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25)Given that for carbon dioxide AHsublimation 15 kJ/mol and ASsublimatior 140 J/mol-K, what can we say about ASuniv for the sublimation of dry ice at 258C? Suniv 7...

Question

25)Given that for carbon dioxide AHsublimation 15 kJ/mol and ASsublimatior 140 J/mol-K, what can we say about ASuniv for the sublimation of dry ice at 258C? Suniv 740 J /mol-K ASuniv +485 J/mol-K ASuniv = -460 J/mol-K ASuniv +190 W/mol-K ASuniv +89.6 J/mol-K

25)Given that for carbon dioxide AHsublimation 15 kJ/mol and ASsublimatior 140 J/mol-K, what can we say about ASuniv for the sublimation of dry ice at 258C? Suniv 740 J /mol-K ASuniv +485 J/mol-K ASuniv = -460 J/mol-K ASuniv +190 W/mol-K ASuniv +89.6 J/mol-K



Answers

If carbon dioxide is cooled at 1 atm, it condenses directly to a solid (dry ice) at $-78.4^{\circ} \mathrm{C}$. The heat of sublimation at this temperature is $\Delta \hat{H}_{\mathrm{sub}}\left(-78.4^{\circ} \mathrm{C}\right)=6030$ cal/mol. (a) Calculate the heat removal rate (kW) required to produce $300 \mathrm{kg} / \mathrm{h}$ of dry ice at 1 atm and $-78.4^{\circ} \mathrm{C}$ if $\mathrm{CO}_{2}(\mathrm{v})$ at $20^{\circ} \mathrm{C}$ is the feed. (b) Suppose the process is carried out at 9.9 atm instead of 1 atm with the same initial and final temperatures. Referring to Figure $6.1-1 b,$ write an expression for the required heat removal rate in terms of heat capacities and latent heats of $\mathrm{CO}_{2}$ in different phases.

So in this question, our first step is we're gonna try and figure out what Delta s not is of celebration. In other words, what you know, in jewels per mole, Calvin Instant. From there, we can multiply the amount moles. We have to get just the Delta s, um, sublimation, which will be in jewels for Calvin. And so to do this step, we're gonna have to use Delta G, not it goes Delta h not minus t dealt ass. Now it's implied that since we have a phase change, Delta G is gonna be zero. And so we have Delta is not equals Team Delta s. We're solving for Delta s So Delta s not equals Delta h not over teeth. And we plug in Delta H. We have 25.2 killed, Jules per moment. We want this in jewels because ass is only given to us and jewels. So, uh, multiplied by 1000. We have shoot 25,200 joules per mole. The temperature is given towards as negative 78 degrees Celsius. We want the same Calvin, so add to 73. So we have all of this. And this could be in Calvin and our adult s is going to come out to I don't That's not specifically, um will come out to, ah, 100 29 0.2 jewels. Permal Calvin. Now we just want to figure out the amount of mostly and multiplied by this delta asked. Not so. We have 129.2 joules per mole. Calvin, the massive co two we have is 84 0.8 grams of CO two. If we divided that by the molecular weight, which is 44 grams per mole watcher happens here. We got that The grams units, cancel out. We have moles here in the numerator of this term, which will cancel out with the moles in the denominator of that term. So if you work through all of that, you're gonna get a final answer That tells us we have 249 jewels per kelvin as our change and enter Pete. Just what you Delta s a sublimation for that specific amount of moles of steel to

So we can calculate the, uh, the entropy change with this sublimation from Delta H over T. And that gives us Ah, I noticed that the temperature is negative. 78 degrees. Uh, centigrade said Celsius. That's 1 95 K on that gives us 320 Jules promote Kelvin. And then, um basically, this question emphasizes that the thermodynamic quantities still Taji dealt H in Delta s are stored geometric, which is to say they're based on the balanced equation that is theater mount for a more. But in this case, we have more than a mole. And so we take the actual amount and converted to moles. And then we multiply by the basically the the Moller entropy, and we get the actual value for the I'm sorry, the Moeller entropy, and we get the actual value for the entropy change in this situation.

So let's figure out how much energy it takes to sublime. Carbon dioxide. Sublimation is the process of taking a solid and going directly to a gas. We don't go through the liquid state and we know that the heat of sublimation is 32.3 Killah jewels per mole. Problem is we don't have molds. We know the number of grams of carbon dioxide that we have. So we're first going to have to convert two moles. We can use molar mass. We know that every mole of carbon dioxide, if we add up a carbon and two oxygen is 44.01 g. So if we stopped there are grams would cancel out. We get moles. But we want the amount of heat. The number of killer jewels. So what we can do is we can take the delta H of sublimation and figure out the heat. We have 32.3. Kill the jewels of energy necessary for everyone more. So our molds will cancel out. We're gonna be left with. Kill the jewels that is heat. And so when we put it into the calculator, we're gonna answer to three significant figures. 36 0.7. Kill a jewels. That's the amount of energy required to sublimate 50 g of carbon dioxide

So we know that a Q is a call to M times l. Now, in a question, we know that the heat off sublimation, or L, is equal to 573 kilo jaw her kilogram or 573 times 10 to the three jewels bear over kilogram. And now you know that I M is 250 grams or 250 times 10 to the minus three kilograms. So now with this information, I can find Q Q is 250 times 10 to the minus. Three times 573 times 10 to the three. And this is a culture to 14. Ah of 140 times 10 to the three Jules.


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