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Question 7Select the product of the following reaction: CH, CHzCH CCH 2 HBrCH; Br CH; € CH-CH;CH;CH; CH-CH-CHz-BrCH; BrCH; CH-C-CH,CH;CH; CH-CHz CH-Br...

Question

Question 7Select the product of the following reaction: CH, CHzCH CCH 2 HBrCH; Br CH; € CH-CH;CH;CH; CH-CH-CHz-BrCH; BrCH; CH-C-CH,CH;CH; CH-CHz CH-Br

Question 7 Select the product of the following reaction: CH, CHzCH CCH 2 HBr CH; Br CH; € CH-CH; CH; CH; CH-CH-CHz-Br CH; Br CH; CH-C-CH, CH; CH; CH-CHz CH-Br



Answers

Identify the product in the given reaction. $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}+\mathrm{NOCl} \rightarrow(\mathrm{A})$ (a) $\mathrm{CH}_{3}-\mathrm{CHCl}-\mathrm{CH}_{2} \mathrm{NO}$ (b) (c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHClNO}$ (d) $\mathrm{CH}_{3} \mathrm{NOCH}_{2} \mathrm{CH}_{2} \mathrm{Cl}$

In this problem part time writing the reaction CS three C triple bone. See CH two CH 3 In presence of cl two trans Edison will happen and the product will become C double bond C. Ch two ch t cl cl see http. So according to the option of Sandy it cut it and said for this problem. two according to the option option D. Each correct answer for this problem, I hope you understand the major product of the given reaction.

So we have the following organic compound here. We have our to Bromell octane, and we would like to know what product we're gonna get if we react this organic compound with different nuclear files. So first step here is to draw what that is gonna look like our our to broom octane. So inclined drawing a eight carbon chain. I would like that. And we can draw a promo group in the two position. With the are configuration. This is gonna be denoted by a wedge so we can quickly assigned priorities to make sure that we are in the right configuration. Here s O Brahma Group is a prior to number one. Carbon connected to the long chain is gonna be number two Death. A group is number three in the hydrogen that is facing away from us. It is not shown here. Is gonna be in group priority number four. So we do see that we are in the are figuration here now, what would happen if we reacted this with the nuclear file cyanide? So go ahead and draw. The are to bring walk 10 in the are configuration here. All right, so we do know that cyanide is very good nuclear final very strongly the while, and we have our alcohol allied in the secondary position. So it looks like we're going to proceed. This reaction will proceed via S and two and so are resulting product is gonna look like this. And now this is gonna proceed with inversion of configuration. And so are Sinai Group that comes in is not gonna be coming. Ah, coming, going away from us So it's gonna be known and denoted by dash dash line Yeah, and we see that our Sinai group remains the same priority as are leaving outgoing daylight which ah, in this case is going to be bro mean So we will have ah inversion of absolute configuration as well. And so whereas we had in our figuration here, we will have an s configuration as well. Well, I know we will have an s configuration on our ah, new product. So for being we have an acetate I on. So we go ahead and Joe are are to broom octane and we're gonna go ahead and react it with our asked eight on Since acetate is a very good nuclear file, very strong Akuffo. And again we have our secondary. Ah, after a lot, this will proceed via s and two and our products is gonna look like the following. Looks like we're going to have inversion of configuration. So now we're gonna have a dashed line here and we're gonna go and draw the estate. There we go. And we see then. So this is our on the left side are starting. And then for our product, we are going to have inversion of absolute configuration as well, because our acetate ah has the same priority group as are leaving calcula Hey, light. And so now we're going to be in the S configuration here. So now we have our methane highlight methane highlight. And so we're gonna go ahead and draw. Are are to bring methane. Alright, I'm sorry are to bring walked in. It's gonna be reacting with their methane highlight. You know, that methane highlight is a very strong nickel, fellas. Well and again, what's again? We have our secondary Alcoa. Hey, line. So this is also gonna proceed the, uh s and two reaction and we'll get the following product and we're gonna have a dashed line here with our methane violate, it's gonna look like that. And once again, Ah, Since this group now shares the same priority as are leaving alcohol Allied, which was roaming, it is gonna be we're gonna have an inversion of absolute configuration as well. So on the left side, we're gonna have our configuration. But now we're gonna have inversion of absolute configuration and so on the for our product, we're gonna have s

In this problem, the reaction will happen something like this. Let's look at it carefully. CS three CS 2. I will react with alcoholic A ohh, it to give A which will react with we are to BP and which will react with Casey and to give C. And the product. See here, E and CCH two CH two, NC CH two CH 2 CN two according to the option in this problem, option, age, correct answer for this problem.

In this problem, the reaction will happen. Something like this. Just look at it carefully. G S three CS two CH two, in pageants of & S three. It will give CS three CH two CH to see you manage to and intelligence of we are to any wage. It will give see STD Ch two, Ch 2 and H two. So according to the option in this problem, option age, correct answer for this problem. Option age very cancel for this problem.


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