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Queation Completion Status;Is the following circuit correclly sotup?R= 1.5 kQThere Is not enough information to answer the question It depends on the power supply (...

Question

Queation Completion Status;Is the following circuit correclly sotup?R= 1.5 kQThere Is not enough information to answer the question It depends on the power supply (battery) Yes

Queation Completion Status; Is the following circuit correclly sotup? R= 1.5 kQ There Is not enough information to answer the question It depends on the power supply (battery) Yes



Answers

Questions $1-3$ refer to the following diagram.
What is the total power dissipated in the circuit when the switch is closed?
(A) 1 $\mathrm{W}$
(B) 4 $\mathrm{W}$
(C) 10 $\mathrm{W}$
(D) 12 $\mathrm{W}$
(E) 16 $\mathrm{W}$

Hi integration problem resistance is having a value of 4.0 kg ohm. Self conductance of the coil is 8.0 micro Henry. And the IMF applied is 20 year old. So first of all we will find it's time constant and that is given as the ratio of self conductance with the resistance. So here it will be 8 to 10 days, 4 -600, Divided by four into tended for three home. So finally here it comes out to be 2.0 in 2 10 days per minus nine seconds. Or we can say this is 210 nanoseconds, no maximum current equally. William current passing through the circuit will be given by noticeable to using homes law ratio of the IMF to the resistance. Instead it will be 20 years old invited by 4000 homes. Hence This I not here comes out to be 0.005 M. P. Here. So using the expression for the current growing through and allow a circuit, then the switch is closed. That equation is I. Is equal to I not bracket one minus zero for minus T by toe where I is any instantaneous value of the current. And that instantaneous current here in this given problem is given us to milli ampere. So here it will be 2.0 into Tended Bar -3 ampere is equal to for this five .005. It may also be written as five into 10 days 4 -3 amperes. So here it is 5-10 for -3 ampere bracket one minus here. S to the power minus T by tao, which is 2.0 nanoseconds. So canceling this standards for -3. Finally we get 1- He reached power minus T by two nano, second is equal to oh by five Doans 0.4. Therefore he reached the bar minus T by two. Nanosecond is equal to 1 -0.4 means this is 0.6. So finally converting this exponential form in to look at it. Make form we get Log off 0.6. Earth based E means natural logarithms. It's going to dynasty by two nanoseconds and dislocated um of 0.6 at the S. E. here. It will come out to be -0.5. Fund. So finally the time in which the current Given up to two million. Pierre his gun is given by one point 02 nanosecond. Multiplying this here. Which is an answer for this given problem. Thank you.

Eventually. How long after the switch is closed? Is the current I going to be equal to 2.0 milli amps? We have that. The resistance is equaling 4.0. Kill Liam's kilo arms. Uh, the induct its would be 8.0 micro Henry's and the IMF is equaling 20 volts. So at this point, we can say that, um, we can use essentially equation 30 41. We know that the eye the current would be equal to the IMF, divided by the resistance multiplied by one minus e to the negative t over the inductive time constant T's of l. And here we know that t sub l is equaling 2.0 nanoseconds. So we can say that we're going to re arrange for tea and tease equaling the inductive time, constant times the natural log of one divided by one minus. I are over e and essentially we just have to solve. So t is going to be equal to two times 10 to the negative ninth seconds times the natural log and this would be one divided by one minus. I would be 2.0 milli amps, so two times 10 to the negative third amps multiplied by our of 4.0 Killy OEMs. So we consist a 4000 arms and then divided by E the IMF of 20 revolts. And we find that the time it takes for the current to reach again 2.0 milli amps is going to be approximately 1.0 times 10 to the negative ninth seconds. This would be our answer for the time taken to reach a current of 2.0 milli amps. That is the end of the solution. Thank you for watching.

So in this problem with the circuit is shown below. So this is our one. We have our two and our three We all know determine the power dissipated by the power of by the by the by the circuit. So first, we need to determine the equivalent of resistance of this circuit. So Ah, our two or three there is nearing serious, right? So that'll be our two plans are free and this is in paranoids are one. So the equivalent the resistance of the circuit is that our what times are two plus are free. Bye bye. Are one plants are two plus or three prey, then the power equal. So this is our e r e Q r equivalents v squared over R U Q. Which gives you the square times are one plus our two, plus our three divide by our one are two plus our three. All right,

This is a given circuit diagram in the kitchen and we are going to find the value of current flowing through the battery. Let's suppose this is current I. And in order to find the current I forced to find the equivalent resistance of the circuit. So we can re draw the circuit as we have a jump this point as a this point B. This point C. So from point A. Three resistors are connected this to six arm. And this tree home. So the equivalent circuit can be region as This is the battery of six world. And from here this point is A. From point if we have connected three resistors, this is of two home and another this is of six home, the six of them and two women, six of them are connected with each other at point B. This is point B. And from point B. We have another resistance of 1.5 to appoint. See let's suppose this is point C. From point A. We have another resistance that is 303 home and this is connected to point c. So this is the equivalent circuit. Now we can see that this too. There's two ohm and the six of them are in parallel. So they're equivalent will be 1.5 home. So 1.5 and 1.5 will be in series. So we can re draw the circuit as this is a tree. Um This is a three home resistor. And here the six women to home equivalent will be 1.5 home and it is connected with other 1.5 home resistor And it is connected with a battery of six world. Now we can find the equivalent resistance of the circuit that will be nothing. But this 1.5 and 1.5 will be three. Now three and three are connected in parallel, so equivalent resistance will be three multiplied three, divide three plus three. That means 1.5. So current flowing through the circuit can be written as we divide our equivalent. That means six divide 1.5. That means four ampere. So in the given options, options, he will be the right answer.


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