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Your for Toracetic Answer: ichacid pH 4,74 of a buffer Reponyorean 1 with of 0.260 M two acetic eecira plc0s870 sodium acetate? The pKaAnswer...

Question

Your for Toracetic Answer: ichacid pH 4,74 of a buffer Reponyorean 1 with of 0.260 M two acetic eecira plc0s870 sodium acetate? The pKaAnswer

Your for Toracetic Answer: ichacid pH 4,74 of a buffer Reponyorean 1 with of 0.260 M two acetic eecira plc0s870 sodium acetate? The pKa Answer



Answers

Calculate the mass of sodium acetate, $\mathrm{NaCH}_{3} \mathrm{COO},$ you should add to $500 . \mathrm{mL}$ of a $0.150-\mathrm{M}$ solution of acetic acid, $\mathrm{CH}_{3} \mathrm{COOH},$ to buffer a solution at a $\mathrm{pH}$ of 4.57

So before we start just to remind ourselves of the important equation we have, Ph is equal to p k a. Add log of these. So I have had the asset so we can plug in some values. So we have five is equal to 4.76 Add log of soul of acid. Simplify that town of it. I take away 12.7 equal to log So over the acid not went to full log felt over the acid. Let me take the in vast log. I'm not going too far. We get the ratio of salt acid. On the next page we have 1.73 so to acid, so we can write this as follows. Salt equals 1.73 acid. So we take Salter's acts. Acid is why we can solve and have X. But why is not point to Moloch? Text is 1.73 y 2.73 Y is not point to where why is equal to not point not 73 Mullah. So let me go back to X and y is equal to not point to Moloch. We get X ad 9.973 people to 9.2. Mola X is equal to not point to take. We're not point not 73 So X is equal to one, not 0.1 to 7 mola. So not quite 13 model of sodium acetate, and not when not seven mother of acetic acid are to be taken to prepare, not point to Mullah buffer at Ph. Five, it's

In this problem. We are asked to consider a buffer solution that consists of acidic acid and sodium acetate. The concentrations are as follows. 0.10 bowls and 0.13 moles Both in a one 0.0 leaders solution. We have to perform three calculations. I'll do them separately calculation A asked what is the ph of this buffer? This is pretty simple. Let's write our chemical equation. I'm going to abbreviate a city gasol like this should be both ways. I'm going to abbreviate acetate like that. These are all gateway accuse. And I looked up the K. A. Of a city gas. It There's 1.8 times 10 to the -5 from this. We can write our expression as follows again. This stands for the acetate ion and this stands for a city Cassidy to solve for ph we are going to be solving for this value. So he gets this value. Let's rearrange for h plus concentration. I should get myself a little more room there. My hydrogen ion concentration will equal 1.8 times 10 to the -5 times my age. My I should probably use parentheses. The concentration of my acidic acid divided by the concentration of my ass tape, Which will be 1.8 Times 10 to the -5 times my concentration for my Citric acid was 0.10. Leave them all her off out of space and 0.13. Therefore my hydrogen ion concentration Equals 1.38. 5 Time is 10 to the -5 Bowler. And this is the value. I'm going to enter my calculator. But my correct sig figs will be as follows. So when I take my negative log ah 1.385 Times 10 to the -5 Mueller. I will get a ph of 4.86 and that's based on two significant figures there, which allows me to have two decibels. There's problem # one solved problem letter A solved I should say B asked us to consider the same situation except we are also going to add some K O. H. We scroll up here we're going to add. So it's the same solution with 0.02 moles of K. O. H. At it. And what is the ph let me write the same equation and I'm cheating by not writing the whole acetic acid to save us a little time and not writing the whole acetate. And this time let's go ahead and start with our same initial solutions. Going to actually do an initial an ice table here. So I, my initial will be 0.10 moller, 0.02 moller And 0.13 Molar. Because we're adding our hopes, I forgot to add my K. O. H. I'm sorry, I gotta do this over. I forgot I was adding K. O. H. Okay, so let's go to plus my K. O. H. There we go now. And that will give us some acetate oops acetate ion. I'm cheating again. Plus water, which we don't care about and r K plus, which we don't care about. So I don't care about those two. Now. We can fill in our Table 0.10 0.02 and 0.13. Those are all things that were given. Now when we add that potassium hydroxide, that's going to reduce that concentration. So I get zero, it will reduce this by the same amount. Give me an equilibrium concentration is a .08 And this is going to increase by 0.02. Give me 0.0 15. We're gonna have the exact same equation as we had in the last page. Our hydrogen ion concentration will be equal to the K. A. Times. Let's go back. We're going to use this equation right here. So RHAC will be our height acetic acid with 0.08 And her acetate will be 0.15. Do the math on this one and I get 9.60 times 10 To the -6. Now, if you'll check this one out, you'll notice that one of my um operations if you will only has one decimal plate. So this would be equal to one Times 10 to the minus fifth. That means I can have one decimal place in my ph so if we take the negative log and I'm going to check this one, Make sure I've got the right one. I honestly wrote this down a few days ago. I don't remember if I Which one I entered in here. 1.5 times 10. Okay. 1.8. So I'm gonna take my negative blog of it was just six. Okay, it'll be fine. So if I take my negative log of 9.60 Times 10 to the -6 I get A Ph of five. Remember I have one decimal place there So I can go to 5.0 And there's # two. Or let her be Finally, let's go ahead. I never use black. We're gonna have the exact same scenario except this time instead of k O H. We're going to add a gentle three. Also at 0.20 moller I got a zero right there, .020. There we go Moeller. So this time we're going to be adding an acid which means I need my acetate here. Oops, I forgot to do my shortcut there. And uh I better do this on this side then and I'll have my nitrate here and I don't care about that. So I've got initial concentration of 0.13 0.10 and 0.02. So again this will be negative are change will be this and this the equilibrium concentrations will be 0.11 zero and 0.12. And again we'll punch them into the same equation again, we have the acetic acid in the numerator and the acetate in the denominator. This time we get 1.96 times 10 to the -5. And I can report that as 2.0 Because I've got to be the two sig figs. Again. I'm gonna punch this into my calculator to make sure I've got the right number Negative log of 1.96 times 10 To the -5. 4.7. Okay, excellent. So this means I can have two decimal places. I'm going to take the negative log of 1.96. I'm sticking to the -5 And I got 4.71 ph We are done.

All right, So for this question, were given that we have 0.1 mostly leader of acetic acid and 0.25 most cheerleader off sodium acid Tate. The city cast is gonna be our acid. And so the masked he's gonna be your base, the concentrations of them. So we can put this into the Henderson Hospital equation to find the pH of our solution P h is equal to and the PK of ah, acetic acid buffer is 4.76 plus the lock 0.25 over play. One log of 0.25 over 0.1 is equal. 2.398 0.398 post plus 4.76 gives us a pH 5.16

Hello, everyone. My name is Mohammed Ali and this question we had a make sure consisting off, Ascetic said and sodium Essie. When we want to calculate the B H off these, make sure we apply under so massive Elect Equation, which is a B H, equals a B k A. Off the city as it lost law, the concentration off sodium Cassidy divided buys a concentration off ascetic acid. He gave us a value of B itch, which is fine the value of piquet off ascetic acid, which is 4.7 45 Then we can calculate the issue, which first with subtract fine negatives of value off peak A. And so the racial off concentration off sodium acidity buys a concentration off aesthetic assets is equal. Sheftel, which is Tim, bore five negative, 4.74 fine, and he give us a value off ascetic ascend and given which is open to So we Will. Times's by this result so we can calculate the concentration off sodium acid eating that should be existed gives his value be H, which we found. It's equal or 0.36 mourner. But in thes question, he wanted away so we can see the phone. The concentration is equals away divided boys a molecular way off their sodium acid a day times by 1000 by the volume by Millie liter. And this case, we have the concentration which is open in three states and the way we want A and the molecular weight off sodium acetate is 82 and the volume is 500 militar. So by blind in these equation, we can found the weight off sodium s city rewire to gives his value off the edge, which is 15 gram. Thank you.


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