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When a cupcake is placed 16.9 cm away from thecenter of a concave mirror, its image is located 48.3 cmbehind the mirror. What is the focal length of the mirror?...

Question

When a cupcake is placed 16.9 cm away from thecenter of a concave mirror, its image is located 48.3 cmbehind the mirror. What is the focal length of the mirror?

When a cupcake is placed 16.9 cm away from the center of a concave mirror, its image is located 48.3 cm behind the mirror. What is the focal length of the mirror?



Answers

A convex mirror produces an image located $18.4 \mathrm{cm}$ behind the mirror when an object is placed $32.0 \mathrm{cm}$ in front of the mirror. What is the focal length of this mirror?

Find the focal length of a concave mirror Within object 39.3 cm in front of it that projects an image 17.8 cm in front of the mirror. So you know that S. I. is 17.8 cm. S. O. is 39.3 cm. You need to find the focal length. So, using the one over F equals one over S. O plus one over F. I. You know that F. Is S. O. That's I over S. O. Plus S. I. So our answer needs to be 2, 3 significant figures. So this gives us a focal length of 12 0.3 centimetres.

Hi. The given problem, the distance of image which is formed behind the mirror is given as minus 5.66 centimeters. And distance of objects in front of the mirror is 34.4 centimetre. So the focal length of mirror will be given by mirror formula which is one upon F is equal to one upon a soup plus one upon as I so plugging in the values here, this is one by 34.4 minus here, it will become minus one by 5.66 So the L C. M here will be 34.4, multiplied by 5.66 So here it will be 5.66 minus 34.4. So finally this focal length will get an expression as 34.4 into 566 centimeter divided by this difference, which will be negative and the difference is 28.74 So finally, for the length of this mirror, which is convicts, historical mirror comes out to be minus 6.77 centimeter. Which is the answer for this given problem here. Thank you.

Yeah, object in its image in a concave mirror are the same height, so H. I. Is equal to H. O. But inverted when the object is 45.3 cm from the mirror, what is the focal length of the mirror? Okay, so first we can use that H. I over H. O. Is able to negative as I over S. O. To solve for S. I. So plugging in values and solving for S. I. And we find that S. I. Is equal to F. L. So if H. I. Is equal to negative H. O. As I is equal to espo, which means when we use the mirror equation one over S. O. Has won over S. I. We get that. This is equal, gives us a focal length of 22 0.7 centimeters.

High in the given problem, the image is being formed behind the mirror so image distance is minus 3.55 centimetre object that stands in front of the mirror is 24.5 centimeters. So the focal length of spherical mirror will be given by mirror formula, which is one by F physical to one by SA plus one by S. I. So plugging in the non values. Here, this is one by 24.5 and here it will become minus one by 3.55 There is a L c M will be 24.5, multiplied by 3.55 So here this is 3.55 minus 24.5. So finally this focal length here will be given by minus 24.5 in 23.55 centimeter divided by this difference will come out to be 20 0.95 and in negative, which we have used already. So finally, this focal length of the mirror will come out to be minus 4.15 centimetre hands. The mirror is convex in nature, and this is the answer for the given problem. Thank you.


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