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The weight of an astronaut on Earth surface is 1020 N. What isthe astronaut weight in a satellite orbiting Earth at an altitudeof 480km with a speed of 420 m/s? (g=...

Question

The weight of an astronaut on Earth surface is 1020 N. What isthe astronaut weight in a satellite orbiting Earth at an altitudeof 480km with a speed of 420 m/s? (g=9.8 m/s2, G= 6.67 ×10-11 N m2/kg2 andREarth = 6400 km).Select one:a.720 Nb.770 Nc.825 Nd.880 N

The weight of an astronaut on Earth surface is 1020 N. What is the astronaut weight in a satellite orbiting Earth at an altitude of 480km with a speed of 420 m/s? (g=9.8 m/s2, G= 6.67 × 10-11 N m2/kg2 and REarth = 6400 km). Select one: a. 720 N b. 770 N c. 825 N d. 880 N



Answers

What is the weight of a $68-\mathrm{kg}$ astronaut $(a)$ on Earth, (b) on the Moon $\left(g=1.7 \mathrm{~m} / \mathrm{s}^{2}\right),(c)$ on Mars $\left(g=3.7 \mathrm{~m} / \mathrm{s}^{2}\right),$ (d) in outer space traveling with constant velocity?

Uh, so we're going to be solving problem two and checked her for of the gang Coy physics textbook and were given that there's a sixty eight kilogram astronaut. We're as to find his wage. That's the mass of the astronaut. Or has to find his weight on Earth on the moon and on Mars as well as in outer space. Traveling a constant velocity to part a, um, wait on earth we know that way is a force. Maybe Reese thinking about weight is almost just like mass. But masses, um, and inherit property of an object. And the weight is really a force that depends on the acceleration due to gravity. So I'LL label it W um but this is really force of gravity, usually labeled FT physics textbooks and this sequel to the Mass, just like any force mass times acceleration, except for the celebration, is Teo and on Earth. We know that this is nine point eight approximately nine point eight meters per second squared to play in the mass at the same time sixty eight times bring create, and this will be in new ten's kilograms nears per second squared, and we can put that into a calculator. Get six hundred sixty six point four and remember, we only want report. The number of significant digits that we're using, which is to significant, is it's nine point eight sixty eight. So this is roughly six hundred seventy millions. Some part B for asked to find this fur on the moon where were given that he's equal to one point seven communes per second squared. So can we just use the same formula, her weight being Mt. And he just We're gonna play these numbers in the calculator. Still the sixty eight kilograms. And now we're not going to use nine point eight years for second squared. That's exploration due to gravity on Earth. Money's the one point seven. If they told us. Given the problem for the acceleration due to gravity on the moon and then approximating Teo to significant digits, you should get one hundred twenty Nunes part See, we're just going to do the exact same thing. They also tell us acceleration due to gravity. But on Mars three point seven years per second squared, Yeah, still using the same mask. It's all about the same astronaut. Sixty eight kilograms. Oops! And the answer of you should get for that just plugging into calculator approximating Turn fifteen unions and then party his work. It's different because we're now told that the asteroids in outer space not on a planet, not feeling gravity and he's trailing a constant velocity and on velocity is constant. It means that acceleration is zero draw narrow that this implies equal zero because, remember, the acceleration is stuff have lost e changes in time, but it's constant. That's what we're told in the problem. And then wait is a force. This's equal to M A. But one a zero means equal to zero. So travelling and constant velocity in outer space, there's just no forces acting on the asteroid, so thank you for listening.

So here. For all of the cases, three weight would be equal to the mass times acceleration due to gravity. Ah, where the acceleration due to gravity would essentially change with each location. So for party, when they want the weight on earth, it would simply be equal to the mass times the gravity on earth. And this is equaling 68 kilograms times 9.80 meters per second squared. This is giving us 670 unions for part B. We want the weight on the moon. This would be equal to the mass times of gravity on the moon. Again, this is gonna be equal to 68 kilograms multiplied by 1.7 meters per second squared. This is giving us 120 in unions. Four parts. See, you have the weight on Mars again. The mass times acceleration due to gravity on Mars six, this would equal 68 kilograms multiplied by 3.7 meters per second squared. Ah, this is giving us 250 Newtons and for party. We want the weight in space in space. The gravity would be zero. So again it would equal the mass times acceleration due to gravity in space. However, this would be 68 kilograms times zero meters per second squared. There's no acceleration due to gravity in space. So this would equal zero Newton's There you would have no weight in space. That is the end of the solution. Thank you for watching.

Here we got what is the weight of a asked, what is the weight of a astronaut? That ways that has a mass of 76 kg. And we asked what is the what is um his weight Her weight um on the moon or on Earth? On the moon? On MARS. And then in space with constant velocity, traveling constant velocity. So the weight is just the mass times the gravitational constant. And depending on where they where this astronaut is, the gravitational constant is different. So on Earth the astronaut weighs 746 newtons. Because GS 9.81 they tell us on the moon, G is 17 So the mass times 17 is 129 newtons. So much much lighter on the on the moon than on Earth on MArs, MArs has a much lower gravitational constant than Earth does because it's it's smaller. Um And so that is the weight on MArs is 281 newtons. So if we ever get an astronaut to MArs, we will way less. And that's again, there was an interesting thing recently about the helicopter that they have that can fly on MArs, although the atmosphere is very thin, so it's hard to get aerodynamic lift forces. Um The nice thing is, is that the weight that that the lift forces have to overcome is um, is significantly less than it would be on Earth. And then finally, in in outer space, when if a traveling at a constant velocity so that the acceleration of the astronaut is zero, then g is zero and the weight or effectively zero, obviously there's gravitational forces from whatever surrounding bodies, but again, those would all be very, very small. Um and so the effect, effectively the weight of a person in in space is just zero and that's why we call it weightless.

So in this problem we know that Ah, astronaut with 600 neuters on the earth And we know that the gravitational constant on the Earth's G is Ah, 10 meters second squid. Right. So we get in turning the mass of the astronaut mess equal 600 noticed Do you like 10? So this gives you 60 kilograms. So the mess that's not depend on where this restaurant is. No matter on the matter in the matter in the on the earth, so are in the moon. So it does not matter. The man says always 60 killed. Where's okay?


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