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Problem-2 Complete the following equations giving the structure of the major products and any missing reagent: For cach reaction, state what type of reaction is inv...

Question

Problem-2 Complete the following equations giving the structure of the major products and any missing reagent: For cach reaction, state what type of reaction is involved ie dehydration etc. Report stereochemistry where appropriate:OCH CH;SOC FonTCl pidin?POChPBT,OC(CH;h

Problem-2 Complete the following equations giving the structure of the major products and any missing reagent: For cach reaction, state what type of reaction is involved ie dehydration etc. Report stereochemistry where appropriate: OCH CH; SOC Fon TCl pidin? POCh PBT, OC(CH;h



Answers

What is the major product of each of the following reactions? Assume that there is an equivalent amount of each reagent.

This question asked us to drop the major products of each reaction. So for part A, we have two different Al keens in this molecule to choose from this one on the end. Here. This is the terminal keen and this internal one right here and we're going to react with the internal one because that will give us a more stable carbon cattle and intermediate. So the first step that will happen is the l Keen will come and grab his hydrogen and kick the burning off of it. So we'll get an intermediate. Ah, a car broke out on intermediate That looks like this So this carbon will get the hydrogen and this one will be our carbo Catalan because a tertiary carbo cat lion this carbon is going more stable than a secondary one, which is what this carbon would be. So there's our carbon cattle and intermediate. And then the next step is for this bro me new plea for a come in and talk. The car broke a tie in. So that will give us, um a product that looks like this. These are three. Okay, so there's our product for part A for part B here we have an Al Qaeda on one end and now keen on the other. And we know from the previous few chapters here that Al Keane's are more reactive than all kinds. So we're going to react with the l keen. Um, And when we react, a double bond with an l keen, Um, we get chlorine on each of those carbons that will look like this. So we get a chlorine on each carbon opposite each other. So it's her product for part B. And then for part C. Here we have this seven member ring, um, and again, hoops such be three again with, um to Al Kean's on it and that we have to decide which one is going to be our the one that we're reacting with. And so we know that this one has this tertiary position on it because of this metal group. So this is where we're going to want our carpal cat I, and to be so will react with the Selkie. So this will grab our age. Um, and then and then that will be our carbo cat. I am right here. And this carbon right here will get the hydrogen, and we still have this Elke left over, and then we just have to attack with our chlorine molecule to get our products. Um, which looks like this.

Okay, so you get the products with falling reactions. In the first one, we have purple dark acid with ammonia and just don't heat. Okay, so the car bostock acid has a lower P. K. The pneumonia, it's gonna behave the worst acid. And ammonia is then going to. Do you need a pair of electrons to form bomb the hydrogen of permanent acid? And this is really the only hydrogen can grab. You can't get any from over here the lecture and go back to the oxygen and be as much negative. So we need the structure, I'm guessing NH four as well. So, in the presence of heat and around 200 yourself, 200 degrees Celsius, we're actually gonna get a carbonic acid. I mean, he um didn't came out. So if we drop the oxygen and just add this NH two group, we have a loss of water as well. See too hard regions from um and H four than the auction from the Canada based permanent acid X one. Is this imode with water and heat. Do you have a four carbon Ahmad. So we can t minus C. O N H R C O. N. Function group that she could be attached to to hide regions or some are groups. But um the mean is more basic than water. It's going to impersonate water really. A NH three. What is a weak base. So it's got the bigger but we're also going to get hydroxide too strong base. And what's that? A curse going to attack the carbonell carbon. And once we get the cox that I on, it's got to reform the double bond the oxygen to expel ammonia because again, it's a weak base. It's good leaving group. So the addition of so each group that and will Catalonia, this is side products. X one is a before carbon Esther with sitting hydroxide heat. Okay, so city metro oxide is a strong base. It's going to attack the carbon or carbon directly with their cocks an eye on and it's going to reform to expel the um the proceeds through the proceeds through your burger addition of a witch and then a fox side. I am Okay so the methotrexate on stronger base than permanent acid as a result is going to grabbed parents on from permanent acid and we're gonna get the structure. So the negative charge the oxygen is going to pair it with the stadium from sitting my drug side and the salt. So we're gonna get methanol side products one smith oxide departments the hydrogen of permanent acid.

In this problem, the reaction will occur something like this. Just look at it carefully here to teach ohh this in presence of BCC in dried CH two cl 2 will give the product package this compound. We will give the product dead this compound. So according to the option in this problem, option B. H. Correct answer for this problem.

Students welcome back and this question I'm given by the structures of the product of the following direction. Okay so we are given three reaction and we have provided the products. So first reaction is CH three ch double one CH two. And this is reacted with it too in the presence of edge place and the aesthetic. Okay so first of all this is property. Okay, so when we react this with water so it will undergo hydro assist. So the platform will be CH three ch CH three and this oil will attach here because it is more Stephen and hedge will attach here. Okay, now second reaction in this, we have given this compound. Okay, this compound, the name of this compound is metal to absorb uh cycle anxiety. Okay so this is the compound and this is separate with any bh course and the beach prison reducing it. So it will reduce this compound. So it will reduce what it will uh sorry there. Ohh okay so it will reduce what it will reduce this button group to alcohol. Okay, so this will convert this material to societal anxiety to two. Hydroxy society anxiety. Okay, so the product will be something like this. This part will remain thing. Okay because it it isn't you know another compound words Northern Kiddo and only this you changed. Okay, so this is material to society and exactly the solution material two. Hydroxy cycle, exact. Okay, next it's this compound CH three Ch door see it financial and CH three. Okay and this is reacted with maybe H four and this is reduced. So if you saw the CH all over here and if you reduce this compound, uh, this L. D. I. Will become a trip to L. A. Tomorrow. Okay. So this will become matter to CH three CH two ch polyester. Which Okay. And CHD over here. So this is to material, you know, form a tight you take nice and this will be converted to storm a tile beauty one old. Okay, So this is a big answer. Thank you.


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