERPEN BILuLak T6 Vi...
1 answers
For the sequence $q_{1}=8, \quad q_{2}=12, \quad q_{3}=12, \quad q_{4}=28, \quad q_{5}=33$. Is $q$ nondecreasing?
For the sequence $q_{1}=8, \quad q_{2}=12, \quad q_{3}=12, \quad q_{4}=28, \quad q_{5}=33$. Is $q$ nondecreasing?...
5 answers
Wow 10Everynciohborhood 0 @ cotaims iunnolhct & neighborhood of @ .eredSelec On1g: Tiuged eul 4Tokee1ag questign
Wow 10 Every nciohborhood 0 @ cotaims iunnolhct & neighborhood of @ . ered Selec On1g: Tiug ed eul 4 Tokee 1ag questign...
5 answers
Differentiate the trajectory Equation 3.14 to find its slope, $ an heta=d y / d x,$ and show that the slope is in the direction of the projectile's velocity, as given by Equations 3.10 and 3.11
Differentiate the trajectory Equation 3.14 to find its slope, $\tan \theta=d y / d x,$ and show that the slope is in the direction of the projectile's velocity, as given by Equations 3.10 and 3.11...
1 answers
2 20Find a basis for each ofthe subspaces N(A), R(AT), N(AT), R(AT) if A = 0 -22 0
2 2 0 Find a basis for each ofthe subspaces N(A), R(AT), N(AT), R(AT) if A = 0 -2 2 0...
1 answers
In Exercises 37-52, evaluate the function at each specified value of the independent variable and simplify. $ f(x) = \left\{ \begin{array}{ll} 2x + 1, & \mbox{ $ x < 0 $} \\ 2x + 2, & \mbox{ $ x \ge 0 $} \end{array} \right.$ (a) $f(-1)$ (b) $f(0)$ (c) $f(2)$
In Exercises 37-52, evaluate the function at each specified value of the independent variable and simplify. $ f(x) = \left\{ \begin{array}{ll} 2x + 1, & \mbox{ $ x < 0 $} \\ 2x + 2, & \mbox{ $ x \ge 0 $} \end{array} \right.$ (a)...
5 answers
Cylinder of volume 1.0 [10 Points] One mole of a monatomic ideal gas is contained in L a temperature of 400 K The gas is to be brought to a final state of volume 2.0 L and temperature 400 K. reversible heat source is available with heat capacityC(T) = ATwhere A=30 J/K? and an initial temperature of TRHS; 300 K Calculate the Jexi mum delivered work?
cylinder of volume 1.0 [10 Points] One mole of a monatomic ideal gas is contained in L a temperature of 400 K The gas is to be brought to a final state of volume 2.0 L and temperature 400 K. reversible heat source is available with heat capacity C(T) = AT where A=30 J/K? and an initial temperature o...
5 answers
Comoact dic (CO Ennbnim EMm] treor Faut t oul onto Aith (nenrrumoton that dunna 0htaadr tt muac deteced 4consuni (anarntal EDEEC any palnt. Slnce Tcaale CctAle Onela Hpred Iar muslc near te Guter edae end Haroce anoularinad muc naartna Inner Dart oltha diat muscatthn Dutrr Edgt 0,0568 m) the anqular sptrd metHndthe contant tanccntel eced ut Ahlch mulcDetectedFlnd tna angula Lnteu FmIyaimnudaOialance0,0105trom Ita center 04 # CD_
comoact dic (CO Ennbnim EMm] treor Faut t oul onto Aith (nenrrumoton that dunna 0htaadr tt muac deteced 4consuni (anarntal EDEEC any palnt. Slnce Tcaale CctAle Onela Hpred Iar muslc near te Guter edae end Haroce anoularinad muc naartna Inner Dart oltha diat muscatthn Dutrr Edgt 0,0568 m) the anqula...
5 answers
Arctan(n) n" + [ n=l
arctan(n) n" + [ n=l...

-- 0.019739--