5

13.Select the compounds 'having metal. in zero oxidation state: (2 Points)Ni(CO)4Cr(CO)sFez(CO)=Co(Co)all of the abovenon of the above...

Question

13.Select the compounds 'having metal. in zero oxidation state: (2 Points)Ni(CO)4Cr(CO)sFez(CO)=Co(Co)all of the abovenon of the above

13.Select the compounds 'having metal. in zero oxidation state: (2 Points) Ni(CO)4 Cr(CO)s Fez(CO)= Co(Co) all of the above non of the above



Answers

Assign oxidation states to all of the atoms in each of the following.
$$
\begin{array}{ll}{\text { a. } \mathrm{CrCl}_{3}} & {\text { c. } \mathrm{H}_{2} \mathrm{S}} \\ {\text { b. } \mathrm{Ni}(\mathrm{OH})_{2}} & {\text { d. } \mathrm{CS}_{2}}\end{array}
$$

Sony cheese scenarios. We have a new I honest solid that has a total charge of zero s O. If we're asked to find the oxidation state of the metal. In other words, the charge on it. We're going to need to take the charge of the metal plus all the other things the Liggins and they counter ions. And that has to equal zero. And so I work through it first when we have three and four pluses as our cat I owns. And so we have a plus three charge three times one plus them Charge on the metal and we have six c l minus Liggins. So we have six times negative one So three plus the charge. The metal minus six house equals zero. And so the charge on rhodium here should be three plus new color. So we have the charge of the metal plus the charge of ammonia. Eligon is You feel so Ignore it. Now we have s C and minus leg in here. Has feel sign it. So two of them so and the charge of metal minus to minus one from Brome in the charge on the metal should be three Plus, here we have the charge on the metal athlete's, I mean is a neutral leg. Insulin or it. This counter acts the eso for Tu minus I on the Soffit Island, so M minus two equals zero. The charge on copper is two plus. That's the oxidation state, Um, now sodium is a normally n A plus, and so we have two of them. So plus to charge, plus the charge on the Man Younis That better. Mangini's metal, plus the charge of E d. T. A. Remember E. T. A. Is a accident. A Ligon with a charge of minus four. So two plus in charge of the middle minus 40 c equals zero, so the manatees in the is in the two plus state.

To answer this question or the parts of this question, we need to review our oxidation state rules. One of the rules for oxidation states is if we have an ionic compound and we have a mon atomic ion, the oxidation state is its charge will be using that quite a bit with this problem because there are many of them that are charged. Let's look at H two, S. 04 the first one. There's a rule that states that oxygen is always minus two unless it is a super oxide or a peroxide. But this question begins by specifically stating that none of the oxygen containing compounds are peroxide or super oxides. So we can state that the oxidation state of oxygen is minus two with sulfuric acid. We know that the hydrogen completely dissociates with a plus one charge, so each hydrogen is going to have a plus one oxidation state. Another rule is that the oxidation states for compounds need to sum up to zero. So if we have minus two times four, that's minus eight plus one times two plus two that gives us minus six. So in order to have a zero summed oxidation state than sulfur needs to be plus six. Next we have calcium hydroxide here we have an ionic compound, calcium with a poly atomic ion hydroxide. The charge on calcium is plus two. So that will be its oxidation state. We also have a rule for oxygen that it is always minus two because it's not a super oxide or peroxide, and hydrogen then will be plus one. There's a rule for hydrogen typically being plus one. Unless there's a rule that supersedes it. But if we didn't know whether hydrogen was plus one, we could take the plus two and the minus two times two gives us minus four. So plus to minus four gives us minus two. So each hydrogen needs to be plus one. Next we've got B. R. O. H. There's a rule for oxygen that it will be minus two. There's a rule for hydrogen that it's typically plus one. So to sum to zero, the bro, ming also needs to be plus one and the next one is C. L. N. 02 There's a rule for oxygen that it will be minus two. There are two of them. So that's minus four. There's not a rule for nitrogen but there's typically a rule for religions where they will be a minus one unless they're forced to be something else. Because the rule supersedes it, as in the case up here. But there's no rule superseding uh chlorine having a minus one oxidation state. So we'll put minus one there. That's then going to force nitrogen. If we've got minus two, there are two of them, that's minus four minus one more, that's minus five. So to sum up to zero, nitrogen needs to be plus five. The next one is T I C. L. Four chlorine is typically minus one. There are four of them giving this a total of minus four. So to be have a summed oxidation state of zero. Then the titanium needs to have a plus for oxidation state and for the next one we have sodium. There's a rule for sodium and there's a rule for hydrogen rule for hydrogen says your plus one rule for sodium says you're also plus one. So which rule supersedes which the sodium rule is going to supersede the hydrogen rule. So sodium we'll have a plus one charge giving it a plus one oxidation state, forcing the hydrogen to b minus one. Typically when we combine a hydrogen with a metal, the hydrogen will have a minus one charge and we refer to it as a hydride.

So this question were given a bunch of different Ionic salts coordination complex in them. And we have to figure out what the oxidation state of the metal is right here in this example. And so just remember that we're gonna do is we're going toe have an unknown oxidation state for the metal. Then we're gonna add in all the things that we know and it should equal the total Ah, charge of the metal. And so here, if this 1st 1 in red, we have the metal charge right here the COBOL, any theories and neutral against us, I'm gonna have an effect. The n o to minus Ligon has minus one charge, obviously. And so we have minus three because of that should equal zero because there's no total charge right here. So the metal should be in a three plus state. So we have Cobalt three. Plus, here we have again, the ammonia ligand is neutral, so ignore it. We have the medal charge balancing out with the end of three minus an eye on. So we have m minus one treacle zero because there's no total charge. And so we show silver in the plus one state here we have K plus three of them. So we have a plus three charge over here, plus the metal charge. Plus, remember, we have this Oxlade Ligon to see two of four to minus. So if we have two of them, two to minus is we have minus four, and then we have seal minus two of them. So we have minus two. Should equal zero because there's a no total charge. And so we have three minus four is negative. One minus two is negative. Three. The metal should have a charge of three. So we have chromium three plus. And here for a last one, we have season, which is a plus one charge, it's Ah, climb metal. Um, caesium. Plus normally. So, plus one plus the charge of the metal minus two. Because he all minuses. A leading with a minus one charge. We have two of them. She zero. So the metal charge should be equal to, uh, plus one in order to cancel us out. So we have copper plus

Answer. For part a oxidation state off copper, nitrogen and oxygen are plus two plus five and minus two, respectively. Unser for part B oxidation states off a strong Geum hydrogen and oxygen are plus two plus one and minus two or respectfully and super Parsi oxidation stares off potassium, Colombia and oxygen O R yeah, plus one plus six and minus two. Respect to Lee. Okay, answer for party oxidation stares off sodium hydrogen carbon and oxygen are plus one plus one plus four and minus two, respectively.


Similar Solved Questions

5 answers
Find the partial derivatives with TCFEwith respect I0 and y 10. Find the first and second partial derivalives f(xy)=x'-jry+yJaand _ 0' _
Find the partial derivatives with TCFE with respect I0 and y 10. Find the first and second partial derivalives f(xy)=x'-jry+y Jaand _ 0' _...
5 answers
Differentiate.OA 2x In 9x + x 0 B. x In gx Oc: 9x*? [(2xlIn 9x) ODl 9x*2 (Zx In 9x +x)Y = 9x*?
Differentiate. OA 2x In 9x + x 0 B. x In gx Oc: 9x*? [(2xlIn 9x) ODl 9x*2 (Zx In 9x +x) Y = 9x*?...
5 answers
Use the N chain Ax aind xy, find dzldt;{
Use the N chain Ax aind xy, find dzldt; {...
5 answers
Let $z=x+i y .$ Express the given quantity in terms of $x$ and $y$.$operatorname{Re}left(z^{2}ight)$
Let $z=x+i y .$ Express the given quantity in terms of $x$ and $y$. $operatorname{Re}left(z^{2} ight)$...
5 answers
Simplify.$$12^{-1}$$
Simplify. $$12^{-1}$$...
5 answers
A= 1 -1 2 51
A= 1 -1 2 51...
5 answers
A sample of 38 books by the same autho had mean numde cl pages 0l 324 and_ sarple stardutu dnallan 01 63 poges Find 9590 confidence interval for the average number pages this author' books Explain %ai Ins meensUse the AnanmThe interval303 2923K< # 366 7077Round numbers heredecimal placesThis means that
A sample of 38 books by the same autho had mean numde cl pages 0l 324 and_ sarple stardutu dnallan 01 63 poges Find 9590 confidence interval for the average number pages this author' books Explain %ai Ins meens Use the Ananm The interval 303 2923 K< # 366 7077 Round numbers here decimal plac...
5 answers
Use initial value theorem and final value (heorem to find f(0) and f (c),6 +7s2 + Ss F(s) s(s2 + 45 + 2)
Use initial value theorem and final value (heorem to find f(0) and f (c), 6 +7s2 + Ss F(s) s(s2 + 45 + 2)...
5 answers
A scuba diver achieves neutral buoyancy by adjusting the volume of air in her air vest so that the buoyant force equals her weight. If she then kicks her feet and swims down an additional 20 feet, will the net force now be upward, zero, or downward? Explain.
A scuba diver achieves neutral buoyancy by adjusting the volume of air in her air vest so that the buoyant force equals her weight. If she then kicks her feet and swims down an additional 20 feet, will the net force now be upward, zero, or downward? Explain....
5 answers
04: The frequency distribution below was constructed for the grades ofa group of 30 studentsClass LumitsFreduenc;Drow (requency histogram Wnar the number 5 in the forth 0 155 represents Construct the relazive frequercy disiribution Construc 3 cumubaivcnclative recuenc cistrbution; Drav an ogNCJt 6 19 of 856 wordsFocusMacBook Air
04: The frequency distribution below was constructed for the grades ofa group of 30 students Class Lumits Freduenc; Drow (requency histogram Wnar the number 5 in the forth 0 155 represents Construct the relazive frequercy disiribution Construc 3 cumubaivcnclative recuenc cistrbution; Drav an ogNC Jt...
5 answers
In Problems 27–38, use a calculator to find the value of each expression rounded to two decimal places.$$ an ^{-1} 5$$
In Problems 27–38, use a calculator to find the value of each expression rounded to two decimal places. $$\tan ^{-1} 5$$...
1 answers
Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $x^{3}-64=(x+4)\left(x^{2}+4 x-16\right)$
Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $x^{3}-64=(x+4)\left(x^{2}+4 x-16\right)$...
5 answers
Practice: How many grams of nitric acid, HNO3 and water are found in 5319 of 831 mass percent nitric acid?531g HNOz and 30.0 g H,o8319 HNOz and 16.9 9 H,o44.9 HNO3 and 8.971,09.00 g HNO; and 5319 H,0Show AnswerCneck Answer
Practice: How many grams of nitric acid, HNO3 and water are found in 5319 of 831 mass percent nitric acid? 531g HNOz and 30.0 g H,o 8319 HNOz and 16.9 9 H,o 44.9 HNO3 and 8.971,0 9.00 g HNO; and 5319 H,0 Show Answer Cneck Answer...
4 answers
According t0 survey conducted by OnCampus Research, 27% of college students reported they will work during spring break What is the probability that if you talk to 22 ofyour friends, will be planning to work over spring break? (List the calculator function vou used )
According t0 survey conducted by OnCampus Research, 27% of college students reported they will work during spring break What is the probability that if you talk to 22 ofyour friends, will be planning to work over spring break? (List the calculator function vou used )...
5 answers
Given the linear transformation T Pz - P3 where T(p(t)) = (t2 + l)p" (t) what is the standard matrix representing T using the standard bases {1,t,t2} and {1,t,t2,t3} for Pz and P3, respectively:
Given the linear transformation T Pz - P3 where T(p(t)) = (t2 + l)p" (t) what is the standard matrix representing T using the standard bases {1,t,t2} and {1,t,t2,t3} for Pz and P3, respectively:...
5 answers
QUESTIONA steel wire with length 1.50 m and cross-sectional area 4.00*10-6 m? hangs vertically from rigid support. The Young' modulus for steel 2.0*1011Nlm2. A large metal block with mass 80.0 kg is suspended at rest from the ower end of the wire_ What is the increase in the length of the wire due to the block hanging from it?0.150 cm0.015 cm0.294 cmnone of these answers0.147 cm
QUESTION A steel wire with length 1.50 m and cross-sectional area 4.00*10-6 m? hangs vertically from rigid support. The Young' modulus for steel 2.0*1011Nlm2. A large metal block with mass 80.0 kg is suspended at rest from the ower end of the wire_ What is the increase in the length of the wire...

-- 0.020737--