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How UOz(s) One Enter 1 Mi displacement reaction 1 liters V 0f 4.86 I7 the JH HzO() ton V react and 6.02 IV kg Hfor {power plants involves a...

Question

How UOz(s) One Enter 1 Mi displacement reaction 1 liters V 0f 4.86 I7 the JH HzO() ton V react and 6.02 IV kg Hfor {power plants involves a

How UOz(s) One Enter 1 Mi displacement reaction 1 liters V 0f 4.86 I7 the JH HzO() ton V react and 6.02 IV kg Hfor { power plants involves a



Answers

One of the first steps in the enrichment of uranium for use in nuclear power plants involves a displacement reaction between $\mathrm{UO}_{2}$ and aqueous $\mathrm{HF}:$

$$\mathrm{UO}_{2}(s)+\mathrm{HF}(a q) \longrightarrow \mathrm{UF}_{4}(s)+\mathrm{H}_{2} \mathrm{O}(l)[\text { unbalanced }]$$

How many liters of 2.40$M$ $\mathrm{HF}$ will react with 2.15 $\mathrm{kg}$ of $\mathrm{UO}_{2}?$

This guy should be on a power. A typical household, their use this knife if he wants affinity per second on average and unapologetic using deuterium right Using the equation 31 it be which Ah Kee consumes tour duty ruins and the energy release Pull reaction IHS three point to 7 a.m. et notify My steam s off the duty once. You quite about this for year. So the energy quiet. You know you're filter energy. I under 50 times Number of seconds. You know, you're just Tripoli one 56 said about seven this in terms of juice Got a call about this energy perfusion to juice by multiplying by 1.6 times 10 apartments 13 Jewess play movie So it is the amount of energy release Po you should. So the number off deuterium studies required. It s basically two times the number off fusion reactions. Right? Sees each future direction takes up tool duty rounds there for you. Take two times sort energy. Do you have I d and she proficient position. I'm off duty runs and finally you can get What is the mess, miss Too young. Just stick to this one. Played by You told me, miss. Jeez, about ah, tool points. You one que multiply this by the coalition factor for you too. Kilograms. And we should gets about 3.8% old minutes for killer cramps. Oh, approximately is your point. Tree it, Gramps.

850 Jules for a second, 850 Jule per second multiplied by one here into a 3.156 Multiply by 10 to the power seven seconds. The number of seconds in one year into one million Electron worlds one million electron Walt divided by, um 1.601 point six They don't multiply by ah, 10 to the power minus three minus 13. Sorry, it's not treat minus 13 Jule into do divided by, um, 0.23 million electron walks spine to tree 1,000,000 electron walls into Let me do it here a 2.14 2.14 multiplied by 10 to the power minus tree kilograms divided by ah 6.0 to 6.2 Multiply by 10 to the power 20 three And solving this we have, um this is a cool too, um, zero point 35 graham. So this much feel is ah required 0.35 grounds

Way Have a house that has 960 watts of power, and we want to know if determined fuel that would have to be used in a year supply the left help were also given. This weighs in this reaction. I need there the experience, William. Okay. And we have the number of raps and yes, and equals power times time over energy. Okay. And we also have I am AP. And this is minimal. Amount of daiquiri in fuel is people's two kinds in kinds. Massive. Miriam. And you put this in. So we have to over e. Okay, now I'm just gonna plug in. Amazing how? Get to times 960 watt. And you, Bert. This too cool for a second, okay? And he have time of one year, and we're going times just like seconds. So 3.15 36 times on the southern second or yeah, year okay over this thing And we have three points. 27 and be. And we're times Innis by 1.6 Hines head boy, 10 to the negative point area. Date of 22 tools over and me. Okay. And now for the n e d of the massive deuterium. And we have 33.3 five times on. Did they give 27 kilograms? Okay. And now you're here and want to put everything in your calculator. And after you do that, unless before we do that, let's do the signs. You guys do not wait years taken off. We have what's keeping off? Yes, and even taken off. And this becomes we have the tools for a second. So we know with the jewels second here, sucking up here and then we have nose down here. Times this way. Kilograms. And we see how this all cancels out in these kilograms. Your answer should be kilogram. Okay, so after we plug in all that into our calculator should get 0.0 387 690 kilograms. Oh, are you? Get to put this into grams. So this is your feeling. This is OK. Okay,

Hello students. So let one kilowatt hour. In this question, we have given one kilowatt hour is taken as one unit of energy. That is small. You so this is small. You can be written as one molecular by kilo, which is 10. To the power three molecular by our witches equals 236 double zero seconds. Okay so this become in the jewels. So this can be written as 3.6 molecular weight. And to the power five jewel. No, we have to determine the wagon by the force F. Equals to five newton. Newton producing a displacement D. Of one kilometer. That is equal to 10 to the power three m. So the warden W. It is equal to force molecular displacement day. So forces five. Newton displacement asian to the power three m. So this becomes newton meter or june. So this work can be converted into unit. So this is equal to five molecular weight into the power three divided by this, you so 10 3.6 molecular weight into the power five and this you. So from here, after solving work done W This is equal to one by 7 20 times of you. So from the given options option A is the correct answer for this problem. Okay, thank you.


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