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Question 61 ptsThe following data represents the ageat which 40 students got married for the first time27 22 28 35Assuming that there are 4 classes,what should the ...

Question

Question 61 ptsThe following data represents the ageat which 40 students got married for the first time27 22 28 35Assuming that there are 4 classes,what should the interval width be?

Question 6 1 pts The following data represents the ageat which 40 students got married for the first time 27 22 28 35 Assuming that there are 4 classes,what should the interval width be?



Answers

Use the following information to answer the next ten questions. The data that follow are the square footage (in 1,000 feet squared) of 28 homes.
$$\begin{array}{|c|c|c|c|c|c|c|}\hline 1.5 & {2.4} & {3.6} & {2.6} & {1.6} & {2.4} & {2.0} \\ \hline 3.5 & {2.5} & {1.8} & {2.4} & {2.5} & {3.5} & {4.0} \\ \hline 2.6 & {1.6} & {2.2} & {1.8} & {3.8} & {2.5} & {1.5} \\\hline {2.8}&{1.8} &{4.5}&{1.9} &{1.9}& {3.1}& {1.6}\\\hline\end{array}$$
$$\text{Table 5.4}$$
The sample mean $=2.50$ and the sample standard deviation $=0.8302.$
The distribution can be written as $X \sim U(1.5,4.5).$
What are the constraints for the values of $x ?$

We have the following data set comprised of 12 numbers starting with 23 ending with 41 picture here. And we want to find the mid quartile of this data set to start. Let's remember that the middle quartile is defined as Q one plus Q three Over to where Q one refers to the value of the first quartile and Q three refers to value at the third quartile. To find the values of Q one and Q three. We need to first put this data set in order from smallest to largest values. So in order we have 22 23 24 32 33 34 36 38 39 40 41 47. Since there's 12 data points, the first quartile is going to fall between the 3rd and 4th data points and the third quartile is going to fall between the ninth and 10th data points. These are picture here, where we get obtain Q one by summing and taking the average of these data points three and 4 24 plus 32/2, 28. And similarly for Q three, we have 39 plus 40 over to 39.5. Now to obtain the mid quartile, we used the above definition and Q one and Q three found here. Doing so. We have 10 mid court tile, 28 plus 39 point 5/2 or 67 point 5/2, or our final solution box here in the bottom right, 33.75

So in number 22 we're looking for the Probability X is less than 3.5. Given X is less than four. So there's two methods the book shows you. I'll be doing the second method in the book. So it's the probability of both things happening. We'll both things happening is really on Lee this part because it would have to be less than 3.5 from this. So we're gonna do the probability then X is less than 3.5 over the probability of the second item, which is X minus four. The probability the X is less then four. So finding this the numerator with a 3.5 minus 1.5 times 1/3 so we want to do from this would be the base 3.5 down to the smallest number conveyed. A. This is the height over. We're gonna do the same thing with the denominator, so that would be four minus 1.5. Once again, times the height, which would be 1/3 with 1/3 would just cancel out. So we do that subtraction, we get to over four minus 1.5 is 2.5 than that probability is 0.8, So the probability of X is less than 3.5. Given X is less than four is pointing.

Problem. 40 forces. The following data showed the lengths off boats moored in the marina that dates are order from smallest to largest. We are also identified the median Here we have 27 observations and we know that the median number between zero and 27 is 14. So if you can't the 14 number in this data constant from 16 and upwards so one to three full 56 seven a nine 10 11 12 13 14 are 14 number is 27. Thus Tony, seven is our median. And to confirm this, we should also get 18 values to the rights of 27 because 27 is our median. It said the left off this Tooni seven also 13 values. Let's just do the constant, though, to confirm so. One, 2345 678 9 10 We live in solve 13 And this confirmed it 27 is really in my median. Thank you

This is the table we must construct before you can complete the question. So we start with the range. The range is the maximum value, minus the minimum value. So I have 12 minus three and that is equal to nine. Let's find the median says there are 40 values the forties coming from the fact that the cumulative frequency is 40. This is their 40 values. The median is the average of the 20th into manifest values. His jab ridge of the 20th and 20 faced values notice, though, so that our table has been arranged from lowest to highest in terms of the hours. So it was some of the food places than the one which contains native fruit. Crazy of 20 and 20 fest will be the hours we are actually looking for. Okay, so when you someday frequencies lady free question of 20 be other poetry of Interval aids and then 20 fest also be on the same point. So both both of these values lie in the interval eight and I mean both the 20th and tree defense values delight in the interval aids. Therefore, the median is eight. Let's find the first quartile or Q. What since the 20 values below the median below the median Q one is the average off the 10th and 11th values is the average of the 10th and 11th values now on the table. Cumulative frequency of 14. Okay, Quinn Tae's the fruit crazy. Now when you some the few cases quality food grace off. 14 contains 10 and they contains 11. Okay, yes, when I someday frequencies community frequency off 14 Quinn taste 10 and 11 and it is at intervals seven. So both of these values lie in the interval. Seven. Therefore, Q one is seven. No, let's find the said quite tile or cure three. Since the 20 values above the median cure three is the average off the 10th and 11th values from the upper end off the distribution, different values do they end off the distribution. This part is the lower end and this up and we're looking for the upper end. Okay, And this part is the upper end because they contain the bigger values. So when I sum up the frequencies here, frequent community for Gracie off 10 will be other prints where I have our 10 that is summing up the fruit praises from the upper end and they're completely free. Gracie of 12 was will be other printer. I have our nine a key, so these values lie in the into a vast 10 and nine. Therefore, cure three is the quarter the mean off 10 and nine, and that is equal to 9.5. So this is our third quite tile. Now let's find our inter quartile range or like you are. And it is basically the difference between the Circle A trial and the first car title, So our inter quite high range is 2.5.


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