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Mixture of Fez(SO4)z and its hydrate Fez(SO4) 9H,O has mass of 0400 g. After heating to drive off all the water , the mass is only 0.7926 g What is the weight perce...

Question

Mixture of Fez(SO4)z and its hydrate Fez(SO4) 9H,O has mass of 0400 g. After heating to drive off all the water , the mass is only 0.7926 g What is the weight percentage of Fez(SO4); 9H,O in the original mixture? Report your answer t0 4 significant figures_ Molar masses: Fez(SO4): 399.88 g/mol; Fe_(SO4)3 9H,O 562.02 g/mol.

mixture of Fez(SO4)z and its hydrate Fez(SO4) 9H,O has mass of 0400 g. After heating to drive off all the water , the mass is only 0.7926 g What is the weight percentage of Fez(SO4); 9H,O in the original mixture? Report your answer t0 4 significant figures_ Molar masses: Fez(SO4): 399.88 g/mol; Fe_(SO4)3 9H,O 562.02 g/mol.



Answers

A mixture of $\mathrm{CuSO}_{4}$ and $\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}$ has a mass of $1.245 \mathrm{g}$. After heating to drive off all the water, the mass is only $0.832 \mathrm{g}$. What is the mass percent of $\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}$ in the mixture? (See page $98 .$ )

So in this problem, we're going to be looking at the reaction of copper two sulphate and copper, two sulphate Penta hydrate. We've got a mixture of these two samples and our total mass is 1.245 grams. So again, we've got 1.245 g, and part of it is anhydrous copper, two sulphate. And part of it is, um, competence sulphate Pantai Drake. After we drive off all of the water, we have a mass of 0.832 g. We're gonna find the mass percent of the copper two sulphate, and to hydrate in the mixture. Okay, there we go. We're going to do massive water. Two moles of water, two moles of copper, two sulphate Pento hydrate. I excuse me. Two moles of copper, two sulphate and bent hydrate to massive copper. Two sulphate Penta hydrate. Then we're gonna divide that by the mass of the sample and that will tell us are percent. And I think we're ready to begin putting together our calculation with a lovely shade of purple. So the mass of water driven off is gonna be 1.245 g. Are mixture minus the dry and hydra sample. We get 0.413 g of water. Now we're going to convert 0.413 g of water, two moles of water by dividing by the molar mass of water, which is 18.2 grams per mole. Our answer is 0.2 to 9 bowls of age to out. Our next step is to convert that bulls of H 20 the moles of copper two sulphate Penta hydrate. And we're going to do that with simple mole ratio. This is easy. Look, we have five there, so we're gonna use our coefficients of one and five and we get zero point. That's not right. 0.0 zero for five. You have to get a little bit more room here. Can't right all the way to the edge of the paper. Here we go. 0.0 zero for 584 malls of the Penta Hydrate. Okay, and then we're gonna be going to our next page transcribe this information on to this page. This is how many moles of the copper two sulphate pento hydrate we have now We're going to convert this to mass of copper. Two sulphate Penta hydrate by multiplying by the molar mass of the copper. Two sulphate Penta hydrate is to 49.68 g per mole and we have 1.144 g of copper. Two sulphate Penta hydrate. Almost done. Now we're simply going to divide. I should have written Pento hydrate right there. 1.144 g, divided by 1.245 g equals 91.9% C. U. S 04 got five h 20 and that's the answer.

In this problem were asked to find the mass percent of copper sulfate in a solution of copper sulfate and water were given the total mass of the solution and the mass of the copper sulfate after it's been heated to drive off water to find them mass percent, we simply divide this dried copper sulfate isolate by the original mass of the mixture.

The direction for the given problem. See you is so four. Five is true. All less big nation sulfate MGs 04 do saving. It's true all copper sulfate series so far less ignitions and bed mgs a four plus 12 is too. Oh, and most of it's Tual is it Will do five point 0 to 10 Graham, my niece, who into nine it it wrong is equal to 2.3 Do ground, Moller. They're more killer Murders off C. U S 04 into five is to all is equal to 249.61 g. But a more and do 0.3 program is to all multiply one wall off his store, divided by 18.0 graham Offish tour multi play. One more, one more off copper sulfate in 25 is through all divided by two Well from all off the stool multiply do for 9.61 g and divided by one more copper. Some fit in Hyde. Rigid form is it will do to a point 35 ground copper sulfate in hydrated from five issue or in mass percent off upper solve it. What is to all is 2.35 ground, divided by five point 0 to 0 ground. Want to play 100? Person is it Will do. 46 point 8% is the most percent of copper sulfate into five vegetable mass percent off her judicial person. Thirties for six point it person here Graham Skin, Sylhet, Graham.

Right. So for ah, hydrate. If we're trying to figure out essentially how much water is present, we have to look at how many moles of water there compared to the moles of copper sulfate. So four copper selfie we know, given this information that 250 grams was heated and then the 160 grams was left. Okay, so he had the 250 grams at 1st 160 grams heated. There is what was left. So that's our dry salt, which means 90 grams of H 20 is what was heated off. So we have to turn that 90 grams and moles, I said to turn grams and moles divide by the molar mass morass of water. It's right around 18 grams per mole. Hey, when you do that Calculation 90 divided by 18 gives you five moles of H 20 So if one roll of copper sulphate contains five moles off of the hydrate contains five bowls of water, then that tells us our formula. So it's gonna be C u S 04 and that's gonna be a penta hydrate or five h 20


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