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7.36 citric acid is dissolved in ! Lof its solution 12.0 mL of this solution required neutralize 15.0 mL of Ba(OHJz solution What molarity of the Ba(OH)2 solution? ...

Question

7.36 citric acid is dissolved in ! Lof its solution 12.0 mL of this solution required neutralize 15.0 mL of Ba(OHJz solution What molarity of the Ba(OH)2 solution? Also , find the grams of citric acid required t0 neutralize the base here points) 3Ba(OH)z(aq) 2H,CaHOn(aq) Ba (CoHs01)(aq) 6H-O()

7.36 citric acid is dissolved in ! Lof its solution 12.0 mL of this solution required neutralize 15.0 mL of Ba(OHJz solution What molarity of the Ba(OH)2 solution? Also , find the grams of citric acid required t0 neutralize the base here points) 3Ba(OH)z(aq) 2H,CaHOn(aq) Ba (CoHs01)(aq) 6H-O()



Answers

Citric acid, $\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{7}$, is a triprotic acid. It occurs naturally in citrus fruits like lemons and has applications in food flavouring and preservatives. A solution containing an unknown concentration of the acid is titrated with KOH. It requires $23.20 \mathrm{~mL}$ of $0.500 \mathrm{M} \mathrm{KOH}$ solution to titrate all three acidic protons in $100.00 \mathrm{~mL}$ of the citric acid solution. Write a balanced net ionic equation for the neutralization reaction, and calculate the molarity of the citric acid solution.

In this problem, we're going to be talking about solution, chemistry solution, steak, yama tree and acid base chemistry. And let's get some information about the problem in this problem or given citric acid or were considering citric acid. And I'm waiting to get my problem up here we have 0.250 g. The chemical formula is C six h eight 07 We're dissolving this and 25.0 mill leaders of water. It requires 37 0.2 mL of 0.105 Moeller sodium hydroxide for complete neutralization. The question is how many acidic or ionized herbal hydrogen does per molecule? Dis citric acid have. And I think that's everything we were given. I don't see my 25 mL of water yet, but we have 25 mL of water. Okay, let's convert grams of citric acid, two moles of citric acid, and that's going to be done. I'm just using the molar mass. Pretty simple. So we're going to divide 0.250 g. There, there. I've got the 25 mL up there, so we're going to divide our 0.250 g by 1 92.1 grams per mole. Okay, that I mentioned that I was voice over in this because I had an audio problem. Now here's where we're going to put one mall of citric acid over 1 92 0.14 grams. This equals 0.0 130 moles of citric acid. Now we're going to figure out our volume times. Polarity equals malls, so we're going to get our moles of hydroxide my ball to playing. The volume. Zero point 0372 leaders, which is 37.2 mL times 0.105 Moles per leader to get 3.91 times 10 to the minus three year 30.391 Moles of sodium hydroxide Easy Now We're going to take our molds that we just calculated moles of O age divided by moles of citric acid, and I think you can probably see what the answer is going to be right now. It's going to be three, so citric acid is a try product acid with three ionized herbal hydrogen, and that's it.

This question says that citric acid, which can be obtained from lemon juice, has the molecular formula see six each 807 That it tells us a 0.25 grams sample of citric acid dissolved in 25 milliliters of water requires 37.2 milliliters of 0.105 Mueller any oh age for complete neutralization that asks us what number of acidic hydrogen is per molecule does citric acid half. So here is the molecular formula that they gave us for citric acid, and they told us that if we have a 0.25 grams sample that were that we will be time trading or neutralizing with sodium hydroxide. So let's first figure out how many moles of citric acid are in this amount of citric acid. So 0.256 0.25 grams of C six h eight 07 If we divide this by the Moler mass of this compound. So one more C six h 87 is equal to 100 and 92 0.1 to 4 grams grams. Cancel left with moles, which is what we wanted. We see that this amount of citric acid contains 0.13 Moles of C six each. Eight 07 Great. Now let's see how many moles of base we're required to neutralize this. It tells us that it was a 0.105 bowler. Well, points here for one's your five moles of study my draw oxide any. Ohh. Her leader, but small spotted by the volume tells us it required 37. I went to milliliters. Divide that by 1000 to convert toe leaders so we can cancel. There's volume units milliliters cancel leaders cancel. We're left with moles of setting hydroxide. Do this calculation you would get 0.39 balls of any other age was used to neutralize the citric acid. We can write that 0.39 moles of any Ohh is needed to neutralize every 0.1 three moles of citric acid. And to figure out how many acidic proto proton citric acid has, we simply divide by the number of moles of citric acid. There are between these two. Figure out what the ratio between any ohh and citric acid is, and since sodium hydroxide has one hydroxide to donate, however, many hydroxide balls. Whatever this ratio is will tell us how many acidic protons that were to neutralize you could probably see this. You wouldn't need your calculator. This comes out to three. Any Ohh for every one C six h eight 07 So if you need three molds of any Ohh To neutralize everyone well of C six h 807 or citric asset that tells you that there must be three acidic Hodgins, three acidic hydrogen cz for every molecule of citric acid.

Here today. We're looking at citric acid and resolution of it Julia Solution using but 150 g of the citric A citizen salute. Okay, it's a better See. So here's the nuclear formula. Forced to drink acid? Yeah. Commonly seen not only in Citrus fruits, but also soft drinks. Okay, So first mean to find the molar mass. I'm from all of such a gossip. So I was to fully evaluate the solution. So you know what? It iss We first list out each moment and then write down the number of each Adam. Then we just simply multiply it by the atomic mass of each the elements. Guess there's one on 10.0. Can't say that again. Okay, well, we know the molar mass of hydrogen. It's one and then 15.9 for oxygen. If we add those up, we get 192 0.123 grams per mole. Okay, So what we're actually trying to find here is the mill aridity of the solution, which is most for leader. Okay, so we know that malls is equivalent to mask over molar mass which want to find modularity. We need the most mhm. So you've been given that we're looking weren't interested enough. 0.15 grams of the salute, and we've already calculated smaller mass over there. Just divide the two figures. Yeah. Okay. Okay. Let's find my pen. Okay, this is equivalent to 7.8 times 10 to the negative four walls. It's a very small number. Okay, now we're ready. Toe plug this into the C equals on a graffiti formula. And we have our most that we just calculated, divided by the volume of the desired solution, which is to leaders. And he e here just means times 10 to the exponents. That's what he's replacing. He's like e x p on your types, leader. All right, so once we've done this division, we get a molar concentration of 3.9 times 10 to the negative four. Okay, so let's just do a brief recap. But it first did Waas when The molar mass. Then we found malls of salute with the Moller mouse of the solid and the given malls. And then we plug that into this equation. Singles in a ravine to find the concentration


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