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Question 50/20 ptsCar A increases speed from 5 m/s to 10 m/s. An identical car B increases speed from 10 m/s to 15 m/s. Which statement about the change of kinetic ...

Question

Question 50/20 ptsCar A increases speed from 5 m/s to 10 m/s. An identical car B increases speed from 10 m/s to 15 m/s. Which statement about the change of kinetic energy for car A (AKA ) and the change of kinetic energy for . car B (4K B) is true?orrect AnswerAK_A < AK_BouAnsweredAK_A > AK_BAK_A=AKB

Question 5 0/20 pts Car A increases speed from 5 m/s to 10 m/s. An identical car B increases speed from 10 m/s to 15 m/s. Which statement about the change of kinetic energy for car A (AKA ) and the change of kinetic energy for . car B (4K B) is true? orrect Answer AK_A < AK_B ouAnswered AK_A > AK_B AK_A=AKB



Answers

Velocity and Acceleration of a Car A car rolls down a hill. Its distance (in feet) from its starting point is given by $s(t)=$ $1.5 t^{2}+4 t,$ where $t$ is in seconds.
(a) How far will the car move in 10 seconds?
(b) What is the velocity at 5 seconds? At 10 seconds?
(c) How can you tell from $v(t)$ that the car will not stop?
(d) What is the acceleration at 5 seconds? At 10 seconds?
(e) What is happening to the velocity and the acceleration as $t$
increases?

Hello, everyone. This probably We're told that we have a car that is moving with some initial velocity, which is 10 m per second. And so it has a kinetic energy off a half M times V. I squared. And so in part A were as if we want the car could double its kinetic energy. So one its final kinetic energy to be two times the initial kinetic energy. Um, at what Speed or with what speed does the car have to travel? Okay, so we have that The final kinetic energy is a half times and times to be f squared where VF is the final velocity. They want this to be equal to two times the initial kinetic energy because the two times half times M v, I squared. And so we want this guy to be equal to this guy over here. Okay, so we said, let me to be equal to each other. The half and the M drops out. So we have VF squared is equal to two times V. I squared, take the square root, and then putting in the numbers we find a BF is, you know, equal to root two times B I, which is 10. And so we find that the F is equal to 14 m per second. Okay, this is part A and part B were as if the final velocity is given and it is two times the initial velocity. So if we f is equal to two times V I, that is to say it's 20 m per second in this case, then by what factor does the kinetic energy increase off the car? Okay. And so the way we do this is we set. We looked at the ratio of the final kinetic energy and the initial kinetic energy and so this gives us a half m v f squared over half MV I squared where again the halfs and d and the EMS canceled. And so we have a We have squared over V I squared but we have squared Is nothing else but to times V I all squared And so if we write this out this is you know this is four times V I squared and so we cancel that be I squared with the denominator and we find that the increase in Canet Energy is by a factor of

Hello and welcome to this video solution of enumerate here we are given that a car is traveling at a constant speed of 20 m/s. So Let's say the velocity of car is 20 m/s rate. And next um, it overtakes another car which is moving at constant acceleration 2m/s and it was initially addressed. Right? So we have got a separate car where we just caught which was addressed and moving with acceleration of two m per second squared. Right? No, Assume that the land of each card to be five m the total distance covered in overtaking will be great. So first of all we calculate the distance traveled by the car distance you will find the first car In 20 seconds Red Light Which is 2030 right? Because it was it's moving in with uniform velocity rate in the second case the distance is equal to U. T plus half 80 square eight. Now, the distance covered s will be equal to you with zero plus half to the square it. Right. So here we have the distance covered in time. He is the square. Right next we have to see that the total distance that is required. Right? This distance is a distance covered by the first, correct. That is actually covering by the first coverages 2050. Now to cover the same distance and and an additional of let's say five plus 5 10 m. Right. Uh huh. Right. The second car has to cover the same distance a distance of 20 plus 10 m in a time of the square, is that a lot of times these distances Total distances a civility square. So we can say that the square is equal to Quantity Plus 10. Right now, this is a quadratic equation minus 20 t minus 10 will be called to zero from which we will have equal to 20 point 49 second straight. Now, the total distance compared to what it will be Quality Square Right? Which is is equal to the square, which is equal to 20.49 Squared, which is equal to 4 194, 19.8 meters. This is the total distance with which ah the total distance of what taking we can say right, but someone is not given the options, But the correct answer is for 419.8 m/s. I hope this is clear to you and how very good rest of the day. Thank you.

The day Engine chillax relation is equal to do be divided five et attending to lax Relation is equal to rate of change of velocity. Right. And you re is equal to DS, divided by city. When is different chatted with respect to time Then we get velocity And from here we can right DT is equal to d s d minded by re yeah, since 80 is equal to on TV divided by D TV before 80 is equal to g B divided by DT and DTs Dia's divided by TV DS divided by B All right on this implies age Tangential X relation is equal to I'll be times you d be divided by D. S Andi, we have ah TV divided by D s Legner I don't here DVD divided by D s is equal to minus sooner 0.15 It's minus 0.15 on tending to lax. Relation is equal to 25 25 minus 10.15 No 0.1 five into minus zero point 15 15 Right. So well, we have a s is equal to all 51.5 meter, 51.5 meter. So we have miss here as well. So s is able to 50 51.5 meter and therefore are tending to lax Relation is equal to minus 2.59 minus two point 59 meter per second square. And when s is equal to when s is equal to 51.5 meter and musical too. 17.275 meters per 2nd 17.2 75 meter per second. Well, we have ah rule. Right. Well, uh, Rome is equal to one less divi divided by the X deep my divided by D X clear into three, divided by two Divided by Andi Square Why divided by D X trail and de by divided by D X eyes equal to minus do divided by 625 times X x is equal to 50 on and this implies state D by divided by D. X is equal to minus 0.16 right and d square d squared. Why divided by are the X Square is able to minus 0.0 32 and then rule is equal to 324 0.576 meter right sequel to 300 UH, 24 point 576 meter and being with eight V is equal to real times. Peter Daut and pleaded not, is equal to be divided by role. So Peter Don't is equal to 17 point 275 divided by 324 point 576576 So a pita don t is equal to zero corn. Siegel concede a 00.0 0.532 five three to Radian per second, radiant for second and normal X relation. Normal X relation is a cold, too. Are all times Peter, not square well, which is equal do 0.919 me, too, per second square. Now Total X relation is equal to root. Dandan two X Relations Square Place normal Next Relations Fear, which is equal to 2.75 music or second square

Well, let's find out. A change in kinetic energy is the first case. Uh, so change in kinetic energies. Let's say Delta care one for the first case is equal to kinetic energy final minus of in the sure kinetic energy Well are this can be returnees and divided by two his common. We, uh, one F square minus 31 eye, uh, square. Let's plug into values and divided by two into ah, finally lost. He's 100 meter per second. It's 10. In fact, we one f squared is equal to 100 and the eye is zero. And therefore, a change in kinetic energy in the first case is equal to 50 times. Mm. Uh, Jules, no. Let's calculate a change in kinetic energy in the second case. And in the second case, let's say change in kinetic energy is Delta K two and again Delta Kate Do is skimming by final kinetic energy minus, um, initial, uh, kinetic energy on this change in kinetic energy can be rate unease and divided by two into Ah, oui to F scare. Uh, minus we too. We I square. Let's a plug in the values. Well, we too have square is 1600 uh, 1600 minus. Well, we do. I screened his mind and red and simplifying we get dealt a key, too is equal to, uh, 350 times em into Jules. So change in kinetic energy in the second case is 350 times em. Jules. So it is very obviously the change in kinetic energies crater in the second case. So, uh, change chained in, uh, Connecticut Jersey is greater eyes greater in the second case and the second, uh, kiss. All right. Now, let's sex gland is why is it so? Well, um, if he observed eight, um, a Delta K one, which is a change in kinetic energy. In the first case, it's equal to I am divided by two into wee one f uh, Les, We won I into we won f minus. Ah, we wouldn't I? We one eye. So the change in kinetic energy is proportional to the product off this some off the two velocities and the other difference. So, using this information, it is clear to understand why the changes much cratering the second kiss. Ah, we can arrive it. The same conclusion is previously by noting that uh uh, the general form is equal into, uh, Delta Key is equal to am divided by two into we f bliss we i into Delta we and further Delta K prime, um, for the second case is equal to Delta key into we f crime less Uh, we I prime divided by ah Rieff Bliss We I and therefore Delta K Prime is equal to tell the K into four deep lis qwerty divided by a 10 plus zero. Therefore, Delta K Prime is equal. D'oh! Seven times off Delta Kid Don't take a prime is the change in kinetic energy in the second case and Delta gaze the change in kinetic energy in the first case and this equation tell the state change in kinetic energy. In the second case, it's seven times off the change in kinetic energy. In the first case


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