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1. Identify any true statements about the following moleculeCOzHHsOHHsOHCOzHSelect all that are True_ The molecule has at least one diastereomer The molecule is chi...

Question

1. Identify any true statements about the following moleculeCOzHHsOHHsOHCOzHSelect all that are True_ The molecule has at least one diastereomer The molecule is chiral The molecule is optically inactive The molecule is achiral The molecule has an enantiomer The molecule is a meso compound Submit Answer Tries 0/1

1. Identify any true statements about the following molecule COzH Hs OH Hs OH COzH Select all that are True_ The molecule has at least one diastereomer The molecule is chiral The molecule is optically inactive The molecule is achiral The molecule has an enantiomer The molecule is a meso compound Submit Answer Tries 0/1



Answers

Statement -1: Molecules that are not superimpossable on their mirror images are chiral.
Statement -2: All chiral molecules have chiral centres. (a) If both Statement-1 and Statement-2 are correct, and Statement-2 is the correct explanation of the Statement-2. (b) If both Statement-1 and Statement-2 are correct, but Statement $-2$ is not the correct explanation of the Statement-1. (c) If Statement-1 is correct but Statement-2 is incorrect. (d) If Statement-1 is incorrect but Statement-2 is correct.

Heroin. So in this caution there's which of the following molecules are kyra? So up shut people being see and we are correct, correct. The more Lincoln. Okay. Right. Okay. Cht buy it. Yeah. And barons. I am CH three than be. Mhm Yeah. Mhm. I CS three then seeds. Oh yeah. Uh, carol. The ocean A. Mm is Al Qaeda. Since carbon is not attached revenge To four different experience. Different such students. Okay. Thanks a lot.

This problem coverage the chirality of molecules. Now, the first question is asking about a molecule to stereo centers and how many stereo I summers are possible. So mm to find how many stereo I summers are possible. We want to use the formula to end is equal to put stereo extra murders in an is equal to stereo centers. For this first one we'll have to to the to is equal to four for stereo icing as possible. And since this is true false question and its attitude of the two is equal to four stereo as soon as possible. This would be true For the next one. It's asking about a molecule with three stereo centers. So using the above formula, we would do to to the three is equal to eight stereo ice first possible, but the statement says 3 to the two Is equal to nine stereo I summers. This would not be correct because we have to use this above formula to find how many stereo I streamers are possible from the number of stereo centers. So this question would be false because There are eight stereo as much as possible. Not nine. Yeah. Yeah. For the next one it's asking about in an tumors and whether or not they occur in pairs. So whenever you have an anti mirror, like let's do an example here has in O. H. Here and then on a dash you would have a hydrogen and then you could have a miracle. And then let's say you have an amine. So if I want to draw the an and humor of this, I'm going to switch to groups. So in this case I'll make the alcohol on a dash in the hydrogen will be on the wedge and then the method will stay the same. So when I went to draw the in into more for this molecule, I didn't have a lot of options, I could just switch to groups and then I get one and humor. So that means that for every an anti more there's one non super imposible mirror image. So yes, they do occur in pairs. That is true. The next question is asking about two Pantanal in three Pantanal. So let's draw this out. So for two pentagonal we have the alcohol on the to look into for three we have the alcohol three. Now it's asking about the Cairo chirality. So for two Penton, all this would be considered a Cairo center because there is a hydrogen here and this metal is different from this purple group, which is different from this alcohol group. So this is Cairo For this for three pension all there is a mirror image or mirrors imagery in the molecule. So it would not have for different substitutes. This substitute is equal to this substitute. So this would not be considered a Cairo center. So the statement is saying that both two pentagonal and three pence channel our Cairo and showing in timor is um but that would be false to Pentonville shows any terrorism in his Cairo. But three dimensional is not Cairo. The next question is asking about one metal cyclo hexane. Also, let's draw that out your cyclo vaccine. Put the alcohol here On the one located. And the method would also go on the one looking. So it's asking about its chirality. So as we saw up here, this only has three different substitutes because there is a mirror plane in the molecule. So that means that this is not a Cairo center and therefore this is in a Cairo molecule. So since that was what the statement was asking, that would be true, this is a Cairo and does not show any anti terrorism for s It's asking about diets to rumors. Mhm. And it's saying that diet streamers are stereo is numbers that are not mirror images. So die astronomers are typically defined as anything that's not in any humor. So and and and humor is something that has a mirror image that is non super imposible. If a mirror image is super imposible, that means it's an identical molecule. So die streamers are just everything that's left. If we look at an example of to beauty, this is CIS and this is trans these are considered Dia streamers and they're not mirror images of one another. So that's just one example. But this statement is true. Die streamers are service members that are not your images.

We're solving problems. 15 from chapter. We have been asked to select the correct statement among the provided Once let's read through the meaning off each of these statements. Option aces Molecules with formulas ch three c head to toe George and see three exits or two cannot be structuralism. Er's now had their bean. She had three ch two c o h instead of ch three ch teau origin. The statement. This would be correct, but there is ch three ch teau it and 60 ch teau or it on DSI three x six or two cannot be structuralism. Er's this statement as therefore incorrect and weaken. Rule out option A now moving on to the next statement Option B. The molecules must have a single bond to be ableto forms This trans eyes summers whereas we know that molecules must have a double bond single one one make it quite visible for the formation off trans I summers. So they must have a double bond on this. Over this information, we can do not option B and we will move on to Option D first, uh, instead of option, C will understand option d Andre. Toby, uh, it says To be in an Schumer's, a molecule must have at least four different atoms or groups connected to a central carbon. This is correct. Statement on If option D is correct. Options Option C should be false because options he says that there has to be at least three Option. C says that there has to be at least three atoms or groups three different atoms or groups groups connected to the central covers. But as we know that option D is correct and option DCIS there has to be four different groups or atoms that makes D as the right answer.

In this problem, first time drawing the structure here it is. Then Here it is C- three at 7. Here it is C two at 5. Here it is CS three. So the true statement about this structure is it is a Kyron molecule, 88, a tidal molecule. So, according to the option in this problem, only option. Age, correct, answer. Only up Sonny is correct and said, but this problem.


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