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Eonadn hmpdneluer Hen Dern GobalInd 444d I0okoCotanel Netru dur 0467mtanhu C meeeend e MTt tentehctIta Goreann Wratn cntnu 0n 4 Eo Noolni7ononk EHane...

Question

Eonadn hmpdneluer Hen Dern GobalInd 444d I0okoCotanel Netru dur 0467mtanhu C meeeend e MTt tentehctIta Goreann Wratn cntnu 0n 4 Eo Noolni7ononk EHane

Eonadn hmpdneluer Hen Dern GobalInd 444d I0oko Cotanel Netru dur 0467 mtanhu C meeeend e MTt tentehctIta Goreann Wratn cntnu 0n 4 Eo Noolni7ononk EHane



Answers

(a) $\mathrm{CH}_{3} \mathrm{NHCH}_{3}$ (b) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NHCH}_{2} \mathrm{CH}_{3}$ (c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NHCH}_{3}$ (d) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}$

In this problem did yet then it happened something like this. CS three CH 2 C 00 quiet In presence of Sierra two. They fast for us at media reaction will take place and product for me. CS three CS SEAL c o H on further reaction with alcoholic a witch. It will give final product ID C. H to the well born c h c cocoa page according to the option Yes. Obscenity is correct answer option B. Each correct answer for this problem.

In this problem, just look at it carefully. BB I too, will react in pageants of BSE here, too. ECU was to give compound Are we change which aid 80 cl here, which it A d c L. Here? So this is white PPT. They said white PPT. Therefore, according to the option option, age, correct and said for this problem, A d c l a will be the white PPT in this problem.

So with this problem, it's important that we would draw a Venn diagram. Um, so were mainly focused on, um thin, fat, red and brown and then male and female. So we have thin, and fat needs to be separate. Entities red and brown need to be separate. However, they can cross over with the thin and fat. Um, and then lastly, we also have, um, the fact that they can be male or female. So if they are male and female, they could cross over sense any of these. And, um, it would have to look like this, so it'll include. Ah, and then our other one would look similar, except it would include everything, including this, so gets a little bit messy. But what we end up seeing is that there are nine fat red roosters. So if we were to plot this on our Venn diagram for part A, we want to determine how many are in the flock. So with this, um, looking at our Venn diagram, we end up seeing that there are 89 total and one way that we could determine this would be, um, in just picking a couple of our criteria and looking. If, for example, we see that there's overlap, we would want all the overlap in the categories such that they are not the same chicken. But we end up seeing that there are 89 total, and then for B. We want to determine, um, how many of them are read. So then, based on that, we would end up getting that there are 32 again. This is once we plot all of our chickens into a specific category, then we want to know how many of them are fat roosters. Um, so that's part C. And in order to do that, we take the number of T prime and intersected with M prime. So it's going to be based on the fact that they are male, Um, and they are not thin. So that's going to look like, um, and that's why it's intersected suddenly end up getting 26 that set then for D. We want to know how many fat hens there, so that's going to be the again, the complement of the thin so the fat ones, because they're either thin or their fat, and then we're going to intersect that with the hens. So that's going to be the complement of the mail, which is the female, and that's gonna end up giving us 30. Then for E. We want to determine the thin and the brown, so it's going to be t intersected with the compliments of the red, which is brown, and that's going to give us 22. And then, lastly, we want to take F, which is the number of fat and red, so not thin complement of thin intersected with are red, and that's gonna give us 21 for our final answer.

In this problem, I can write DDX in it see http CH two C 00 H. This compound in pageants of Cl two A red P. That to be dad reaction. It will give the compound edge, see http C h C L C. O AT and this compound in perchance of alcoholic kO edge. The hydro chlorination happened here and the compound formed the CH two double 1 C h c o egg. Therefore, according to the option of indeed correct option, the is correct answer. I hope you understand the solution.


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