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00The The Which coils The coils of the QUESTION 95 have seven-residue are predominant held following slight pseudo-repeat V not left-handed Kq feature occurs hydrog...

Question

00The The Which coils The coils of the QUESTION 95 have seven-residue are predominant held following slight pseudo-repeat V not left-handed Kq feature occurs hydrogen structure 2 of the resulting 4 bonds V in contact 3.5 between colled residue 8 coils repe 3

0 0 The The Which coils The coils of the QUESTION 95 have seven-residue are predominant held following slight pseudo-repeat V not left-handed Kq feature occurs hydrogen structure 2 of the resulting 4 bonds V in contact 3.5 between colled residue 8 coils repe 3



Answers

Two identical, flat, circular coils of wire each have 100 turns and radius $R=0.500 \mathrm{m}$ . The coils are arranged as a set of Helmholtz coils so that the separation distance between the coils is equal to the radius of the coils (see Fig. $\mathrm{P} 30.58$ ). Each coil carries current $I=10.0$ A. Determine the magnitude of the magnetic field at a point on the common axis of the coils and halfway between them.

Hello, everybody. In this problem, it is given. There are two conducting. Identical. Quite each. Opera. Idiots. Wine. Five meter. Having $100 on both in good, same current off. Can you get it? Bothwell upended. We have to find a magnetic tweet at people. We have to find a magnetic field at people. Pichit, midway between the axis of the two. Quite that is X is given on way. No, I start solving magnetic total magnetic feed at three point Bilby the militant off magnetic feet. Don't go. What The weight. It would be you. Not I are. You square in tow end. Cool Our square plates Exit square to the public. Three right toe from the second. Well, toe it will be you, not I audio square and door Our square pellets exit square to the public three vato on solving it this gun, but it connects. Um, you know, I artist square and go our square polis exit square Could be a perception of the value affects. That is Harper Radius R squared by foot Or do the bubba too late. Now you can take our square moment from the numerator, so this could be the next you not I body square and goingto when we take our square permit our school keep our three. Righto. So it would be Are you on this Can bitterness bunch Lisbon Bayport with the power three wayto on simply by you will get magnetic field Will be. You know, I n no, uh, one plus one by poor people were three by toe, no substitute. You noted for bite and tend to the power off minus seven. Corinthians 10 amputee each while having the $100 Really a 6.5. But by portability, Wine group I get converted it 1.2 pipe, hold the power. Do you wait if we do that calculation this final Underwood week 1.80 in tow tend to the power off my industry. So this is the answer for this problem. Thanks for watching the video

Okay discussion is from the helm holds coil. So there are there is a pair of two identical flat circular coils like this. Okay. And these are the points Okay and these how the radius are? Okay and the distance between these two are also are Okay so there is a midpoint in between these two coils. Okay. And what are what is given? Okay. Each the circular coil of wire. Each 500 tons, so and is given 100 okay. And the radius of 0.5 m. So our is given 0.5. Okay. And the coil are arranged as the set of Helmand's coil. Okay, parallel and with the separation of 0.5 m so they are is again the separation is 0.5 m if each coil carries a current of 10 mps so I is given 10 m pierre so determine the magnitude of the magnetic field at the point on the common axis of the coil and halfway between them. So at this point. Okay, So we can say X will be our by two hair, understand so no problem. We know that the magnitude of the magnetic field can be given by. Okay. Further there is um you note I Squire divided by two X. Square plus R squared. Okay. But there are two players. So it will be multiplied by two and it is only for one turn. But there are uh there are 100 tons. So we will multiply it by and understand. So this will be the formula for hell holes pair. Okay you can also learn this formula. So now we will uh put the values here to first of all to will be cut and because two new not I ari Squire and divided by axes are by two. So it will be oh sorry it's raised to the party but it was also there. Okay. So it will be are required by four plus. Are required. So it will be five. Are inspired by four holders to the power three by to understand. So when we saw it will be new and I ari Squire divided by ari Squire raised to the power three by two. It will be our cube. Okay. And five by four raised to the power three by two. It will be 1.40 understand. So here numerator are square denominator, argue so it will only one are in denominators. Some you note and I divided by 1.40. R will be the magnitude of magnetic field. Okay, so we will be now we will put all values here. First of all. New, not that is four pi multiplied by 10 raised to the power negative seven. It will be Tesla meter par mps. Okay. And any number of times that are 100 multiplied by that is current. That is given 10 ampere divided by 1.40 r. That is radius, it is given. Okay, zero point five me to understand. So when we solve it will be well saul using calculator, it will be 1.80 multiplied by 10 raised to the power negative three Tesla. And this will be the final answer of this question. Thank you.

Considered true molecules. Off are the peptide composed off. Only Ellen in presidents brought the hydrogen bonding in directions that result when these two that parents adopt a barrel Be doubly good sheet sheet. Any meat answered the same cushion for the NT. Parallel. Be doubly. Did she derangement? So here we have to see two molecules off the top of a date that paid for the four. Ominous is composed off only Ellen Ellen in molecules composed of only lending monitoring. So here we have one tap update way we can make it. L mean, enter the gate. So here it should be, Oh, ej group. Well, and here it should be C E O c. Oh, And this should be against age three and that when it is Ellen in our group this Series three this is also seeing three and each. And this one is again Siege three. And and this should be Hide us. This is an terminal. This is city Terminal. This is again Thank you. And this should be seeing three. And this is C. C. And this one is a linseed street. To make it element in our group should be edge otherwise the basic framework agreement. So he had to shoot you. See, t and each on this shoot people it. So these are Children's our tow. Better pay teens on and we have managed temporarily are to make the big Apple good sheet. Uh, we definitely did. She dead? Engagement protections, lan your side by side. Some characteristics are common that we can see here the 1st 1 issue and image borns in Lyon the plane off the sheet. All this you and Anedge borns are lying in the plane of the ships. That second is hydrogen bonding that we have to make and hard is our groups are armies or ended above and below. So this metal group will be aboard the plane. Where is, uh, the C o N h on Argos importing and all other groups? Several minutes saying bling. So for hydrogen bonding, it should be in between Annette and see you off the other team. So it should be this one here are. So it should be region oxygen and hydrogen. Hi. Anderson Off then is to group and CEO off the oxygen should be from the CEO group, Doctor, other team. So that is how the drug trade. Hi. Doesn't boarding this present of And it is a parallel arrangement. So in a way, Bella, redouble. Did she eat this? Dance around in the same direction in the same direction. Border station, sir. Turning from end to see terminal amino. The seas. So this is seated. You know, this is an termina onboard the case. It is running in the same direction. You know what happens in any parallel? Independent? Also, we're taking the same that the page 13 which is made of off I need So here are so everywhere we have to make this, uh, Argosy. It's three, this is and the mineral on our group must be here. So this is See it. Three it. Then again, this should be c etc. This is C. It's three. Oh, and this is a in siege t. So our group is see? It seems when it is the meanest cities Ellen ing. So this is what is people in the ocean and here. See, terminal Hoyt group must present on Dhere managed to group must present and this is a win. See, it's three ej and by that were specifying According to the ocean this turtle of dead, which is made up off only enemy. So everywhere are corruption in the city. Now, this student have a branch inside of level. We have to arrange them in any parallel. We don't look it sheet in and different little bit A printed sheet This dance run in opposite directions. You can see the strange is running in opposite direction. Bunnies from ent o sita mineral in this direction. Other one is from here to here. This is really and hydrogen bonding between the an agency. Oh, gross. Um, still holds that means so whether it is parallel or enter Berlin Hi. I wasn't born ing will remain in the green hydrogen and oxygen hydrogen off the image to Grandpa Front E and, uh, oxygen off the other group of sea cabin. A group of off other t on in between. Her doesn't Morning is former, it is represented by this. So that is how you are making the hydrogen bonding in directions are in case off any parallel. Be deputy in sheet and chance

In this problem were given two concentric but different size loops of current carrying wire and were asked to figure out what the direction and magnitude of the current needs to be in the outer wire in orderto have a zero net magnetic field at the center of both of the wires. So what is this looking like? Well, let's have a small inner wire. Let's make a little bit bigger A smaller inner wire here and ah were not asked to calculate things relative to the inner circle. So let's just pick a random direction for current will pick the direction that's conventionally positive, which is counterclockwise. So we'll have a loop with the current going counterclockwise here. Then we have a nether concentric loop that's bigger around this, and we need to then figure out Mrs Inner Loop current. What is the outer loop current? And then what is the direction? Right? So is it clockwise or counterclockwise? We're not sure. So we need to figure that out such that we want tohave right at the center here. Ultimately a net magnetic field of zero. So how do we figure this out? Well, we need to figure out if we need the outer loop to cancel the outer current loop to cancel the magnetic field from the inner current loop. Well, let's figure out what the magnetic field from the inner current loop would be and what direction it would be given the right direction of magnetic field would be at the center of the inner loop. Given the direction the current, we've defined the inner loop. Okay, so, by definition, a magnetic field from a, uh, just a one loop of wire, actually, any coil circular coil of wire. The man feel the center of that circular coil is given by n the number of loops and that coil times, or you're not times the current through that coil divided by two times are, which is the radius. So how far away we are from the center of the loop to the outside of the loop now four. The inner loop the magnetic field is center of the inner loop is going to be given by the number of turns in the inner loop multiplied by you not multiply the current by the in the inner loop divided by two times the radius of the inner loop Okay, so we have an expression for what the magnetic field would be. Well, what is the magnitude of the magnet field? What is the direction of this magnetic field? We follow the right hand rule. We have used our fingers to curve around the direction of the current, and we have our thumb That's gonna point in the direction of the resulting magnet field. And in this case, that is gonna be out. So the magnetic field from the inner coil of wire is definitely going to be directed outward at the center here. So what is the overall vector of the magnetic field at the center of the inner loop? Well, it's going to have a magnitude of the expression that I have listed here, and it is be going going to be going out of the screen. So we know that we need to cancel out this inner magnetic field by using the magnet UK by the outer, of course, the outer loop in this diagram. So what is the expression gonna be for the outer loop? So let's see what will be right here. What? We need the number of turns theater loop has not. When you know, the current in the outer loop, and then we need to know how big the outer loop is. Right? Okay, so we have the expression for the magnitude. So we know these magnitudes here have to be equal if they're able to add up and cancel each other out. But also, not only do they need to be equal, they needed the opposite in direction. So we have to have the magnetic field from the outer loop being into the screen. And what current direction do we need for that to happen? So if you want the direction of the magnetic field from the outer loop to be into the screen, we can put our thumb pointing down. They got some point it down into the screen and then rotate our fingers around. Follower wrist around and we'll see that the current needs to go, um, in a clockwise direction. So opposite of what we chose in order to cause this particular type of magnet fields so I can get rid of that. Perfect. So that's gonna be the direction that we need to have. The current needs to be going the opposite her in the outer loop needs to be going the opposite direction as the inner loop. Cool, cool, Cool. So we figured out that part of the problem we have to be going into the screen. The magnetic field must be going into the screen and therefore the outer loop current has been going. The opposite direction is the inner loop current. Now we need to figure out what that outer loop current needs to be in order to create such a magnetic field that canceled so that these two magnetic fields created by each of these clips canceled at the center. So that means that the magnitude of these magnetic fields have to be equal. So we're going to say the magnitude of the inner loop magnet field must be equal to the magnitude of the outer loop magnetic field. Let me do that. What do we get? Okay, so we have the number of turns on the inner loop times me not times the current in the inner loop divided by twice the radius of the inner loop and that must be equal to the number of turns in the outer loop multiplied by me not times the current in the outer loop divided by two times the radius of the outer loop. We'll see. We have a few things. Cancel across the city, quality arm units can cancel and our twos can cancel. And then they can solve for the current that we want to find because we know the dimensions of each the loops. And we know the current in the inner coil. So what does this look like? What's rearranged for I out and what we get is a nice low equation with some particular cool ratios. So that current in the outer loop ends up being equal to the ratio of the number of turns of the inner loop to the outer loop, multiplied by the ratio of the raid ei of the outer loop to the inner loop, and then multiply that by the current in the interview. So we plug all this stuff in. We have 140 turns in the interlude 180 turns in the outer loop. We have a radius of 0.23 meters in the outer loop, 0.15 meters in the inner loop, and the interlude has a current of 7.2 amps. So in the end, overall, what is the outer loop Current need to be in order to create a magnetic field center that cancels with the minute field created by the inner loop Will that current ends up being about 8.6 amps? And remember that current needs to be going in the direction opposite to the current in the inner loop in order to create a magnetic field that cancels with the magnetic field from the inner loop. So we have the answer of 8.6 amps for the magnitude and opposite the direction of the interlude current for the direction.


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