Inheritance and in particular flies or dress. Ophelia. And here we have a capital s for a straight wing, a little less for a curved wing. Big are for red eyes, and little are for brown eyes. Okay, so part A just wants us to very simple use these letters to represent the parental gina types. So in the first cross, we're doing too true. Breeding tells us that in the first sense, So that would be true. Beauty means Hamas, I guess, for either the dominant trait or messiahs for the recessive traits, this would be the parent cross. And then, of course, this gives us the standard F one generation that is hetero, I guess. And so that we make a test cross with this generation in another set of true breeding. Recess it. This? Yeah. Okay, so it was just thio construct thes, and l b is we're going thio, um, do our standard Planet Square. So if we have this heros, I guess that could break down into for possible game. It's, um, sort of one of every flavor, hoping this a little tick on the S helps separate the capital. The dominant versus the recess civil lower case. I hate using S s because they look relatively the same big or small. Okay, and then, But the game, it's for the recessive. We only have one option e Technically, it would make for game. It's with the exact same, um, recessive in each. But we don't need to make for columns. And so we'll do our square here and we get a head rose, I guess for both, Then the hello Zegas in one but recessive in the other and then homeless Vegas recessive. Okay, so this would be b and then see is just to sort of say, Well, what, um, are these gene attempts and fuel types, right? So the distribution here is 25% of each for both the geno types and FINA types. A few Typically, though, this first road would be the straight and, uh, straight winged and red eyed. Then we have the straight wing because it has the dominant s. But this time the brown eyes let me get into the courage. Wings were recessive, double recessive for us to the next to both the curved wings. And then we see the dominant I color. So for this third row will be red eyes. And in the last row, recess in both, we will have curved wings and brown eyes. Okay? And that's hopefully get some practice, doing things in the standard way there. But then we get to D, and we want to mix it up a little bit. So these telling us, as it happens, these air on the same chromosome, which means they're linked. So then we do a different cross on. I tend to write my linked crosses a little bit differently. Like to just group them together. So that would mean that our first parent, the very first cross with the true breeding would I'm sorry about the ticks here, Um, would look like this. And so then I group these linked traits like this. So then the only kind of offspring ends up being this linked dominant with a linked recesses set. Of course. This problem then wanted us to cross this with another true breeding recess. If I've perhaps they put a tick on that one where it doesn't belong. So this is the recessive okay? And so But when they're linked, then we only really get two options, right? so because this is the same. No matter which way it goes, we either get a combination with the first pair or with the second pair. So the only offspring here end up being either. How does I guess? In both or Home was, I guess, in both. And so that would mean we would maybe expect without crossover 50% of each and the FINA types would of course be 50% um, straight winged and red eyed for this one. That's headers, I guess. And then, um, curdling and brown eyed for the home side is recessive okay, but E, as they move on, wants us to suppose that 500 flies are produced in a test cross and to apply, uh, math medic math methods to calculate the expected number. So if we look at the map that were given, we can see that the wings the gene different wings occurs at 75.5 map units aan den. The one for eyes occurs up 104.5 map units s The difference here is 29 map units now a recombination frequency. So one map unit is going to be equal to a 0.1 recombination frequency. That means these are having a recombination occur 29% of the time. Okay, so we initially predicted that we would have 50%. Would be this Hera's, I guess in that 50% would be homeless, I guess. Successive. But it's 29% are gonna recall. I recommend it. Then we No, that 71% will be of this kind. Okay, which means that's gonna be 35.5% each. So if we take 500 figure out what 35.5% of that is, that means we'll have approximately. I'm getting 177.5, so you can say 170. Can't may have half a fly more on down 177 of both of these gino types. Mhm. Okay. And so that leaves. 29% will be the other two. They become been, we re accommodated ones. So that's when we have hello zegas in one, but not the other. Or, um, it's also 14 and a half percent each. So if we take 500 multiply that by 14 and a half percent, that means approximately 72 flies. Each would be of the hetero zegas in one and not the other. Okay, if you have these altogether, do surrounding where two flies short. So, um, maybe we could add to thio the dominant where the recombination ones, Um it doesn't really matter, but that concludes this slightly lengthy, multi part problem.