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Ie standard enthalpy of formationof H-Ox(g) eeiyoi 2nO--0 doublc bond, 136 kJmol Use this information and the bond cncrgies below; to estimate the bondUecuullastion...

Question

Ie standard enthalpy of formationof H-Ox(g) eeiyoi 2nO--0 doublc bond, 136 kJmol Use this information and the bond cncrgies below; to estimate the bondUecuullastionBond Encreles (kMmol) H-H 436O=H464414360C=6C#c6144421umdlbl 498 [ Jimold6zikmmo51466mold5z8Ltnal

Ie standard enthalpy of formationof H-Ox(g) eeiyoi 2nO--0 doublc bond, 136 kJmol Use this information and the bond cncrgies below; to estimate the bond Uecuullastion Bond Encreles (kMmol) H-H 436 O=H 464 414 360 C=6 C#c 614 4421umdl bl 498 [ Jimol d6zikmmo 51466mol d5z8Ltnal



Answers

From the following data, calculate the average bond enthalpy for the $\mathrm{N}-\mathrm{H}$ bond: $$\begin{aligned} \mathrm{NH}_{3}(g) \longrightarrow \mathrm{NH}_{2}(g)+\mathrm{H}(g) & \Delta H^{\circ}=435 \mathrm{kJ} / \mathrm{mol} \\ \mathrm{NH}_{2}(g) \longrightarrow \mathrm{NH}(g)+\mathrm{H}(g) & \Delta H^{\circ}=381 \mathrm{kJ} / \mathrm{mol} \\ \mathrm{NH}(g) \longrightarrow \mathrm{N}(g)+\mathrm{H}(g) & \Delta H^{\circ}=360 \mathrm{kJ} / \mathrm{mol} \end{aligned}$$

Do find the average bond ndp of the N H. Bond. You will simply add up our three Ansel Peace and divide that by three like we would find a normal average. So our first end will be or 35 kilograms per mole. We also have 3 81 killer jewels, Permal, and we have 3 60 killer jewels. Permal. So to find the average Mike agenda hydrogen bond in therapy, you will have our 4 35 plus 3 81 killer jewels. Permal less 3 60 and divide that tumble by three. You will be left with 3 92 Kill a Jules Permal.

Oh, so today we're going to be calculating. That will be a formation of, ah, chlorine oxide using the bond and trophies of Corinne oxygen, chlorine, chlorine, oxygen and client oxide. So, first we're going to write the reaction that is taking place. So have to chlorine. Their decline is die atomic. It's bonded to each other. We have not a die atomic oxygen, and then we're forming to Klein Oxides. So we're breaking one coin bond court coin coin bond breaking one oxygen oxygen bond informing too cloying oxygen bonds. So this is for two chlorine oxygen's. So this would be to time understood until P information. So it would just be the bonds that are formed, which takes energy and subtracting the energy that is released from the bonds that are formed. Formed so bonds broken, subtracting bonds formed. So we have 246 to 0.7 plus 498 0.7. Then we're subtracting to 206. And so if we do some math and we see that we have 329 0.4. So now, since this is for two molecules of chlor ide ox, chlorine oxide we divide by two. We see that we have 164 0.7 killer jewels. Permal. And since this is a positive quantity, this isn't endo thermic reaction and requires energy.

Hello students in this question we have to calculate the and help of the following reaction. Using the given bond energy. So the and help me change delta H. Is given by bond energy of three of 10 to minus bond energy of the product. So we can right here that in the reactant we have three bond of C. H. Plus one bond of O. H. Plus one bond of C. O. Plus one bond of F. C. L. Okay. And minus three bonds of see edge. Okay. Plus one bond of C. And C. L. Plus two bones of h. and after writing the occupation. Okay. Which is given. So hence we can substitute the values of three manipulated by 414 plus 4 63 plus 3 35 plus 4 31. These are the values for the For the pre a tent and minus of three. multiplied by 414. Yeah. Plus 3 26. Plus humor cleared by 4 63. Okay, so after solving the Delta H. It is obtained as minus 23. Kill a jewel per mode. So it means from the given options option A. It is the correct answer for this problem. Okay. Thank you.

For this problem will be determined the entropy information of corn but outside. And the first thing that you always have to know and determined. And the information is the equation necessary to form it. So it's a form, Corinne one outside. You have to use Corrine and Oxygen and our balances. Who would have to put a to in front of corny monoxide? So this is our equation. And then, if you recall the equation for incomplete information, is the sum, uh, your bonds broken won't supplied by their individual moles. It's attractive by the bonds formed, also once fired by God malls and then you and put the sum of the bond energy. So you're gonna be breaking a reactive bonds. We're gonna break that card and quarrying bond, which have the value of 242.7 killed. Jules Permal. We'll be playing that by one mole to cancel Kemal's, adding that to the value of the oxygen bond, which is 498.7, killing Jewel's Permal once part by the one mall from the equation. And we will be subtracting the value for the corn. But outside, which is 206 killing joules per mole, but required have to multiply this by two moles based on our balanced equation, cancelling out her moles. And this will give us an entropy in formation of 329 playing for cultural.


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