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PositionTimeP Q R $...

Question

PositionTimeP Q R $

Position Time P Q R $



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Use the formula $I=P r t$. Solve for the time, $t$ for (a) $I=\$ 2,376, P=\$ 9,000$ $r=4.4 \%$ (b) in general

In this problem we have the formula interest equals the principal times the rate times time. And were given the following information. And we're looking for The time. So I'm going to start out by making a substitution 600 And $24 for the interest. 6000 For the principal. The rate 5.2. I'm going to write as a decimal .052. And then the time which we are looking for. So the first thing I'm gonna do is I'm going to multiply the 6000 Times The .052, Which is 312. So I get 624. Okay. Equals 312 times t. It's a fight both sides for a 312. Yeah. And I end up with T equals two. Okay. So now if I want to solve for time in general, I would start out with my formula interest equals principal times rate, times time. And then here I can use the division property of equality. And I could see that the time is going to equal interest divided by the principal times the rate

Course. Cinnamon seven beard. Ex elation is equal to B D squared minus. You'd be you. Now we know that Los De is equal to the integration off X elation. This is it called. He'd be you by three minus. You'd be above a full upon for plus constant C and the displacement. A function is given as immigration off the We lost the function. This isn't going to do a being to the power for by well minus you. He to the power five upon. Don't be less See Hey, less see one. These are very quiet functions.

So we have our displacement vector our hat. Ah, this is giving us 9.60 t I had plus 8.85 j hat minus 1.0 t squared K hat. And to find this would be in meters. And to find the velocity vector, this would simply be equal to the derivative of the displacement vector with respect to time. So this would be equal to 9.60 I hat minus 2.0 teeth. Uh, que hat and the units here would be meters per second to find the acceleration vector. This would simply be equal to the derivative of the velocity vector with respect to time. And this would simply be equal to negative 2.0 Que hat. The units here would be meters per seconds squared. That is the end of the solution. Thank you for watching

Hello students. In this question, we have to state the reverberation, reverberation time. Okay. Time. So we can say that it is it is perceived as a time perceived as a time 40 sounds as uh, time for the sound to die. Sound to die. Okay. After the away, after the some source seizes, sound source seizes. Okay, so when the sound sources seizes, this sound starts dying away. Okay? And when this is the sound is dying, then for the time, up to which this is perceived. This is known as reverberation time. Okay. And this depends, yeah, this depends upon the, upon the intensity of the sound. Okay, intensity of the So, okay, so this becomes meaning for the reverberation time. Okay, thank you.


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