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Compute the molar work in mol-1 performed by the reaction, 15 C6Ho(g) 02 (g) 6CO2 3HzO(g) 2carried out at KkJmol-1Use the thermodynamic tables...

Question

Compute the molar work in mol-1 performed by the reaction, 15 C6Ho(g) 02 (g) 6CO2 3HzO(g) 2carried out at KkJmol-1Use the thermodynamic tables

Compute the molar work in mol-1 performed by the reaction, 15 C6Ho(g) 02 (g) 6CO2 3HzO(g) 2 carried out at K kJmol-1 Use the thermodynamic tables



Answers

Calculate $K_{P}$ for the following reaction at $25^{\circ} \mathrm{C}$ : $$ \mathrm{H}_{2}(g)+\mathrm{I}_{2}(g) \rightleftarrows 2 \mathrm{HI}(g) \quad \Delta G^{\circ}=2.60 \mathrm{kJ} / \mathrm{mol} $$

This is sort of a big problem, and we're going to start by looking at our reaction. Nitrogen gas reacts with hydrogen gas to produce ammonia and by Delta H for this reaction equals negative 92.6 killer jewels per mole. Okay, that's given. And we are also given that we have 2.0 moles of end to and we have 6.0 bulls of age too. That's what I'm given here. Also, I'm given that I am at 1.0 atmospheres of pressure and 25 degrees seat. Okay, were asked to find, calculate work, find work in jewels. This is one of our unknowns. And second is what is the Delta U. So we have two things to dio. Okay, so what we're going to do on this one is we are our plan. Let me switch colors for a plan here for a plan we're going to use PD equals inner t. And on this one we're going to solve for V, our second order of business will be to use. Ah, work equals that negative p times dealt to be will be finding our work. Um, when we find our work we're also going to be. We've already got our Delta Ages, but we're going to figure out Delta H for the conditions given and then for our delta u will be doing our Let me see here will be doing our, um, work and killer jewels plus our delta h. So that's our plan. Let's start first we said we were going to use, um let's evaluate a problem. We have to 0.0 moles of nitrogen and we have 6.0 moles of hydrogen for a total of 8.0 moles of gas and that 8.0 moles of gas will yield a product 4.0 moles of product. So what we're seeing here is a loss of four moles. We have a loss of four moles of gas. Now we're going to use that into solving for V. P equals nrt is and our T overpay. So let's go ahead and solve this. We've got V equals 4.0 malls and our are will be since we're an atmosphere 0.0 8 to 1 l A t m overcame all our temperature was 25 c, which is to 98 k and our pressure very nicely is one. Do my math here. And my Delta V will be 98 leaders, 98 leaders. And that's 98 leaders. Um, decrease. That's a decrease. So that'll be a negative number because we went from eight, 24 Okay, Now our next order of business is to use. I'm gonna go there next page. We're going to use our work equals negative p times Delta v. So this we're gonna have negative 1.0 atmospheres times a negative 98 leaders. I'm gonna go back. Make sure it was 98. Yep. Negative. 98 leaders. Okay, that will equal 98 leaders. I need to convert that using our conversion factor of 101 101 0.3 Jules per leader. Atmosphere. That's leader atmospheres. Cross cross equals and this will get me, um, 99 100 jewels, which is 9.9 killer jal's. There's my work. Answer. That's the answer for work. Okay, that's simply enough. Now, we also have to find our Delta U. And that's going to be the sum of Delta H and W. So I've got my 9.9 killer jewels right here. That's my X. What's this going to be? Well, if we go back to go back to original problem here, we've got negative 92.6 Killer jolt per mole. And I've got two moles of this. So I've got negative 92.6 killer jewels, and that is for two malls. That's for two moles. But I have four moles because of the numbers that I was given. So I need to double that. So I've got negative one. 85.2. I just did that in my head. Negative. 1 85.2 What's wrong, page? The number that goes right here is going to be 95. Where is that number? 92.6 Negative. 92.6 killed joules per mole. Times two. So it'll be negative. 1 80 5.2. Okay, I'm gonna raise this and x X will equal negative 1 75.3 killer jewels. That's killer JAL's as well. So that's my delta W or dull to you. There's Delta U, and there's work

So far are given a chemical reaction. That is two K two in the solid state generates K 20 and 3/2 2. So we have our Delta G the reaction equation because we want to calculate Gibbs Energy. Remember that oxygen and Standard State we have it's free energy is equal to zero. So why Delta G After we consider the other components, there's 159.9 killed Jules Month. So next we're calculating K so we can use the following equation So the G not is equal to negative r t l N k So we can rearrange for lnk. What we get is negative 64.208 and then we simply just So if okay, that is 1.30 times 10 to the negative 28. So k two is the most dynamically stable with respect to cater. I want to

Heather and so forth. This question. The standard intel P. Change of direct to north. In terms of standard intel piece of the formation is given by this reaction. N. P. Delta H. For product minus and B. H. For reacted. So first here N. P N N R. You can see this is an art. So her N. P. And an R. R. The number of modes of reacting. So delta HF. Standard lee standard and therapy of formation for a compound. The standard entropy change of reaction delta S. In the terms of standard in 12 years of in tall piece of formation is given by this equation that is delta S equals two and be is nord products. My necessarily talk and B. S. So her N. P. N. And R. The number of Mosul product transactions. So standard and help your formation of a compound. So for the gas phase we have been given the reaction that is Ceo plus H. Two. Yes, you too plus H. Two. So we'll have to calculate the values for delta X. Reaction and delta S. Using the equation one and two. Question one. An equation to so we'll get delta H. On equals two 41.2 kg jewels. And the standard and trophy reaction change of reactions will be delta snort. Which is it was to minus 42.1 kg. This whole is the whole calculation you have to do yourself. So now we'll have to calculate the free energy change of reaction delta G. From delta X. And delta is not so delta G. For delta G. It's coming out equals to tell to edge nord minus. So we'll get minus 41 point to kill a jewel minus 2 98 Calvin minus 42.1 42.1. Kill a jewel into one cage. Kill a jewel about 10. They should about three jewel to convert it. So by solving this will get 28.7 kayla. So the relation between the energy change in the Cleveland constant K. P. Is delta G. Nord equals two minus our tv. No in K. P. So we'll have to rearrange the towns to obtain K. P. So K. P. Actually arranging will get G. A bone Rt. So her cape is the global constant. So capable will have to put the values, substitute the values so we'll get 1 to 10 issued the power five. So the key of the reaction is one into 10 days of our five. No the B. Part have to calculate the standard free energy change of reaction. Delta G. From delta X. And delta S. At 4 73 kelvin. So delta G. Again we'll get equals two delta H. Nord when a sti delta s. Not. So we'll get minus 21.3 kg jewels. So the relation between free energy change and equilibrium constant K. P. As we know this delta geek was too minus hearty in K. P. We'll have to rearrange for K. P. So we'll get a peek was to e minister to G upon hearty. This is the equation three. So her cape is the constant and which is 8.314 jewel per mole. So in the gas constant T. So we'll have to substitute the values so we'll get K. P equals two. After substituting and solving the full calculation will get 2.3 to 10 days to the power to so the K. For the reaction is 2.7 to 10 to the power to now for the last part, the standard free energy change that is to G. Can we found out by this formula for products minus delta G. F. For reacted. So this is the equation for so her N. P and R. Are the number of moles of products and reactions so that G. Standard in therapy of formation of a compound. So we'll have to calculate the value for delta G. So for delta gino the value will get after solving will get 28.6 kg. So now we'll have to substitute the values in the expression to calculate K. P. So we'll get Cape equals to one into 10 to the power five. So the key of the reaction is turning into one into 10 inches four or five. And that's your final answer. Thank you.

The problem 17.84. They want me to there's three parts. So the first part they want you to chapters the value of K. P. At 25 degrees associates. And this is the equilibrium you have. And to do this first you have to calculate the delta age and the delta S. Um Using the tabulated thermodynamic values. They give you an appendix cake and then you plug it into this formula you have here. So first defined it does each other reaction, which is the The data age formation of those c. 0. 2 gas plus the data. Each formation of the age to gas uh minus the down to the beach formation of C. O. Gas and the dark age formation of age drug by the way, all these are gases. So so you have this year. Um so we just find these values. So you have one more 02 times maybe 3 90 3.5. 2 tools over more plus one more each to Times zero rules because Yeah this is zero for age to gas uh minus one more. See all time 110 25. I'm just not going to write to you miss from jews. But this is just building more. Oh just one more was -2 41 28 Killer Rules. Woman more. So when you calculate this, you find that the delta H. Is Nearly 41.23 doors over morals. So that's one part of the answer here. And then the second part asked you to come the delta as reaction and the formula for this is basically the same thing as the data age. We just find the products minus the reactant. So um looking up to values mm These will all be changed to that says mhm. So let me have these values from a appendix king that by one times 2 1 3.6 jewels over Moore's that's okay. Plus one tons 130.6. Who put minus one ones 197.6 and plus one tens 188.7. And you find that this because negative 41 .1 sorry 40 -42.1 tools over Calvin. I am. This would be your second part. So you plug in these two values into this form last year. So you get your data G equals Um Dr. H. We we found is -41.2 drugs. And let's say let's just do for this question. Used tools. And so jules, jules since I don't get as it is. And uh jewels. So we convert dr H. We found into jewels which you just multiply by 1000 to 41.2 times 10 to the power three tools -298 Kelvin um times the delicate s which is -42.1 J. Over. So we find that this is Maybe it's 2.87 times 10 to the power for close over more reaction. So this is your delta G. And we are not done here because the question asked you to solve for K. P. So we plug the delta G. We found into our second equation we have here, which is this? So We get the Delta G. With three founders, maybe 2.87 times 10 to the power for tools equals the R. remember to use 8.314. There was a problem because We are working with energy here and 298 caravan about men of Mp. And you just saw this um equation and you get your K. P. Equals 1.1 times 10 to the Power five. So this will be your answer for part A. And for part B. They actually define K. P. At 200 degrees Celsius. Within the same method we used to impart a. So first we want to find a delta G not of this reaction, which is just the to do not equal the delta H minus the T. Down to us. So we have a child We found earlier than we thought to ages maybe 41 from two times 10 to the power of three goes over more. And in this time instead of having a temperature as 25°C We change it to 200°C. So our new temperature would be 473. Tell them And you multiply that by a news 22.1 jules program will taliban and you solve this and you get that you did you not. This Maybe there's two points 13 times 10 to the power of four tools of the malls. So this will be the first part and the next part you want to plug this into the same equation. Use in part A. Here. So you get the delta be not equals negative at pln okay which is I'm just gonna pull you in So negative 3.13 times 10 to the power four equals Our which is 98 .314 times the temperature which is 4 73 times the L. And um Kay P. So when you solve this you get that R. and K. P. is equal to 5.42. And you raise both sides of the power of E. And you get that the K. P. Is um 2.3 times 10 to the power to. So this would be your answer for part B. And finally for part C. We want to find A K. P. Using the values we have for the delta reaction. So the data is your reaction. You find it the same way as you find the doubt of age and the daughter. Yeah at us. So this is basically um and this copy and paste what I did earlier. So you have the products over the reaction. So the data and information of the product minus the data information or the reactions. Yeah. Change all these values. Can you look it up in appendix G. And are going into this equation I get one times negative. three 94.4. Challenge was all the more us one times zero minus is both being reacted one times negative. 1 37.2. And the first one times 90 days To 28.6 mm. You focus in, you find that the reaction mhm negative 2.86 times 10 to the power for tools over morals. Well notice I just went ahead and converted from Philly jewels to jules because the next step when we use this equation of our values in jewel instead of tuning tools. So we just when I use the dual version of that. So The Delta Gina is maybe a 2.86 times 10 to the four jewels equals negative. 81314 jewels Calvin Times the temperature which is 298 Taliban and Karen's L. And K. P. You found that to keep you equals one 11.5. I'm sorry. O. And K. P. Is 11.5. And we raise this power we find that the K. P. Goes long point serial times 10 to the power five which is a good sign since this. And so we found here matches up pretty closely to the answer we found in part A. So these will be here, wow. So it's here


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