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Activity #1: Escherichia coliE. coli culture with OD600 of 1 has about 8x108 CFU/mLCalculating the cell density of the originalovernight culture (tube A). OD600...

Question

Activity #1: Escherichia coliE. coli culture with OD600 of 1 has about 8x108 CFU/mLCalculating the cell density of the originalovernight culture (tube A). OD600 of “B” is 0.018. Total dilution of B 1:10^21mL of culture A diluted into 99 mL of sterile H2O

Activity #1: Escherichia coli E. coli culture with OD600 of 1 has about 8x108 CFU/mL Calculating the cell density of the original overnight culture (tube A). OD600 of “B” is 0.018. Total dilution of B 1:10^2 1mL of culture A diluted into 99 mL of sterile H2O



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Components of $E .$ coli $E .$ coli cells are rod-shaped, about $2 \mu \mathrm{m}$ long and $0.8 \mu \mathrm{m}$ in diameter. The volume of a cylinder is $\pi r^{2} h$, where $h$ is the height of the cylinder. (a) If the average density of $E .$ coli (mostly water) is $1.1 \times 10^{3} \mathrm{g} / \mathrm{L},$ what is the mass of a single cell? (b) $E$. coli has a protective cell envelope $10 \mathrm{nm}$ thick. What percentage of the total volume of the bacterium does the cell envelope occupy? (c) $E$ coli is capable of growing and multiplying rapidly because it contains some 15,000 spherical ribosomes (diameter 18 $\mathrm{nm}$ ), which carry out protein synthesis. What percentage of the cell volume do the ribosomes occupy?

So we have E. Coli bacteria that swims 22 micrometers per second. Ah, exerting a force of 0.57 PICO Newton's peak in PICO Nunes pica Newton's, um, to overcome the resistance. What is the power output? Well, power is work divided by time, which is force times distance divided by time, distance divided by time is the speed or the velocity. So 0.57 paygo Newton's, um comes the velocity, which is 22 micrometers per second, and that is going to give us the power. So PICO is times 10 to the negative 12th power. So times 10 to the negative 12 power. Um, and then we're gonna multiply that by 22. Um, micro, which is times 10 to the negative sixth power. Ah, Mike Micrometers per second. Um, so that's going to give us watts. So let me put that in my calculator. All right. That gives me the answer to A which is 1.3 times 10 to the negative 17 power. What's Okay? So, second part, what's the you know, how much work would it d'oh in traversing the 25 millimeter with of a microscopy microscopes slide all rights. Ah, work equals force times distance. Ah, work equals the force, which is, um, 0.57 PICO Newtons. Um, times the distance, which is 25 millimeters. That's 250.0 to 5 meters. So force times distance. So this is going to be in jewels. So 0.57 times whips 0.57 times 10 to the negative. 12th power times 0.25 Does a set of Mila is, um, 1.4 times 10 to the negative 14 Jules, then So those are our answers.

We have a simple of broth with eco lion, we want to detect the precise number of living sounds. Should we use a counting chamber? Place out an appropriate solution onto the front leg to do a colony camp. See use a spit trip odometer D. Any of these methods or E. None of these methods. Okay. So what we're looking at first of all is which of these methods will work? Which of these methods would be the best. So if we want to do a direct counts we could use A um counting chamber. We can't use direct microscopic count because of the concentration is too low. The state needs 10-7 to look at doing a direct microscopic. And the problem with this for is if we do a direct so direct counts would not be just living cells would include dead cells and we only want can be living. So the best way to give up is to do colonie County. So the answer is B because by waiting them out underneath the *** is the first step to doing a colony count, and that'll give us not the number of all cells, but the number of colony forming units.

In this problem where asked how we would approach counting a sample of E. Coli that was cultured in broth and it lets us know that the concentration is 10 to the 4 to 10 to the sixth cells per mil leader. Our first task here is to exclude any counting methods that don't apply in this situation. So first we check can equally be cultured in the laboratory and the answer is yes. Yeah equally is great for culturing in the laboratory. Next we consider are we trying to count living cells or living and dead cells? And in this case we want to count living cells. So when you want to count living cells for an easily cultured substance like E. Coli, then you're gonna want to use the colony count method. We can also double check to make sure that our concentration is high enough but we should be good. So how do we do a colony camp? Well first we need to take our solution of E. Coli and do a series of sequential delusions. Where we carefully mix a small amount of our sample with water so that we get fewer and fewer bacteria in each test tube. Then we can take these test tubes and smear them on an agar plate and try to culture them. And our goal is to culture a sample that is small enough when we spread it on a nutrient agar so that each individual cell is spread out and can form its own colony. Then we simply count the number of colonies and that tells us how many cells were in that deluded sample. And we can multiply based on our record of the delusion to figure out how many equal I were in the sample in total. To verify that this is the right method and our problem we can examine the other options. They also give us a suggestion of accounting chamber or a spectra Fatima Tower, which uses light to measure the number of bacteria. But the problem with these options is that they will also count dead cells. Because the light is going to pass through dead cells and living cells the same and the counting chamber, it's going to be really hard for the visualization to distinguish between living and dead cells. So because we want to count living cells, only our answer is B.

So hello. Stand nowhere. Don't undressing this question this consideration are bacteria be millions but millimeters upper exercises given by B X. I was just given as 1133 and either power 0.15 x So first, how many bacteria? Over 2.5 hours. So be 2.5. You'll find 1.33 and feet about you don't find 15 in tow. Go find five pars little. So if you calculate this, Miss comes around for 1.9 to the fight Millions. But let me and be upper $8. So be a 1.2. Either our you'll find 15 Hey, on optical. Listen, it's abuse. 4.41 million minutes on See Khomeini are so it'll take 13 billion bacteria to be X equal. Given one point to the three and you'd apology you'll find one x No, but given 31 1.3340 point 15 packs. Now do I weigh 1.3? So 31 by 1.33 Corporate power. Do you find the 15 X thinking in love initial board say on the office. Not here Ellen 31 upon 1.33 equal to 0.15 x in tow. Ellen. So this gives uh Ln 31 minus Ln 1.33 upon. See, this is gives a little one up. 10 point Judo one fight, not Japan. Gero Gero points So genital point one type people do X so x Listen, get executed. Don't be ours.


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